[php] MySQL query String contains

I've been trying to figure out how I can make a query with MySQL that checks if the value (string $haystack ) in a certain column contains certain data (string $needle), like this:

mysql_query("
SELECT *
FROM `table`
WHERE `column`.contains('{$needle}')
");

In PHP, the function is called substr($haystack, $needle), so maybe:

WHERE substr(`column`, '{$needle}')=1

This question is related to php mysql sql string-comparison

The answer is


You probably are looking for find_in_set function:

Where find_in_set($needle,'column') > 0

This function acts like in_array function in PHP


be aware that this is dangerous:

WHERE `column` LIKE '%{$needle}%'

do first:

$needle = mysql_real_escape_string($needle);

so it will prevent possible attacks.


Use:

SELECT *
  FROM `table`
 WHERE INSTR(`column`, '{$needle}') > 0

Reference:


WHERE `column` LIKE '%$needle%'

Mine is using LOCATE in mysql:

LOCATE(substr,str), LOCATE(substr,str,pos)

This function is multi-byte safe, and is case-sensitive only if at least one argument is a binary string.

In your case:

mysql_query("
SELECT * FROM `table`
WHERE LOCATE('{$needle}','column') > 0
");

In addition to the answer from @WoLpH.

When using the LIKE keyword you also have the ability to limit which direction the string matches. For example:

If you were looking for a string that starts with your $needle:

... WHERE column LIKE '{$needle}%'

If you were looking for a string that ends with the $needle:

... WHERE column LIKE '%{$needle}'

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