$number=1200.0000;
str_replace('.00', '',number_format($number, 2, '.', ''));
Output will be: 1200
You should cast your numbers as floats, which will do this for you.
$string = "42.422005000000000000000000000000";
echo (float)$string;
Output of this will be what you are looking for.
42.422005
Simply adding +
to your string variable will cause typecast to (float) and removes zeros:
var_dump(+'125.00'); // double(125)
var_dump(+'966.70'); // double(966.7)
var_dump(+'844.011'); // double(844.011)
var_dump(+'844.011asdf');// double(844.011)
$value = preg_replace('~\.0+$~','',$value);
Complicated way but works:
$num = '125.0100';
$index = $num[strlen($num)-1];
$i = strlen($num)-1;
while($index == '0') {
if ($num[$i] == '0') {
$num[$i] = '';
$i--;
}
$index = $num[$i];
}
//remove dot if no numbers exist after dot
$explode = explode('.', $num);
if (isset($explode[1]) && intval($explode[1]) <= 0) {
$num = intval($explode[0]);
}
echo $num; //125.01
the solutions above are the optimal way but in case you want to have your own you could use this. What this algorithm does it starts at the end of string and checks if its 0, if it is it sets to empty string and then goes to the next character from back untill the last character is > 0
The following is much simpler
if(floor($num) == $num) {
echo number_format($num);
} else {
echo $num;
}
Strange, when I get a number out of database with a "float" type and if my number is ex. 10000 when I floatval it, it becomes 1.
$number = $ad['price_month']; // 1000 from the database with a float type
echo floatval($number);
Result : 1
I've tested all the solutions above but didn't work.
This is my solution. I want to keep ability to add thousands separator
$precision = 5;
$number = round($number, $precision);
$decimals = strlen(substr(strrchr($number, '.'), 1));
return number_format($number, $precision, '.', ',');
you could just use the floatval
function
echo floatval('125.00');
// 125
echo floatval('966.70');
// 966.7
echo floatval('844.011');
// 844.011
Ultimate Solution: The only safe way is to use regex:
echo preg_replace("/\.?0+$/", "", 3.0); // 3
echo preg_replace("/\d+\.?\d*(\.?0+)/", "", 3.0); // 3
it will work for any case
You can use:
print (floatval)(number_format( $Value), 2 ) );
For everyone coming to this site having the same problem with commata instead, change:
$num = number_format($value, 1, ',', '');
to:
$num = str_replace(',0', '', number_format($value, 1, ',', '')); // e.g. 100,0 becomes 100
If there are two zeros to be removed, then change to:
$num = str_replace(',00', '', number_format($value, 2, ',', '')); // e.g. 100,00 becomes 100
Due to this question is old. First, I'm sorry about this.
The question is about number xxx.xx but in case that it is x,xxx.xxxxx or difference decimal separator such as xxxx,xxxx this can be harder to find and remove zero digits from decimal value.
/**
* Remove zero digits from decimal value.
*
* @param string|int|float $number The number can be any format, any where use in the world such as 123, 1,234.56, 1234.56789, 12.345,67, -98,765.43
* @param string The decimal separator. You have to set this parameter to exactly what it is. For example: in Europe it is mostly use "," instead of ".".
* @return string Return removed zero digits from decimal value.
*/
function removeZeroDigitsFromDecimal($number, $decimal_sep = '.')
{
$explode_num = explode($decimal_sep, $number);
if (is_array($explode_num) && isset($explode_num[count($explode_num)-1]) && intval($explode_num[count($explode_num)-1]) === 0) {
unset($explode_num[count($explode_num)-1]);
$number = implode($decimal_sep, $explode_num);
}
unset($explode_num);
return (string) $number;
}
And here is the code for test.
