[ios] CGContextDrawImage draws image upside down when passed UIImage.CGImage

Does anyone know why CGContextDrawImage would be drawing my image upside down? I am loading an image in from my application:

UIImage *image = [UIImage imageNamed:@"testImage.png"];

And then simply asking core graphics to draw it to my context:

CGContextDrawImage(context, CGRectMake(0, 0, 145, 15), image.CGImage);

It renders in the right place, and dimensions, but the image is upside down. I must be missing something really obvious here?

This question is related to ios cocoa-touch core-graphics cgcontextdrawimage

The answer is


Relevant Quartz2D docs: https://developer.apple.com/library/ios/documentation/2DDrawing/Conceptual/DrawingPrintingiOS/GraphicsDrawingOverview/GraphicsDrawingOverview.html#//apple_ref/doc/uid/TP40010156-CH14-SW4

Flipping the Default Coordinate System

Flipping in UIKit drawing modifies the backing CALayer to align a drawing environment having a LLO coordinate system with the default coordinate system of UIKit. If you only use UIKit methods and function for drawing, you shouldn’t need to flip the CTM. However, if you mix Core Graphics or Image I/O function calls with UIKit calls, flipping the CTM might be necessary.

Specifically, if you draw an image or PDF document by calling Core Graphics functions directly, the object is rendered upside-down in the view’s context. You must flip the CTM to display the image and pages correctly.

To flip a object drawn to a Core Graphics context so that it appears correctly when displayed in a UIKit view, you must modify the CTM in two steps. You translate the origin to the upper-left corner of the drawing area, and then you apply a scale translation, modifying the y-coordinate by -1. The code for doing this looks similar to the following:

CGContextSaveGState(graphicsContext);
CGContextTranslateCTM(graphicsContext, 0.0, imageHeight);
CGContextScaleCTM(graphicsContext, 1.0, -1.0);
CGContextDrawImage(graphicsContext, image, CGRectMake(0, 0, imageWidth, imageHeight));
CGContextRestoreGState(graphicsContext);

Best of both worlds, use UIImage's drawAtPoint: or drawInRect: while still specifying your custom context:

UIGraphicsPushContext(context);
[image drawAtPoint:CGPointZero]; // UIImage will handle all especial cases!
UIGraphicsPopContext();

Also you avoid modifying your context with CGContextTranslateCTM or CGContextScaleCTM which the second answer does.


It happens because QuartzCore has the coordinate system "bottom-left", while UIKit – "top-left".

In the case you can extend CGContext:

extension CGContext {
  func changeToTopLeftCoordinateSystem() {
    translateBy(x: 0, y: boundingBoxOfClipPath.size.height)
    scaleBy(x: 1, y: -1)
  }
}

// somewhere in render 
ctx.saveGState()
ctx.changeToTopLeftCoordinateSystem()
ctx.draw(cgImage!, in: frame)

I'm not sure for UIImage, but this kind of behaviour usually occurs when coordinates are flipped. Most of OS X coordinate systems have their origin at the lower left corner, as in Postscript and PDF. But CGImage coordinate system has its origin at the upper left corner.

Possible solutions may involve an isFlipped property or a scaleYBy:-1 affine transform.


You can also solve this problem by doing this:

//Using an Image as a mask by directly inserting UIImageObject.CGImage causes
//the same inverted display problem. This is solved by saving it to a CGImageRef first.

//CGImageRef image = [UImageObject CGImage];

//CGContextDrawImage(context, boundsRect, image);

Nevermind... Stupid caching.

Swift 3.0 & 4.0

yourImage.draw(in: CGRect, blendMode: CGBlendMode, alpha: ImageOpacity)

No Alteration needed


Supplemental answer with Swift code

Quartz 2D graphics use a coordinate system with the origin in the bottom left while UIKit in iOS uses a coordinate system with the origin at the top left. Everything usually works fine but when doing some graphics operations, you have to modify the coordinate system yourself. The documentation states:

Some technologies set up their graphics contexts using a different default coordinate system than the one used by Quartz. Relative to Quartz, such a coordinate system is a modified coordinate system and must be compensated for when performing some Quartz drawing operations. The most common modified coordinate system places the origin in the upper-left corner of the context and changes the y-axis to point towards the bottom of the page.

