How to define a relative path in java

Question

Here is the structure of my project      I need to read config properties inside MyClass java  I tried to do so with a relative path as follows       Code called from MyClass java File f1   new File              config properties      String path   f1 getPath     prop load new FileInputStream path      This gives me the following error             config properties  The system cannot find the file specified    How can I define a relative path in Java  I m using jdk 1 6 and working on windows

User · Answer

File f1   new File              config properties        this path trying to access  file is in Project directory then just access  file like this   File f new File  filename txt      if your file is in OtherSources Resources  this getClass   getClassLoader   getResource  relative path     - gt  relative path from resources folder

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public static void main String   args            Properties prop   new Properties            InputStream input   null          try               File f new File  config properties                input   new FileInputStream f getPath                 prop load input               System out println prop getProperty  name               catch  IOException ex                ex printStackTrace              finally               if  input    null                    try                       input close                      catch  IOException e                        e printStackTrace                                                       You can also use Path path1  FileSystems getDefault   getPath System getProperty  user home     downloads    somefile txt

User · Answer

It s worth mentioning that in some cases   File myFolder   new File  directory       doesn t point to the root elements  For example when you place your application on C  drive  C  myApp jar  then myFolder points to  windows   C  Users USERNAME directory   instead of  C  Directory

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I was having issues attaching screenshots to ExtentReports using a relative path to my image file  My current directory when executing is  C  Eclipse 64-bit eclipse workspace SeleniumPractic   Under this  I created the folder ExtentReports for both the report html and the image png screenshot as below   private String className   getClass   getName    private String outputFolder    ExtentReports     private String outputFile   className      html   ExtentReports report  ExtentTest test    BeforeMethod         initialise report variables     report   new ExtentReports outputFolder   outputFile       test   report startTest className          more setup code   Test        test method code with log statements   AfterMethod        takeScreenShot returns the relative path and filename for the image     String imgFilename   GenericMethods takeScreenShot driver outputFolder       String imagePath   test addScreenCapture imgFilename       test log LogStatus FAIL   Added image to report   imagePath     This creates the report and image in the ExtentReports folder  but when the report is opened and the  blank  image inspected  hovering over the image src shows  Could not load the image  src    ExtentReports QXKmoVZMW7 png    This is solved by prefixing the relative path and filename for the image with the System Property  user dir   So this works perfectly and the image appears in the html report   Chris  String imgFilename   GenericMethods takeScreenShot driver System getProperty  user dir            outputFolder   String imagePath   test addScreenCapture imgFilename   test log LogStatus FAIL   Added image to report   imagePath

User · Answer

Firstly  see the different between absolute path and relative path here   An absolute path always contains the root element and the complete directory list required to locate the file   Alternatively  a relative path needs to be combined with another path in order to access a file   In constructor File String pathname   Javadoc s File class said that      A pathname  whether abstract or in string form  may be either absolute or relative    If you want to get relative path  you must be define the path from the current working directory to file or directory Try to use system properties to get this As the pictures that you drew    String localDir   System getProperty  user dir    File file   new File localDir      config properties      Moreover  you should try to avoid using similar                   and other similar relative to the file location relative path  because when files are moved  it is harder to handle

User · Answer

Try something like this  String filePath   new File     getAbsolutePath    filePath concat  path to the property file      So your new file points to the path where it is created  usually your project home folder    EDIT   As  cmc said       String basePath   new File     getAbsolutePath        System out println basePath        String path   new File  src main resources conf properties                                                               getAbsolutePath        System out println path     Both give the same value

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Example for Spring Boot  My WSDL-file is in Resources in  wsdl  folder  The path to the WSDL-file is      resources wsdl WebServiceFile wsdl   To get the path from some method to this file you can do the following   String pathToWsdl   this getClass   getClassLoader                        getResource  wsdl  WebServiceFile wsdl   toString

[java] How to define a relative path in java

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