A long bigger than Long MAX VALUE

Question

How can I get a long number bigger than Long MAX VALUE   I want this method to return true   boolean isBiggerThanMaxLong long val        return  val  gt  Long MAX VALUE

User · Answer

You can t  If you have a method called isBiggerThanMaxLong long  it should always return false   If you were to increment the bits of Long MAX VALUE  the next value should be Long MIN VALUE  Read up on twos-complement and that should tell you why

User · Answer

Firstly  the below method doesn t compile as it is missing the return type and it should be Long MAX VALUE in place of Long Max value   public static boolean isBiggerThanMaxLong long value          return value  gt  Long Max value      The above method can never return  true as you are comparing a long value with Long MAX VALUE   see the method signature you can pass only long there Any long can be as big as the Long MAX VALUE  it can t be bigger than that   You can try something like this with BigInteger class    public static boolean isBiggerThanMaxLong BigInteger l       return l compareTo BigInteger valueOf Long MAX VALUE    1 true false      The below code will return true    BigInteger big3   BigInteger valueOf Long MAX VALUE                     add BigInteger valueOf Long MAX VALUE    System out println isBiggerThanMaxLong big3       prints true

User · Answer

That method can t return true   That s the point of Long MAX VALUE   It would be really confusing if its name were     false   Then it should be just called Long SOME FAIRLY LARGE VALUE and have literally zero reasonable uses   Just use Android s isUserAGoat  or you may roll your own function that always returns false   Note that a long in memory takes a fixed number of bytes   From Oracle      long  The long data type is a 64-bit signed two s complement integer  It has a minimum value of -9 223 372 036 854 775 808 and a maximum value of 9 223 372 036 854 775 807  inclusive   Use this data type when you need a range of values wider than those provided by int    As you may know from basic computer science or discrete math  there are 2 64 possible values for a long  since it is 64 bits   And as you know from discrete math or number theory or common sense  if there s only finitely many possibilities  one of them has to be the largest   That would be Long MAX VALUE   So you are asking something similar to  is there an integer that s  0 and  lt  1    Mathematically nonsensical   If you actually need this for something for real then use BigInteger class

User · Answer

If triangle lborderA is indeed a long then the test in the original code is trivially true  and there is no way to test it  It is also useless   However  if triangle lborderA is a double  the comparison is useful and can be tested  isBiggerThanMaxLong 1e300  does return true     public static boolean isBiggerThanMaxLong double in       return in  gt  Long MAX VALUE

[java] A long bigger than Long.MAX_VALUE

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