This phenomenon can be seen in the following two instances of custom views that draw an image in their drawRect methods.

enter image description here

On the left side, the image is upside-down and on the right side the coordinate system has been translated and scaled so that the origin is in the top left.

Upside-down image

override func drawRect(rect: CGRect) {

    // image
    let image = UIImage(named: "rocket")!
    let imageRect = CGRect(x: 0, y: 0, width: image.size.width, height: image.size.height)

    // context
    let context = UIGraphicsGetCurrentContext()

    // draw image in context
    CGContextDrawImage(context, imageRect, image.CGImage)

}

Modified coordinate system

override func drawRect(rect: CGRect) {

    // image
    let image = UIImage(named: "rocket")!
    let imageRect = CGRect(x: 0, y: 0, width: image.size.width, height: image.size.height)

    // context
    let context = UIGraphicsGetCurrentContext()

    // save the context so that it can be undone later
    CGContextSaveGState(context)

    // put the origin of the coordinate system at the top left
    CGContextTranslateCTM(context, 0, image.size.height)
    CGContextScaleCTM(context, 1.0, -1.0)

    // draw the image in the context
    CGContextDrawImage(context, imageRect, image.CGImage)

    // undo changes to the context
    CGContextRestoreGState(context)
}

Even after applying everything I have mentioned, I've still had dramas with the images. In the end, i've just used Gimp to create a 'flipped vertical' version of all my images. Now I don't need to use any Transforms. Hopefully this won't cause further problems down the track.

Does anyone know why CGContextDrawImage would be drawing my image upside down? I am loading an image in from my application:

Quartz2d uses a different co-ordinate system, where the origin is in the lower left corner. So when Quartz draws pixel x[5], y[10] of a 100 * 100 image, that pixel is being drawn in the lower left corner instead of the upper left. Thus causing the 'flipped' image.

The x co-ordinate system matches, so you will need to flip the y co-ordinates.

CGContextTranslateCTM(context, 0, image.size.height);

This means we have translated the image by 0 units on the x axis and by the images height on the y axis. However, this alone will mean our image is still upside down, just being drawn "image.size.height" below where we wish it to be drawn.

The Quartz2D programming guide recommends using ScaleCTM and passing negative values to flip the image. You can use the following code to do this -

CGContextScaleCTM(context, 1.0, -1.0);

Combine the two just before your CGContextDrawImage call and you should have the image drawn correctly.

UIImage *image = [UIImage imageNamed:@"testImage.png"];    
CGRect imageRect = CGRectMake(0, 0, image.size.width, image.size.height);       

CGContextTranslateCTM(context, 0, image.size.height);
CGContextScaleCTM(context, 1.0, -1.0);

CGContextDrawImage(context, imageRect, image.CGImage);

Just be careful if your imageRect co-ordinates do not match those of your image, as you can get unintended results.

To convert back the coordinates:

CGContextScaleCTM(context, 1.0, -1.0);
CGContextTranslateCTM(context, 0, -imageRect.size.height);

I'm not sure for UIImage, but this kind of behaviour usually occurs when coordinates are flipped. Most of OS X coordinate systems have their origin at the lower left corner, as in Postscript and PDF. But CGImage coordinate system has its origin at the upper left corner.

Possible solutions may involve an isFlipped property or a scaleYBy:-1 affine transform.


Best of both worlds, use UIImage's drawAtPoint: or drawInRect: while still specifying your custom context:

UIGraphicsPushContext(context);
[image drawAtPoint:CGPointZero]; // UIImage will handle all especial cases!
UIGraphicsPopContext();

Also you avoid modifying your context with CGContextTranslateCTM or CGContextScaleCTM which the second answer does.


