[for-loop] TypeScript for ... of with index / key?

.forEach already has this ability:

const someArray = [9, 2, 5];
someArray.forEach((value, index) => {
    console.log(index); // 0, 1, 2
    console.log(value); // 9, 2, 5
});

But if you want the abilities of for...of, then you can map the array to the index and value:

for (const { index, value } of someArray.map((value, index) => ({ index, value }))) {
    console.log(index); // 0, 1, 2
    console.log(value); // 9, 2, 5
}

That's a little long, so it may help to put it in a reusable function:

function toEntries<T>(a: T[]) {
    return a.map((value, index) => [index, value] as const);
}

for (const [index, value] of toEntries(someArray)) {
    // ..etc..
}

Iterable Version

This will work when targeting ES3 or ES5 if you compile with the --downlevelIteration compiler option.

function* toEntries<T>(values: T[] | IterableIterator<T>) {
    let index = 0;
    for (const value of values) {
        yield [index, value] as const;
        index++;
    }
}

Array.prototype.entries() - ES6+

If you are able to target ES6+ environments then you can use the .entries() method as outlined in Arnavion's answer.

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