$numbers = [
1234,// 1234
-1234,// -1234
'12,345.67890',// 12,345.67890
'-12,345,678.901234',// -12,345,678.901234
'12345.000000',// 12345
'-12345.000000',// -12345
'12,345.000000',// 12,345
'-12,345.000000000',// -12,345
];
foreach ($numbers as $number) {
var_dump(removeZeroDigitsFromDecimal($number));
}
echo '<hr>'."\n\n\n";
$numbers = [
1234,// 12324
-1234,// -1234
'12.345,67890',// 12.345,67890
'-12.345.678,901234',// -12.345.678,901234
'12345,000000',// 12345
'-12345,000000',// -12345
'12.345,000000',// 12.345
'-12.345,000000000',// -12.345
'-12.345,000000,000',// -12.345,000000 STRANGE!! but also work.
];
foreach ($numbers as $number) {
var_dump(removeZeroDigitsFromDecimal($number, ','));
}
If you want to remove the zero digits just before to display on the page or template.
You can use the sprintf() function
sprintf('%g','125.00');
//125
??sprintf('%g','966.70');
//966.7
????sprintf('%g',844.011);
//844.011
I found this solution is the best:
public function priceFormat(float $price): string
{
//https://stackoverflow.com/a/14531760/5884988
$price = $price + 0;
$split = explode('.', $price);
return number_format($price, isset($split[1]) ? strlen($split[1]) : 2, ',', '.');
}
Thats my small solution... Can included to a class and set vars
private $dsepparator = '.'; // decimals private $tsepparator= ','; // thousand
That can be set by constructor and change to users lang.
class foo
{
private $dsepparator;
private $tsepparator;
function __construct(){
$langDatas = ['en' => ['dsepparator' => '.', 'tsepparator' => ','], 'de' => ['dsepparator' => ',', 'tsepparator' => '.']];
$usersLang = 'de'; // set iso code of lang from user
$this->dsepparator = $langDatas[$usersLang]['dsepparator'];
$this->tsepparator = $langDatas[$usersLang]['tsepparator'];
}
public function numberOmat($amount, $decimals = 2, $hideByZero = false)
{
return ( $hideByZero === true AND ($amount-floor($amount)) <= 0 ) ? number_format($amount, 0, $this->dsepparator, $this->tsepparator) : number_format($amount, $decimals, $this->dsepparator, $this->tsepparator);
}
/*
* $bar = new foo();
* $bar->numberOmat('5.1234', 2, true); // returns: 5,12
* $bar->numberOmat('5', 2); // returns: 5,00
* $bar->numberOmat('5.00', 2, true); // returns: 5
*/
}
This is a simple one line function using rtrim, save separator and decimal point :
function myFormat($num,$dec)
{
return rtrim(rtrim(number_format($num,$dec),'0'),'.');
}
$x = '100.10';
$x = preg_replace("/\.?0*$/",'',$x);
echo $x;
There is nothing that can't be fixed with a simple regex ;)
This is what I use:
function TrimTrailingZeroes($nbr) {
return strpos($nbr,'.')!==false ? rtrim(rtrim($nbr,'0'),'.') : $nbr;
}
N.B. This assumes .
is the decimal separator. It has the advantage that it will work on arbitrarily large (or small) numbers since there is no float cast. It also won't turn numbers into scientific notation (e.g. 1.0E-17).
You can try the following:
rtrim(number_format($coin->current_price,6),'0.')
Be careful with adding +0.
echo number_format(1500.00, 2,".",",")+0;
//1
Result of this is 1.
echo floatval('1,000.00');
// 1
echo floatval('1000.00');
//1000
$str = 15.00;
$str2 = 14.70;
echo rtrim(rtrim(strval($str), "0"), "."); //15
echo rtrim(rtrim(strval($str2), "0"), "."); //14.7
Typecast to a float
.
$int = 4.324000;
$int = (float) $int;
Simple and accurate!
function cleanNumber($num){
$explode = explode('.', $num);
$count = strlen(rtrim($explode[1],'0'));
return bcmul("$num",'1', $count);
}
Source: Stackoverflow.com