If anyone is interested in a no-brainer solution for drawing an image in a custom rect in a context:

 func drawImage(image: UIImage, inRect rect: CGRect, context: CGContext!) {

    //flip coords
    let ty: CGFloat = (rect.origin.y + rect.size.height)
    CGContextTranslateCTM(context, 0, ty)
    CGContextScaleCTM(context, 1.0, -1.0)

    //draw image
    let rect__y_zero = CGRect(origin: CGPoint(x: rect.origin.x, y:0), size: rect.size)
    CGContextDrawImage(context, rect__y_zero, image.CGImage)

    //flip back
    CGContextScaleCTM(context, 1.0, -1.0)
    CGContextTranslateCTM(context, 0, -ty)

}

The image will be scaled to fill the rect.


I use this Swift 5, pure Core Graphics extension that correctly handles non-zero origins in image rects:

extension CGContext {

    /// Draw `image` flipped vertically, positioned and scaled inside `rect`.
    public func drawFlipped(_ image: CGImage, in rect: CGRect) {
        self.saveGState()
        self.translateBy(x: 0, y: rect.origin.y + rect.height)
        self.scaleBy(x: 1.0, y: -1.0)
        self.draw(image, in: CGRect(origin: CGPoint(x: rect.origin.x, y: 0), size: rect.size))
        self.restoreGState()
    }
}

You can use it exactly like CGContext's regular draw(: in:) method:

ctx.drawFlipped(myImage, in: myRect)

Even after applying everything I have mentioned, I've still had dramas with the images. In the end, i've just used Gimp to create a 'flipped vertical' version of all my images. Now I don't need to use any Transforms. Hopefully this won't cause further problems down the track.

Does anyone know why CGContextDrawImage would be drawing my image upside down? I am loading an image in from my application:

Quartz2d uses a different co-ordinate system, where the origin is in the lower left corner. So when Quartz draws pixel x[5], y[10] of a 100 * 100 image, that pixel is being drawn in the lower left corner instead of the upper left. Thus causing the 'flipped' image.

The x co-ordinate system matches, so you will need to flip the y co-ordinates.

CGContextTranslateCTM(context, 0, image.size.height);

This means we have translated the image by 0 units on the x axis and by the images height on the y axis. However, this alone will mean our image is still upside down, just being drawn "image.size.height" below where we wish it to be drawn.

The Quartz2D programming guide recommends using ScaleCTM and passing negative values to flip the image. You can use the following code to do this -

CGContextScaleCTM(context, 1.0, -1.0);

Combine the two just before your CGContextDrawImage call and you should have the image drawn correctly.

UIImage *image = [UIImage imageNamed:@"testImage.png"];    
CGRect imageRect = CGRectMake(0, 0, image.size.width, image.size.height);       

CGContextTranslateCTM(context, 0, image.size.height);
CGContextScaleCTM(context, 1.0, -1.0);

CGContextDrawImage(context, imageRect, image.CGImage);

Just be careful if your imageRect co-ordinates do not match those of your image, as you can get unintended results.

To convert back the coordinates:

CGContextScaleCTM(context, 1.0, -1.0);
CGContextTranslateCTM(context, 0, -imageRect.size.height);

Swift 3 CoreGraphics Solution

If you want to use CG for whatever your reason might be, instead of UIImage, this Swift 3 construction based on previous answers did solve the issue for me:

if let cgImage = uiImage.cgImage {
    cgContext.saveGState()
    cgContext.translateBy(x: 0.0, y: cgRect.size.height)
    cgContext.scaleBy(x: 1.0, y: -1.0)
    cgContext.draw(cgImage, in: cgRect)
    cgContext.restoreGState()
}

UIImage contains a CGImage as its main content member as well as scaling and orientation factors. Since CGImage and its various functions are derived from OSX, it expects a coordinate system that is upside down compared to the iPhone. When you create a UIImage, it defaults to an upside-down orientation to compensate (you can change this!). Use the .CGImage property to access the very powerful CGImage functions, but drawing onto the iPhone screen etc. is best done with the UIImage methods.


