printf prints whole array

Question

Let s assume I have the following code in my C program     include  lt stdio h gt   void PrintSomeMessage  char  p     int main int argc  char  argv          char arr 10     hello       PrintSomeMessage  amp arr 0        return 0        void PrintSomeMessage char  p        printf  p   s  p       Why the output of this would be the whole word  hello  instead of a single character  h    I understand  though  that if I put a   c  in the formatter  it will print just a single letter  But still  the memory address for each letter in this address is different  Please  someone explain it to me

User · Accepted Answer

But still  the memory address for each letter in this address is different    Memory address is different but as its array of characters they are sequential  When you pass address of first element and use  s  printf will print all characters starting from given address until it finds   0

User · Answer

Incase of arrays  the base address  i e  address of the array  is the address of  the 1st element in the array  Also the array name acts as a pointer   Consider a row of houses  each is an element in the array   To identify the row  you only need the 1st house address You know each house is followed by the next  sequential  Getting the address of the 1st house  will also give you the address of the row   Incase of string literals character arrays defined at declaration   they are automatically appended by  0   printf prints using the format specifier and the address provided  Since  you use  s it prints from the 1st address  incrementing the pointer using arithmetic  until   0

[c] printf() prints whole array

Examples related to c

Examples related to arrays

Examples related to char

Examples related to printf