SyntaxFix
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You could take a Set and filter the values who are alreday seen.
Set
var array = ["q", "w", "w", "e", "i", "u", "r"],_x000D_ seen = array.filter((s => v => s.has(v) || !s.add(v))(new Set));_x000D_ _x000D_ console.log(seen);