Even after applying everything I have mentioned, I've still had dramas with the images. In the end, i've just used Gimp to create a 'flipped vertical' version of all my images. Now I don't need to use any Transforms. Hopefully this won't cause further problems down the track.

Does anyone know why CGContextDrawImage would be drawing my image upside down? I am loading an image in from my application:

Quartz2d uses a different co-ordinate system, where the origin is in the lower left corner. So when Quartz draws pixel x[5], y[10] of a 100 * 100 image, that pixel is being drawn in the lower left corner instead of the upper left. Thus causing the 'flipped' image.

The x co-ordinate system matches, so you will need to flip the y co-ordinates.

CGContextTranslateCTM(context, 0, image.size.height);

This means we have translated the image by 0 units on the x axis and by the images height on the y axis. However, this alone will mean our image is still upside down, just being drawn "image.size.height" below where we wish it to be drawn.

The Quartz2D programming guide recommends using ScaleCTM and passing negative values to flip the image. You can use the following code to do this -

CGContextScaleCTM(context, 1.0, -1.0);

Combine the two just before your CGContextDrawImage call and you should have the image drawn correctly.

UIImage *image = [UIImage imageNamed:@"testImage.png"];    
CGRect imageRect = CGRectMake(0, 0, image.size.width, image.size.height);       

CGContextTranslateCTM(context, 0, image.size.height);
CGContextScaleCTM(context, 1.0, -1.0);

CGContextDrawImage(context, imageRect, image.CGImage);

Just be careful if your imageRect co-ordinates do not match those of your image, as you can get unintended results.

To convert back the coordinates:

CGContextScaleCTM(context, 1.0, -1.0);
CGContextTranslateCTM(context, 0, -imageRect.size.height);

Swift 3 CoreGraphics Solution

If you want to use CG for whatever your reason might be, instead of UIImage, this Swift 3 construction based on previous answers did solve the issue for me:

if let cgImage = uiImage.cgImage {
    cgContext.saveGState()
    cgContext.translateBy(x: 0.0, y: cgRect.size.height)
    cgContext.scaleBy(x: 1.0, y: -1.0)
    cgContext.draw(cgImage, in: cgRect)
    cgContext.restoreGState()
}

It happens because QuartzCore has the coordinate system "bottom-left", while UIKit – "top-left".

In the case you can extend CGContext:

extension CGContext {
  func changeToTopLeftCoordinateSystem() {
    translateBy(x: 0, y: boundingBoxOfClipPath.size.height)
    scaleBy(x: 1, y: -1)
  }
}

// somewhere in render 
ctx.saveGState()
ctx.changeToTopLeftCoordinateSystem()
ctx.draw(cgImage!, in: frame)

drawInRect is certainly the way to go. Here's another little thing that will come in way useful when doing this. Usually the picture and the rectangle into which it is going to go don't conform. In that case drawInRect will stretch the picture. Here's a quick and cool way to make sure that the picture's aspect ration isn't changed, by reversing the transformation (which will be to fit the whole thing in):

//Picture and irect don't conform, so there'll be stretching, compensate
    float xf = Picture.size.width/irect.size.width;
    float yf = Picture.size.height/irect.size.height;
    float m = MIN(xf, yf);
    xf /= m;
    yf /= m;
    CGContextScaleCTM(ctx, xf, yf);

    [Picture drawInRect: irect];

During the course of my project I jumped from Kendall's answer to Cliff's answer to solve this problem for images that are loaded from the phone itself.

In the end I ended up using CGImageCreateWithPNGDataProvider instead:

NSString* imageFileName = [[[NSBundle mainBundle] resourcePath] stringByAppendingPathComponent:@"clockdial.png"];

return CGImageCreateWithPNGDataProvider(CGDataProviderCreateWithFilename([imageFileName UTF8String]), NULL, YES, kCGRenderingIntentDefault);

This doesn't suffer from the orientation issues that you would get from getting the CGImage from a UIImage and it can be used as the contents of a CALayer without a hitch.


