How to printf unsigned long in C

Question

I can never understand how to print unsigned long datatype in C   Suppose unsigned foo is an unsigned long  then I try    printf   lu n   unsigned foo  printf   du n   unsigned foo  printf   ud n   unsigned foo  printf   ll n   unsigned foo  printf   ld n   unsigned foo  printf   dl n   unsigned foo    And all of them print some kind of -123123123 number instead of unsigned long that I have

User · Answer

The correct specifier for unsigned long is %lu.

If you are not getting the exact value you are expecting then there may be some problems in your code.

Please copy your code here. Then maybe someone can tell you better what the problem is.

User · Answer

int main         unsigned long long d      scanf   llu   amp d       printf   llu  d       getch        This will be helpful

User · Answer

lu is the correct format for unsigned long  Sounds like there are other issues at play here  such as memory corruption or an uninitialized variable  Perhaps show us a larger picture

User · Answer

lu for unsigned long  llu for unsigned long long

User · Answer

The format is  lu    Please check about the various other datatypes and their usage in printf here

User · Answer

Out of all the combinations you tried   ld and  lu are the only ones which are valid printf format specifiers at all   lu  long unsigned decimal    lx or  lX  long hex with lowercase or uppercase letters   and  lo  long octal  are the only valid format specifiers for a variable of type unsigned long  of course you can add field width  precision  etc modifiers between the   and the l

User · Answer

For int  d  For long int  ld  For long long int  lld   For unsigned long long int  llu

[c] How to printf "unsigned long" in C?

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