The one-liner that Andre Miller posted above works except for recent versions of sed when the input file ends with a blank line and no chars. On my Mac my CPU just spins.
Infinite loop if last line is blank and has no chars:
sed '$!N; /^\(.*\)\n\1$/!P; D'
Doesn't hang, but you lose the last line
sed '$d;N; /^\(.*\)\n\1$/!P; D'
The explanation is at the very end of the sed FAQ:
The GNU sed maintainer felt that despite the portability problems
this would cause, changing the N command to print (rather than
delete) the pattern space was more consistent with one's intuitions
about how a command to "append the Next line" ought to behave.
Another fact favoring the change was that "{N;command;}" will
delete the last line if the file has an odd number of lines, but
print the last line if the file has an even number of lines.To convert scripts which used the former behavior of N (deleting
the pattern space upon reaching the EOF) to scripts compatible with
all versions of sed, change a lone "N;" to "$d;N;".
This can be achieved using awk
Below Line will display unique Values
awk file_name | uniq
You can output these unique values to a new file
awk file_name | uniq > uniq_file_name
new file uniq_file_name will contain only Unique values, no duplicates
Perl one-liner similar to @jonas's awk solution:
perl -ne 'print if ! $x{$_}++' file
This variation removes trailing whitespace before comparing:
perl -lne 's/\s*$//; print if ! $x{$_}++' file
This variation edits the file in-place:
perl -i -ne 'print if ! $x{$_}++' file
This variation edits the file in-place, and makes a backup file.bak
perl -i.bak -ne 'print if ! $x{$_}++' file
uniq would be fooled by trailing spaces and tabs. In order to emulate how a human makes comparison, I am trimming all trailing spaces and tabs before comparison.
I think that the $!N; needs curly braces or else it continues, and that is the cause of infinite loop.
I have bash 5.0 and sed 4.7 in Ubuntu 20.10. The second one-liner did not work, at the character set match.
Three variations, first to eliminate adjacent repeat lines, second to eliminate repeat lines wherever they occur, third to eliminate all but the last instance of lines in file.
# First line in a set of duplicate lines is kept, rest are deleted.
# Emulate human eyes on trailing spaces and tabs by trimming those.
# Use after norepeat() to dedupe blank lines.
dedupe() {
sed -E '
$!{
N;
s/[ \t]+$//;
/^(.*)\n\1$/!P;
D;
}
';
}
# Delete duplicate, nonconsecutive lines from a file. Ignore blank
# lines. Trailing spaces and tabs are trimmed to humanize comparisons
# squeeze blank lines to one
norepeat() {
sed -n -E '
s/[ \t]+$//;
G;
/^(\n){2,}/d;
/^([^\n]+).*\n\1(\n|$)/d;
h;
P;
';
}
lastrepeat() {
sed -n -E '
s/[ \t]+$//;
/^$/{
H;
d;
};
G;
# delete previous repeated line if found
s/^([^\n]+)(.*)(\n\1(\n.*|$))/\1\2\4/;
# after searching for previous repeat, move tested last line to end
s/^([^\n]+)(\n)(.*)/\3\2\1/;
$!{
h;
d;
};
# squeeze blank lines to one
s/(\n){3,}/\n\n/g;
s/^\n//;
p;
';
}
cat filename | sort | uniq -c | awk -F" " '$1<2 {print $2}'
Deletes the duplicate lines using awk.
$ echo -e '1\n2\n2\n3\n3\n3\n4\n4\n4\n4\n5' |sed -nr '$!N;/^(.*)\n\1$/!P;D'
1
2
3
4
5
the core idea is:
print ONLY once of each duplicate consecutive lines at its LAST appearance and use D command to implement LOOP.
Explains:
$!N;: if current line is NOT the last line, use N command to read the next line into pattern space./^(.*)\n\1$/!P: if the contents of current pattern space is two duplicate string separated by \n, which means the next line is the same with current line, we can NOT print it according to our core idea; otherwise, which means current line is the LAST appearance of all of its duplicate consecutive lines, we can now use P command to print the chars in current pattern space util \n (\n also printed).D: we use D command to delete the chars in current pattern space util \n (\n also deleted), then the content of pattern space is the next line.D command will force sed to jump to its FIRST command $!N, but NOT read the next line from file or standard input stream.$ echo -e '1\n2\n2\n3\n3\n3\n4\n4\n4\n4\n5' |sed -nr 'p;:loop;$!N;s/^(.*)\n\1$/\1/;tloop;D'
1
2
3
4
5
the core idea is:
print ONLY once of each duplicate consecutive lines at its FIRST appearance and use : command & t command to implement LOOP.
Explains:
:loop command set a label named loop.N to read next line into the pattern space.s/^(.*)\n\1$/\1/ to delete current line if the next line is same with current line, we use s command to do the delete action.s command is executed successfully, then use tloop command force sed to jump to the label named loop, which will do the same loop to the next lines util there are no duplicate consecutive lines of the line which is latest printed; otherwise, use D command to delete the line which is the same with thelatest-printed line, and force sed to jump to first command, which is the p command, the content of current pattern space is the next new line.An alternative way using Vim(Vi compatible):
Delete duplicate, consecutive lines from a file:
vim -esu NONE +'g/\v^(.*)\n\1$/d' +wq
Delete duplicate, nonconsecutive and nonempty lines from a file:
vim -esu NONE +'g/\v^(.+)$\_.{-}^\1$/d' +wq
From http://sed.sourceforge.net/sed1line.txt: (Please don't ask me how this works ;-) )
# delete duplicate, consecutive lines from a file (emulates "uniq").
# First line in a set of duplicate lines is kept, rest are deleted.
sed '$!N; /^\(.*\)\n\1$/!P; D'
# delete duplicate, nonconsecutive lines from a file. Beware not to
# overflow the buffer size of the hold space, or else use GNU sed.
sed -n 'G; s/\n/&&/; /^\([ -~]*\n\).*\n\1/d; s/\n//; h; P'
Source: Stackoverflow.com