How do relative file paths work in Eclipse

Question

So my 2009 new years resolution is to learn Java   I recently acquired  Java for Dummies  and have been following along with the demo code in the book by re-writing it using Eclipse   Anyway  every example in the book that uses a relative path does not seem to read the  txt file it s supposed to read from   Here is the sample code   import java util Scanner  import java io File  import java io IOException  import javax swing JFrame  import javax swing JLabel  import java awt GridLayout   class TeamFrame extends JFrame        public TeamFrame   throws IOException           PlayerPlus player          Scanner myScanner   new Scanner new File  Hankees txt              for  int num   1  num  lt   9  num                  player   new PlayerPlus myScanner nextLine    myScanner nextDouble                 myScanner nextLine                addPlayerInfo player                            add new JLabel             add new JLabel     ------             add new JLabel  Team Batting Aberage              add new JLabel PlayerPlus findTeamAverageString              setTitle  The Hankees            setLayout new GridLayout 11 2            setDefaultCloseOperation EXIT ON CLOSE           pack            setVisible true              void addPlayerInfo PlayerPlus player            add new JLabel player getName              add new JLabel player getAverageString                And you can see in the below screen shot I have included this file   image no longer available  Also  I have verified that when I build the application that a copy of Hankees txt is placed in the bin folder with the compiled  class files   Lastly  if I change line 12 to the following and place Hankees txt in the root of my C   drive the program compiles and runs fine   Scanner myScanner   new Scanner new File  C   Hankees txt       So basically  my question is what am I doing wrong   Or is Eclipse responsible for this in some way   Thanks for any and all help

User · Answer

This is really similar to another question. How should I load files into my Java application?

How should I load my files into my Java Application?

You do not want to load your files in by:

C:\your\project\file.txt

this is bad!

You should use getResourceAsStream.

InputStream inputStream = YourClass.class.getResourceAsStream(“file.txt”);

And also you should use File.separator; which is the system-dependent name-separator character, represented as a string for convenience.

User · Answer

This is really similar to another question. How should I load files into my Java application?

How should I load my files into my Java Application?

You do not want to load your files in by:

C:\your\project\file.txt

this is bad!

You should use getResourceAsStream.

InputStream inputStream = YourClass.class.getResourceAsStream(“file.txt”);

And also you should use File.separator; which is the system-dependent name-separator character, represented as a string for convenience.

User · Answer

Yeah  eclipse sees the top directory as the working root directory  for the purposes of paths      just thought I d add some extra info  I m new here  I d like to help

User · Answer

Paraphrasing from http   java sun com javase 6 docs api java io File html   The classes under java io resolve relative pathnames against the current user directory  which is typically the directory in which the virtual machine was started   Eclipse sets the working directory to the top-level project folder

User · Answer

You can always get your runtime path by using    String path   new File      getCanonicalPath      This provides valuable information about where to put files and resources

User · Answer

This is really similar to another question. How should I load files into my Java application?

How should I load my files into my Java Application?

You do not want to load your files in by:

C:\your\project\file.txt

this is bad!

You should use getResourceAsStream.

InputStream inputStream = YourClass.class.getResourceAsStream(“file.txt”);

And also you should use File.separator; which is the system-dependent name-separator character, represented as a string for convenience.

User · Answer

A project s build path defines which resources from your source folders are copied to your output folders  Usually this is set to Include all files   New run configurations default to using the project directory for the working directory  though this can also be changed   This code shows the difference between the working directory  and the location of where the class was loaded from   public class TellMeMyWorkingDirectory       public static void main String   args            System out println new java io File     getAbsolutePath             System out println TellMeMyWorkingDirectory class getClassLoader   getResource     getPath               The output is likely to be something like   C  your project directory  C  your project directory bin

User · Answer

Yeah  eclipse sees the top directory as the working root directory  for the purposes of paths      just thought I d add some extra info  I m new here  I d like to help

User · Answer

You need  src Hankees txt   Your file is in the source folder which is not counted as the working directory    Or you can move the file up to the root directory of your project and just use  Hankees txt

User · Answer

Yeah  eclipse sees the top directory as the working root directory  for the purposes of paths      just thought I d add some extra info  I m new here  I d like to help

User · Answer

A project s build path defines which resources from your source folders are copied to your output folders  Usually this is set to Include all files   New run configurations default to using the project directory for the working directory  though this can also be changed   This code shows the difference between the working directory  and the location of where the class was loaded from   public class TellMeMyWorkingDirectory       public static void main String   args            System out println new java io File     getAbsolutePath             System out println TellMeMyWorkingDirectory class getClassLoader   getResource     getPath               The output is likely to be something like   C  your project directory  C  your project directory bin

User · Answer

Paraphrasing from http   java sun com javase 6 docs api java io File html   The classes under java io resolve relative pathnames against the current user directory  which is typically the directory in which the virtual machine was started   Eclipse sets the working directory to the top-level project folder

User · Answer

You need  src Hankees txt   Your file is in the source folder which is not counted as the working directory    Or you can move the file up to the root directory of your project and just use  Hankees txt

User · Answer

You can always get your runtime path by using    String path   new File      getCanonicalPath      This provides valuable information about where to put files and resources

User · Answer

A project s build path defines which resources from your source folders are copied to your output folders  Usually this is set to Include all files   New run configurations default to using the project directory for the working directory  though this can also be changed   This code shows the difference between the working directory  and the location of where the class was loaded from   public class TellMeMyWorkingDirectory       public static void main String   args            System out println new java io File     getAbsolutePath             System out println TellMeMyWorkingDirectory class getClassLoader   getResource     getPath               The output is likely to be something like   C  your project directory  C  your project directory bin

User · Answer

A project s build path defines which resources from your source folders are copied to your output folders  Usually this is set to Include all files   New run configurations default to using the project directory for the working directory  though this can also be changed   This code shows the difference between the working directory  and the location of where the class was loaded from   public class TellMeMyWorkingDirectory       public static void main String   args            System out println new java io File     getAbsolutePath             System out println TellMeMyWorkingDirectory class getClassLoader   getResource     getPath               The output is likely to be something like   C  your project directory  C  your project directory bin

User · Answer

You need  src Hankees txt   Your file is in the source folder which is not counted as the working directory    Or you can move the file up to the root directory of your project and just use  Hankees txt

User · Answer

Yeah  eclipse sees the top directory as the working root directory  for the purposes of paths      just thought I d add some extra info  I m new here  I d like to help

User · Answer

Paraphrasing from http   java sun com javase 6 docs api java io File html   The classes under java io resolve relative pathnames against the current user directory  which is typically the directory in which the virtual machine was started   Eclipse sets the working directory to the top-level project folder

User · Answer

You need  src Hankees txt   Your file is in the source folder which is not counted as the working directory    Or you can move the file up to the root directory of your project and just use  Hankees txt

User · Answer

Paraphrasing from http   java sun com javase 6 docs api java io File html   The classes under java io resolve relative pathnames against the current user directory  which is typically the directory in which the virtual machine was started   Eclipse sets the working directory to the top-level project folder

User · Answer

This is really similar to another question. How should I load files into my Java application?

How should I load my files into my Java Application?

You do not want to load your files in by:

C:\your\project\file.txt

this is bad!

You should use getResourceAsStream.

InputStream inputStream = YourClass.class.getResourceAsStream(“file.txt”);

And also you should use File.separator; which is the system-dependent name-separator character, represented as a string for convenience.

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