How to convert integers to characters in C

Question

For example  if the integer was 97  the character would be  a   or 98 to  b

User · Answer

char c1    char 97     c1    a   int i   98  char c2    char i     c2    b

User · Answer

Casting the integer to a char will do what you want   char theChar      int theInt   97  theChar  char  theInt   cout lt  lt theChar lt  lt endl    There is no difference between  a  and 97 besides the way you interperet them

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In C  int  char  long  etc  are all integers   They typically have different memory sizes and thus different ranges as in INT MIN to INT MAX   char and arrays of char are often used to store characters and strings   Integers are stored in many types  int being the most popular for a balance of speed  size and range   ASCII is by far the most popular character encoding  but others exist   The ASCII code for an  A  is 65   a  is 97    n  is 10  etc   ASCII data is most often stored in a char variable   If the C environment is using ASCII encoding  the following all store the same value into the integer variable   int i1    a   int i2   97  char c1    a   char c2   97    To convert an int to a char  simple assign   int i3    b   int i4   i3  char c3  char c4  c3   i3     To avoid a potential compiler warning  use a cast  char   c4    char  i4     This warning comes up because int typically has a greater range than char and so some loss-of-information may occur   By using the cast  char   the potential loss of info is explicitly directed   To print the value of an integer   printf   lt  c gt  n   c3      prints  lt b gt      Printing a  char  as an integer is less common but do-able printf   lt  d gt  n   c3      prints  lt 98 gt      Printing an  int  as a character is less common but do-able     The value is converted to an  unsigned char  and then printed  printf   lt  c gt  n   i3      prints  lt b gt   printf   lt  d gt  n   i3      prints  lt 98 gt    There are additional issues about printing such as using  hhu or casting when printing an unsigned char  but leave that for later   There is a lot to printf

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void main           int temp integer count 0 i cnd 0      char ascii 10   0       printf  enter a number        scanf   d   amp integer        if integer gt  gt 31                CONVERTING 2 s complement value to normal value            integer  integer 1           for temp integer temp  0 temp  10 count              ascii 0  0x2D       count         cnd 1              else      for temp integer temp  0 temp  10 count              for i count-1 temp integer i gt  cnd i--                  ascii i   temp 10  0x30          temp  10             printf   n count   d ascii  s   count ascii

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Program Converts ASCII to Alphabet   include lt stdio h gt   void main         int num    printf        This Program Converts ASCII to Alphabet       n      printf   Enter ASCII        scanf    d    amp num     printf   d is ASCII value of   c    num   char num        Program Converts Alphabet to ASCII code   include lt stdio h gt   void main         char alphabet    printf        This Program Converts Alphabet to ASCII code       n      printf   Enter Alphabet        scanf    c    amp alphabet     printf  ASCII value of   c  is  d   alphabet   char alphabet

[c] How to convert integers to characters in C?

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