I am trying to extract everything before the ',' comma. How do I do this in JavaScript or jQuery? I tried this and not working..
1345 albany street, Bellevue WA 42344
I just want to grab the street address.
var streetaddress= substr(addy, 0, index(addy, '.'));
This question is related to
javascript
jquery
substring
substr
If you want to return the original string untouched if it does not contain the search character then you can use an anonymous function (a closure):
var streetaddress=(function(s){var i=s.indexOf(',');
return i==-1 ? s : s.substr(0,i);})(addy);
This can be made more generic:
var streetaddress=(function(s,c){var i=s.indexOf(c);
return i==-1 ? s : s.substr(0,i);})(addy,',');
var streetaddress = addy.split(',')[0];
try this:
streetaddress.substring(0, streetaddress.indexOf(','));
You can also use shift()
.
var streetaddress = addy.split(',').shift();
According to MDN Web Docs:
The
shift()
method removes the first element from an array and returns that removed element. This method changes the length of the array.
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/shift
//split string into an array and grab the first item
var streetaddress = addy.split(',')[0];
Also, I'd recommend naming your variables with camel-case(streetAddress) for better readability.
You could use regex as this will give you the string if it matches the requirements. The code would be something like:
const address = "1345 albany street, Bellevue WA 42344";
const regex = /[1-9][0-9]* [a-zA-Z]+ [a-zA-Z]+/;
const matchedResult = address.match(regex);
console.log(matchedResult[0]); // This will give you 1345 albany street.
So to break the code down. [1-9][0-9]*
basically means the first number cannot be a zero and has to be a number between 1-9
and the next number can be any number from 0-9
and can occur zero or more times as sometimes the number is just one digit and then it matches a space. [a-zA-Z]
basically matches all capital letters to small letters and has to occur one or more times and this is repeated.
var streetaddress = addy.substr(0, addy.indexOf('.'));
(You should read through a javascript tutorial, esp. the part about String functions)
almost the same thing as David G's answer but without the anonymous function, if you don't feel like including one.
s = s.substr(0, s.indexOf(',') === -1 ? s.length : s.indexOf(','));
in this case we make use of the fact that the second argument of substr
is a length, and that we know our substring is starting at 0.
the top answer is not a generic solution because of the undesirable behavior if the string doesn't contain the character you are looking for.
if you want correct behavior in a generic case, use this method or David G's method, not the top answer
regex and split methods will also work, but may be somewhat slower / overkill for this specific problem.
var newString = string.substr(0,string.indexOf(','));
If you like it short simply use a RegExp:
var streetAddress = /[^,]*/.exec(addy)[0];
Source: Stackoverflow.com