# Skip over a value in the range function in python

59

What is the pythonic way of looping through a range of numbers and skipping over one value? For example, the range is from 0 to 100 and I would like to skip 50.

Edit: Here's the code that I'm using

``````for i in range(0, len(list)):
x= listRow(list, i)
for j in range (#0 to len(list) not including x#)
...
``````

This question is tagged with `python` `loops` `for-loop` `range`

89

You can use any of these:

``````# Create a range that does not contain 50
for i in [x for x in xrange(100) if x != 50]:
print i

# Create 2 ranges [0,49] and [51, 100] (Python 2)
for i in range(50) + range(51, 100):
print i

# Create a iterator and skip 50
xr = iter(xrange(100))
for i in xr:
print i
if i == 49:
next(xr)

# Simply continue in the loop if the number is 50
for i in range(100):
if i == 50:
continue
print i
``````

3

In addition to the Python 2 approach here are the equivalents for Python 3:

``````# Create a range that does not contain 50
for i in [x for x in range(100) if x != 50]:
print(i)

# Create 2 ranges [0,49] and [51, 100]
from itertools import chain
concatenated = chain(range(50), range(51, 100))
for i in concatenated:
print(i)

# Create a iterator and skip 50
xr = iter(range(100))
for i in xr:
print(i)
if i == 49:
next(xr)

# Simply continue in the loop if the number is 50
for i in range(100):
if i == 50:
continue
print(i)
``````

Ranges are lists in Python 2 and iterators in Python 3.