We can solve this problem using the same function:

UIGraphicsBeginImageContext(image.size);

UIGraphicsPushContext(context);

[image drawInRect:CGRectMake(gestureEndPoint.x,gestureEndPoint.y,350,92)];

UIGraphicsPopContext();

UIGraphicsEndImageContext();

I use this Swift 5, pure Core Graphics extension that correctly handles non-zero origins in image rects:

extension CGContext {

    /// Draw `image` flipped vertically, positioned and scaled inside `rect`.
    public func drawFlipped(_ image: CGImage, in rect: CGRect) {
        self.saveGState()
        self.translateBy(x: 0, y: rect.origin.y + rect.height)
        self.scaleBy(x: 1.0, y: -1.0)
        self.draw(image, in: CGRect(origin: CGPoint(x: rect.origin.x, y: 0), size: rect.size))
        self.restoreGState()
    }
}

You can use it exactly like CGContext's regular draw(: in:) method:

ctx.drawFlipped(myImage, in: myRect)

Swift 3.0 & 4.0

yourImage.draw(in: CGRect, blendMode: CGBlendMode, alpha: ImageOpacity)

No Alteration needed


During the course of my project I jumped from Kendall's answer to Cliff's answer to solve this problem for images that are loaded from the phone itself.

In the end I ended up using CGImageCreateWithPNGDataProvider instead:

NSString* imageFileName = [[[NSBundle mainBundle] resourcePath] stringByAppendingPathComponent:@"clockdial.png"];

return CGImageCreateWithPNGDataProvider(CGDataProviderCreateWithFilename([imageFileName UTF8String]), NULL, YES, kCGRenderingIntentDefault);

This doesn't suffer from the orientation issues that you would get from getting the CGImage from a UIImage and it can be used as the contents of a CALayer without a hitch.


Even after applying everything I have mentioned, I've still had dramas with the images. In the end, i've just used Gimp to create a 'flipped vertical' version of all my images. Now I don't need to use any Transforms. Hopefully this won't cause further problems down the track.

Does anyone know why CGContextDrawImage would be drawing my image upside down? I am loading an image in from my application:

Quartz2d uses a different co-ordinate system, where the origin is in the lower left corner. So when Quartz draws pixel x[5], y[10] of a 100 * 100 image, that pixel is being drawn in the lower left corner instead of the upper left. Thus causing the 'flipped' image.

The x co-ordinate system matches, so you will need to flip the y co-ordinates.

CGContextTranslateCTM(context, 0, image.size.height);

This means we have translated the image by 0 units on the x axis and by the images height on the y axis. However, this alone will mean our image is still upside down, just being drawn "image.size.height" below where we wish it to be drawn.

The Quartz2D programming guide recommends using ScaleCTM and passing negative values to flip the image. You can use the following code to do this -

CGContextScaleCTM(context, 1.0, -1.0);

Combine the two just before your CGContextDrawImage call and you should have the image drawn correctly.

UIImage *image = [UIImage imageNamed:@"testImage.png"];    
CGRect imageRect = CGRectMake(0, 0, image.size.width, image.size.height);       

CGContextTranslateCTM(context, 0, image.size.height);
CGContextScaleCTM(context, 1.0, -1.0);

CGContextDrawImage(context, imageRect, image.CGImage);

Just be careful if your imageRect co-ordinates do not match those of your image, as you can get unintended results.

To convert back the coordinates:

CGContextScaleCTM(context, 1.0, -1.0);
CGContextTranslateCTM(context, 0, -imageRect.size.height);

You can also solve this problem by doing this:

//Using an Image as a mask by directly inserting UIImageObject.CGImage causes
//the same inverted display problem. This is solved by saving it to a CGImageRef first.

//CGImageRef image = [UImageObject CGImage];

//CGContextDrawImage(context, boundsRect, image);

Nevermind... Stupid caching.

