[php] Test if a string contains a word in PHP?

In SQL we have NOT LIKE %string%

I need to do this in PHP.

if ($string NOT LIKE %word%) { do something }

I think that can be done with strpos()

But can’t figure out how…

I need exactly that comparission sentence in valid PHP.

if ($string NOT LIKE %word%) { do something }

If you wanna find just the word like 'are' in "How are you?" and not like 'are' in 'hare'

$word=" are ";
$str="How are you?";
if(strpos($word,$str) !== false){
echo 1;
 }

Use strpos. If the string is not found it returns false, otherwise something that is not false. Be sure to use a type-safe comparison (===) as 0 may be returned and it is a falsy value:

if (strpos($string, $substring) === false) {
    // substring is not found in string
}

if (strpos($string, $substring2) !== false) {
    // substring2 is found in string
}

<?php
//  Use this function and Pass Mixed string and what you want to search in mixed string.
//  For Example :
    $mixedStr = "hello world. This is john duvey";
    $searchStr= "john";

    if(strpos($mixedStr,$searchStr)) {
      echo "Your string here";
    }else {
      echo "String not here";
    }