[jquery] How to reset radiobuttons in jQuery so that none is checked

I have radio buttons in HTML like this:

<td>
    <input id="radio1" type="radio" name="correctAnswer" value="1">1</input>
    <input id="radio2" type="radio" name="correctAnswer" value="2">2</input>
    <input id="radio3" type="radio" name="correctAnswer" value="3">3</input>
    <input id="radio4" type="radio" name="correctAnswer" value="4">4</input>
</td>

This is in a form tag, and when user submits a form I want to make all the radio buttons back to the default. Meaning none of them checked.

I have this code but it gives an error saying [0] is null or not an object

$('input[@name="correctAnswer"]')[0].checked = false;
$('input[@name="correctAnswer"]')[1].checked = false;
$('input[@name="correctAnswer"]')[2].checked = false;
$('input[@name="correctAnswer"]')[3].checked = false;

I am doing this in IE 6.

This question is related to jquery forms

The answer is


I know this is old and that this is a little off topic, but supposing you wanted to uncheck only specific radio buttons in a collection:

_x000D_
_x000D_
$("#go").click(function(){_x000D_
    $("input[name='correctAnswer']").each(function(){_x000D_
      if($(this).val() !== "1"){_x000D_
        $(this).prop("checked",false);_x000D_
      }_x000D_
    });_x000D_
  });
_x000D_
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>_x000D_
<input id="radio1" type="radio" name="correctAnswer" value="1">1</input>_x000D_
<input id="radio2" type="radio" name="correctAnswer" value="2">2</input>_x000D_
<input id="radio3" type="radio" name="correctAnswer" value="3">3</input>_x000D_
<input id="radio4" type="radio" name="correctAnswer" value="4">4</input>_x000D_
<input type="button" id="go" value="go">
_x000D_
_x000D_
_x000D_

And if you are dealing with a radiobutton list, you can use the :checked selector to get just the one you want.

$("#go").click(function(){
  $("input[name='correctAnswer']:checked").prop("checked",false);
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<input id="radio1" type="radio" name="correctAnswer" value="1">1</input>
<input id="radio2" type="radio" name="correctAnswer" value="2">2</input>
<input id="radio3" type="radio" name="correctAnswer" value="3">3</input>
<input id="radio4" type="radio" name="correctAnswer" value="4">4</input>
<input type="button" id="go" value="go">

Why don't you do:

$("#radio1, #radio2, #radio3, #radio4").checked = false;

Where you have: <input type="radio" name="enddate" value="1" />

After value= "1" you can also just add unchecked =" false" />

The line will then be:

<input type="radio" name="enddate" value="1" unchecked =" false" />

Your problem is that the attribute selector doesn't start with a @.

Try this:

$('input[name="correctAnswer"]').attr('checked', false);

Radio button set checked through jquery:

<div id="somediv" >
 <input type="radio" name="enddate" value="1"  />
 <input type="radio" name="enddate" value="2"  />
 <input type="radio" name="enddate" value="3"  />
</div>

jquery code:

$('div#somediv input:radio:nth(0)').attr("checked","checked");

Finally after a lot of tests, I think the most convenient and efficient way to preset is:

var presetValue = "black";
$("input[name=correctAnswer]").filter("[value=" + presetValue + "]").prop("checked",true);
$("input[name=correctAnswer]").button( "refresh" );//JQuery UI only

The refresh is required with the JQueryUI object.

Retrieving the value is easy :

alert($('input[name=correctAnswer]:checked').val())

Tested with JQuery 1.6.1, JQuery UI 1.8.


The best way to set radiobuttons state in jquery:

HTML:

<input type="radio" name="color" value="orange" /> Orange 
<input type="radio" name="color" value="pink" /> Pink 
<input type="radio" name="color" value="black" /> Black
<input type="radio" name="color" value="pinkish purple" /> Pinkish Purple

Jquery (1.4+) code to pre-select one button :

var presetValue = "black";
$("[name=color]").filter("[value='"+presetValue+"']").attr("checked","checked");

In Jquery 1.6+ code the .prop() method is preferred :

var presetValue = "black";
$("[name=color]").filter("[value='"+presetValue+"']").prop("checked",true);

To unselect the buttons :

$("[name=color]").removeAttr("checked");

Although prop changed the checked status but change also show that in the form.

$('input[name="correctAnswer"]').prop('checked', false).change();

If you want to clear all radio buttons in the DOM:

$('input[type=radio]').prop('checked',false);


$('#radio1').removeAttr('checked');
$('#radio2').removeAttr('checked');
$('#radio3').removeAttr('checked');
$('#radio4').removeAttr('checked');

Or

$('input[name="correctAnswer"]').removeAttr('checked');

<div id="radio">
<input type="radio" id="radio1" name="radio"/><label for="radio1">Bar Chart</label>
<input type="radio" id="radio2" name="radio"/><label for="radio2">Pie Chart</label>
<input type="radio" id="radio3" name="radio"/><label for="radio3">Datapoint Chart</label>
</div>

$('#radio input').removeAttr('checked');
// Refresh the jQuery UI buttonset.                  
$( "#radio" ).buttonset('refresh');

Set all radio buttons back to the default:

$("input[name='correctAnswer']").checkboxradio( "refresh" );