Swift 5 answer based on @ZpaceZombor's excellent answer

If you have a UIImage, just use

var image: UIImage = .... 
image.draw(in: CGRect)

If you have a CGImage use my category below

Note: Unlike some other answers, this one takes into account that the rect you want to draw in might have y != 0. Those answers that don't take that into account are incorrect and won't work in the general case.

extension CGContext {
    final func drawImage(image: CGImage, inRect rect: CGRect) {

        //flip coords
        let ty: CGFloat = (rect.origin.y + rect.size.height)
        translateBy(x: 0, y: ty)
        scaleBy(x: 1.0, y: -1.0)

        //draw image
        let rect__y_zero = CGRect(x: rect.origin.x, y: 0, width: rect.width, height: rect.height)
        draw(image, in: rect__y_zero)

        //flip back
        scaleBy(x: 1.0, y: -1.0)
        translateBy(x: 0, y: -ty)

    }
} 

Use like this:

let imageFrame: CGRect = ...
let context: CGContext = ....
let img: CGImage = ..... 
context.drawImage(image: img, inRect: imageFrame)

Supplemental answer with Swift code

Quartz 2D graphics use a coordinate system with the origin in the bottom left while UIKit in iOS uses a coordinate system with the origin at the top left. Everything usually works fine but when doing some graphics operations, you have to modify the coordinate system yourself. The documentation states:

Some technologies set up their graphics contexts using a different default coordinate system than the one used by Quartz. Relative to Quartz, such a coordinate system is a modified coordinate system and must be compensated for when performing some Quartz drawing operations. The most common modified coordinate system places the origin in the upper-left corner of the context and changes the y-axis to point towards the bottom of the page.

This phenomenon can be seen in the following two instances of custom views that draw an image in their drawRect methods.

enter image description here

On the left side, the image is upside-down and on the right side the coordinate system has been translated and scaled so that the origin is in the top left.

Upside-down image

override func drawRect(rect: CGRect) {

    // image
    let image = UIImage(named: "rocket")!
    let imageRect = CGRect(x: 0, y: 0, width: image.size.width, height: image.size.height)

    // context
    let context = UIGraphicsGetCurrentContext()

    // draw image in context
    CGContextDrawImage(context, imageRect, image.CGImage)

}

Modified coordinate system

override func drawRect(rect: CGRect) {

    // image
    let image = UIImage(named: "rocket")!
    let imageRect = CGRect(x: 0, y: 0, width: image.size.width, height: image.size.height)

    // context
    let context = UIGraphicsGetCurrentContext()

    // save the context so that it can be undone later
    CGContextSaveGState(context)

    // put the origin of the coordinate system at the top left
    CGContextTranslateCTM(context, 0, image.size.height)
    CGContextScaleCTM(context, 1.0, -1.0)

    // draw the image in the context
    CGContextDrawImage(context, imageRect, image.CGImage)

    // undo changes to the context
    CGContextRestoreGState(context)
}

Swift 5 answer based on @ZpaceZombor's excellent answer

If you have a UIImage, just use

var image: UIImage = .... 
image.draw(in: CGRect)

If you have a CGImage use my category below

Note: Unlike some other answers, this one takes into account that the rect you want to draw in might have y != 0. Those answers that don't take that into account are incorrect and won't work in the general case.

extension CGContext {
    final func drawImage(image: CGImage, inRect rect: CGRect) {

        //flip coords
        let ty: CGFloat = (rect.origin.y + rect.size.height)
        translateBy(x: 0, y: ty)
        scaleBy(x: 1.0, y: -1.0)

        //draw image
        let rect__y_zero = CGRect(x: rect.origin.x, y: 0, width: rect.width, height: rect.height)
        draw(image, in: rect__y_zero)

        //flip back
        scaleBy(x: 1.0, y: -1.0)
        translateBy(x: 0, y: -ty)

    }
} 

Use like this:

let imageFrame: CGRect = ...
let context: CGContext = ....
let img: CGImage = ..... 
context.drawImage(image: img, inRect: imageFrame)

func renderImage(size: CGSize) -> UIImage {
    return UIGraphicsImageRenderer(size: size).image { rendererContext in
        // flip y axis
        rendererContext.cgContext.translateBy(x: 0, y: size.height)
        rendererContext.cgContext.scaleBy(x: 1, y: -1)

