Two decimal places using printf

Question

I m trying to write a number to two decimal places using printf   as follows    include  lt cstdio gt  int main       printf  When this number   d is assigned to 2 dp  it will be  2 f    94 9456  94 9456     return 0      When I run the program  I get the following output       printf When this number  -1243822529 is assigned to 2 db  it will be  2-0 000000   Why is that   Thanks

User · Answer

Use     2f  or variations on that   See the POSIX spec for an authoritative specification of the printf   format strings   Note that it separates POSIX extras from the core C99 specification   There are some C   sites which show up in a Google search  but some at least have a dubious reputation  judging from comments seen elsewhere on SO   Since you re coding in C    you should probably be avoiding printf   and its relatives

User · Answer

Try using a format like  d  02d   int iAmount   10050  printf  The number with fake decimal point is  d  02d   iAmount 100  iAmount 100     Another approach is to type cast it to double before printing it using  f like this   printf  The number with fake decimal point is  0 2f    double  iAmount  100     My 2 cents

User · Answer

For  d part refer to this How does this program work  and for decimal places use   2f

User · Answer

What you want is   2f  not 2 f   Also  you might want to replace your  d with a  f      include  lt cstdio gt  int main     printf  When this number   f is assigned to 2 dp  it will be    2f    94 9456  94 9456   return 0      This will output      When this number  94 945600 is assigned to 2 dp  it will be  94 95    See here for a full description of the printf formatting options  printf

[c++] Two decimal places using printf( )

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