Here is an example where the things to add come from a dictionary
>>> L = [0, 0, 0, 0]
>>> things_to_add = ({'idx':1, 'amount': 1}, {'idx': 2, 'amount': 1})
>>> for item in things_to_add:
... L[item['idx']] += item['amount']
...
>>> L
[0, 1, 1, 0]
Here is an example adding elements from another list
>>> L = [0, 0, 0, 0]
>>> things_to_add = [0, 1, 1, 0]
>>> for idx, amount in enumerate(things_to_add):
... L[idx] += amount
...
>>> L
[0, 1, 1, 0]
You could also achieve the above with a list comprehension and zip
L[:] = [sum(i) for i in zip(L, things_to_add)]
Here is an example adding from a list of tuples
>>> things_to_add = [(1, 1), (2, 1)]
>>> for idx, amount in things_to_add:
... L[idx] += amount
...
>>> L
[0, 1, 1, 0]
If you try appending the number like, say
listName.append(4) , this will append 4 at last.
But if you are trying to take <int> and then append it as, num = 4 followed by listName.append(num), this will give you an error as 'num' is of <int> type and listName is of type <list>. So do type cast int(num) before appending it.
Yes, it is possible since lists are mutable.
Look at the built-in enumerate() function to get an idea how to iterate over the list and find each entry's index (which you can then use to assign to the specific list item).
You can append to the end of a list:
foo = [1, 2, 3, 4, 5]
foo.append(4)
foo.append([8,7])
print(foo) # [1, 2, 3, 4, 5, 4, [8, 7]]
You can edit items in the list like this:
foo = [1, 2, 3, 4, 5]
foo[3] = foo[3] + 4
print(foo) # [1, 2, 3, 8, 5]
Insert integers into the middle of a list:
x = [2, 5, 10]
x.insert(2, 77)
print(x) # [2, 5, 77, 10]
fooList = [1,3,348,2]
fooList.append(3)
fooList.append(2734)
print(fooList) # [1,3,348,2,3,2734]
Source: Stackoverflow.com