        // draw image rotated/offsetted
        rendererContext.cgContext.saveGState()
        rendererContext.cgContext.translateBy(x: translate.x, y: translate.y)
        rendererContext.cgContext.rotate(by: rotateRadians)
        rendererContext.cgContext.draw(cgImage, in: drawRect)
        rendererContext.cgContext.restoreGState()
    }
}

drawInRect is certainly the way to go. Here's another little thing that will come in way useful when doing this. Usually the picture and the rectangle into which it is going to go don't conform. In that case drawInRect will stretch the picture. Here's a quick and cool way to make sure that the picture's aspect ration isn't changed, by reversing the transformation (which will be to fit the whole thing in):

//Picture and irect don't conform, so there'll be stretching, compensate
    float xf = Picture.size.width/irect.size.width;
    float yf = Picture.size.height/irect.size.height;
    float m = MIN(xf, yf);
    xf /= m;
    yf /= m;
    CGContextScaleCTM(ctx, xf, yf);

    [Picture drawInRect: irect];

func renderImage(size: CGSize) -> UIImage {
    return UIGraphicsImageRenderer(size: size).image { rendererContext in
        // flip y axis
        rendererContext.cgContext.translateBy(x: 0, y: size.height)
        rendererContext.cgContext.scaleBy(x: 1, y: -1)

        // draw image rotated/offsetted
        rendererContext.cgContext.saveGState()
        rendererContext.cgContext.translateBy(x: translate.x, y: translate.y)
        rendererContext.cgContext.rotate(by: rotateRadians)
        rendererContext.cgContext.draw(cgImage, in: drawRect)
        rendererContext.cgContext.restoreGState()
    }
}

UIImage contains a CGImage as its main content member as well as scaling and orientation factors. Since CGImage and its various functions are derived from OSX, it expects a coordinate system that is upside down compared to the iPhone. When you create a UIImage, it defaults to an upside-down orientation to compensate (you can change this!). Use the .CGImage property to access the very powerful CGImage functions, but drawing onto the iPhone screen etc. is best done with the UIImage methods.


I'm not sure for UIImage, but this kind of behaviour usually occurs when coordinates are flipped. Most of OS X coordinate systems have their origin at the lower left corner, as in Postscript and PDF. But CGImage coordinate system has its origin at the upper left corner.

Possible solutions may involve an isFlipped property or a scaleYBy:-1 affine transform.


If anyone is interested in a no-brainer solution for drawing an image in a custom rect in a context:

 func drawImage(image: UIImage, inRect rect: CGRect, context: CGContext!) {

    //flip coords
    let ty: CGFloat = (rect.origin.y + rect.size.height)
    CGContextTranslateCTM(context, 0, ty)
    CGContextScaleCTM(context, 1.0, -1.0)

    //draw image
    let rect__y_zero = CGRect(origin: CGPoint(x: rect.origin.x, y:0), size: rect.size)
    CGContextDrawImage(context, rect__y_zero, image.CGImage)

    //flip back
    CGContextScaleCTM(context, 1.0, -1.0)
    CGContextTranslateCTM(context, 0, -ty)

}

The image will be scaled to fill the rect.


We can solve this problem using the same function:

UIGraphicsBeginImageContext(image.size);

UIGraphicsPushContext(context);

[image drawInRect:CGRectMake(gestureEndPoint.x,gestureEndPoint.y,350,92)];

UIGraphicsPopContext();

UIGraphicsEndImageContext();

I'm not sure for UIImage, but this kind of behaviour usually occurs when coordinates are flipped. Most of OS X coordinate systems have their origin at the lower left corner, as in Postscript and PDF. But CGImage coordinate system has its origin at the upper left corner.

Possible solutions may involve an isFlipped property or a scaleYBy:-1 affine transform.


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