Format specifier 02x

Question

I have a simple program     include  lt stdio h gt  int main             long i   16843009          printf    02x  n   i       I am using  02x format specifier to get 2 char output  However  the output I am getting is   1010101    while I am expecting it to be  01010101

User · Answer

x is a format specifier that format and output the hex value  If you are providing int or long value  it will convert it to hex value    02x means if your provided value is less than two digits then 0 will be prepended   You provided value 16843009 and it has been converted to 1010101 which a hex value

User · Answer

Your string is wider than your format width of 2  So there s no padding to be done

User · Answer

You are actually getting the correct value out   The way your x86  compatible  processor stores data like this  is in Little Endian order  meaning that  the MSB is last in your output   So  given your output      10101010   the last two hex values 10 are the Most Significant Byte  2 hex digits   1 byte   8 bits  for  possibly unnecessary  clarification    So  by reversing the memory storage order of the bytes  your value is actually   01010101   Hope that clears it up

User · Answer

02x means print at least 2 digits  prepend it with 0 s if there s less  In your case it s 7 digits  so you get no extra 0 in front   Also   x is for int  but you have a long  Try  08lx instead

[c] Format specifier %02x

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