[sql] Split String by delimiter position using oracle SQL

You want to use regexp_substr() for this. This should work for your example:

select regexp_substr(val, '[^/]+/[^/]+', 1, 1) as part1,
       regexp_substr(val, '[^/]+$', 1, 1) as part2
from (select 'F/P/O' as val from dual) t

Here, by the way, is the SQL Fiddle.

Oops. I missed the part of the question where it says the last delimiter. For that, we can use regex_replace() for the first part:

select regexp_replace(val, '/[^/]+$', '', 1, 1) as part1,
       regexp_substr(val, '[^/]+$', 1, 1) as part2
from (select 'F/P/O' as val from dual) t

And here is this corresponding SQL Fiddle.

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