[bash] Get current directory name (without full path) in a Bash script

How would I get just the current working directory name in a bash script, or even better, just a terminal command.

pwd gives the full path of the current working directory, e.g. /opt/local/bin but I only want bin

There are a lots way of doing that I particularly liked Charles way because it avoid a new process, but before know this I solved it with awk

pwd | awk -F/ '{print $NF}'

echo "$PWD" | sed 's!.*/!!'

If you are using Bourne shell or ${PWD##*/} is not available.

If you want to see only the current directory in the bash prompt region, you can edit .bashrc file in ~. Change \w to \W in the line:

PS1='${debian_chroot:+($debian_chroot)}\[\033[01;32m\]\u@\h\[\033[00m\]:\[\033[01;34m\]\w\[\033[00m\]\$ '

Run source ~/.bashrc and it will only display the directory name in the prompt region.

Ref: https://superuser.com/questions/60555/show-only-current-directory-name-not-full-path-on-bash-prompt

Use the basename program. For your case:

% basename "$PWD"
bin

basename $(pwd)

or

echo "$(basename $(pwd))"

You can use the basename utility which deletes any prefix ending in / and the suffix (if present in string) from string, and prints the result on the standard output.

$basename <path-of-directory>

i usually use this in sh scripts

SCRIPTSRC=`readlink -f "$0" || echo "$0"`
RUN_PATH=`dirname "${SCRIPTSRC}" || echo .`
echo "Running from ${RUN_PATH}"
...
cd ${RUN_PATH}/subfolder

you can use this to automate things ...

Surprisingly, no one mentioned this alternative that uses only built-in bash commands:

i="$IFS";IFS='/';set -f;p=($PWD);set +f;IFS="$i";echo "${p[-1]}"

As an added bonus you can easily obtain the name of the parent directory with:

[ "${#p[@]}" -gt 1 ] && echo "${p[-2]}"

These will work on Bash 4.3-alpha or newer.

You can use a combination of pwd and basename. E.g.

#!/bin/bash

CURRENT=`pwd`
BASENAME=`basename "$CURRENT"`

echo "$BASENAME"

exit;

$ echo "${PWD##*/}"

​​​​​

For the find jockeys out there like me:

find $PWD -maxdepth 0 -printf "%f\n"

The following commands will result in printing your current working directory in a bash script.

pushd .
CURRENT_DIR="`cd $1; pwd`"
popd
echo $CURRENT_DIR

I strongly prefer using gbasename, which is part of GNU coreutils.

I like the selected answer (Charles Duffy), but be careful if you are in a symlinked dir and you want the name of the target dir. Unfortunately I don't think it can be done in a single parameter expansion expression, perhaps I'm mistaken. This should work:

target_PWD=$(readlink -f .)
echo ${target_PWD##*/}

To see this, an experiment:

cd foo
ln -s . bar
echo ${PWD##*/}

reports "bar"

DIRNAME

To show the leading directories of a path (without incurring a fork-exec of /usr/bin/dirname):

echo ${target_PWD%/*}

This will e.g. transform foo/bar/baz -> foo/bar

Use:

basename "$PWD"

OR

IFS=/ 
var=($PWD)
echo ${var[-1]} 

Turn the Internal Filename Separator (IFS) back to space.

IFS= 

There is one space after the IFS.

This thread is great! Here is one more flavor:

pwd | awk -F / '{print $NF}'

Below grep with regex is also working,

>pwd | grep -o "\w*-*$"

How about grep:

pwd | grep -o '[^/]*$'

Just use:

pwd | xargs basename

or

basename "`pwd`"