Converting Decimal to Binary Java

Question

I am trying to convert decimal to binary numbers from the user s input using Java    I m getting errors   package reversedBinary  import java util Scanner   public class ReversedBinary     public static void main String   args        int number        Scanner in   new Scanner System in        System out println  Enter a positive integer        number in nextInt         if  number  lt 0          System out println  Error  Not a positive integer        else             System out print  Convert to binary is             System out print binaryform number          private static Object binaryform int number        int remainder       if  number  lt  1            System out print number               remainder  number  2       binaryform number  gt  gt 1       System out print remainder               return null          How do I convert Decimal to Binary in Java

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Well  you can use while loop  like this   import java util Scanner   public class DecimalToBinaryExample       public static void main String   args                int num          int a   0          Scanner sc   new Scanner System in           System out println  Please enter a decimal number               num   sc nextInt            int binary     new int 100            while num    0                        binary a    num   2              num   num   2              a                       System out println  The binary value is               for int b   a - 1  b  gt   0  b--                        System out println      binary b                      sc close              You can refer example below for some good explanation   convert decimal to binary example

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public static String convertToBinary int dec        String str           while dec  0                str    Integer toString dec 2           dec    2            return new StringBuffer str  reverse   toString

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The following converts decimal to Binary with Time Complexity   O n  Linear Time and with out any java inbuilt function  private static int decimalToBinary int N        StringBuilder builder   new StringBuilder        int base   2      while  N    0            int reminder   N   base          builder append reminder           N   N   base             return Integer parseInt builder reverse   toString

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converting decimal to binary        param n the number     private static void toBinary int n        if  n    0            return    end of recursion       else           toBinary n   2           System out print n   2                   converting decimal to binary string        param n the number     return the binary string of n     private static String toBinaryString int n        Stack lt Integer gt  bits   new Stack lt  gt         do           bits push n   2           n    2        while  n    0        StringBuilder builder   new StringBuilder        while   bits isEmpty              builder append bits pop               return builder toString        Or you can use Integer toString int i  int radix   e g  Convert 12 to binary   Integer toString 12  2

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All your problems can be solved with a one-liner   To incorporate my solution into your project  simply remove your binaryform int number  method  and replace System out print binaryform number    with System out println Integer toBinaryString number

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I just solved this myself  and I wanted to share my answer because it includes the binary reversal and then conversion to decimal   I m not a very experienced coder but hopefully this will be helpful to someone else   What I did was push the binary data onto a stack as I was converting it  and then popped it off to reverse it and convert it back to decimal   import java util Scanner  import java util Stack   public class ReversedBinary        private Stack lt Integer gt  st       public ReversedBinary                 st   new Stack lt  gt                private int decimaltoBinary int dec                if dec    0    dec    1                        st push dec   2               return dec                     st push dec   2            dec   decimaltoBinary dec   2                    return dec             private int reversedtoDecimal                 int revDec   st pop            int i   1           while  st isEmpty                          revDec    st pop     Math pow 2  i                        return revDec             public static void main String   args                ReversedBinary rev   new ReversedBinary             System out println  Please enter a positive integer              Scanner sc   new Scanner System in           while sc hasNextLine                          int input   Integer parseInt sc nextLine                 if input  lt  1    input  gt  1000000000                                System out println  Integer must be between 1 and 1000000000                               else                               rev decimaltoBinary input                   System out println  Binary to reversed  converted to decimal      rev reversedtoDecimal

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public static void main String   args        Scanner in  new Scanner System in       System out print  Put a number           int a in nextInt        StringBuffer b new StringBuffer        while a gt  1              if a 2  0                  b append 1                  else if a 2  0                   b append 0                 a   2            System out println b reverse

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If you want to reverse the calculated binary form   you can use the StringBuffer class and simply use the reverse   method   Here is a sample program that will explain its use and calculate the binary public class Binary        public StringBuffer calculateBinary int number            StringBuffer sBuf   new StringBuffer            int temp   0          while  number  gt  0                temp   number   2              sBuf append temp               number   number   2                    return sBuf reverse              public class Main        public static void main String   args  throws IOException           System out println  quot enter the number you want to convert quot            BufferedReader bReader   new BufferedReader newInputStreamReader System in            int number   Integer parseInt bReader readLine              Binary binaryObject   new Binary            StringBuffer result   binaryObject calculateBinary number           System out println result

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int n   13      String binary              decimal to binary     while  n  gt  0            int d   n  amp  1          binary   d   binary          n   n  gt  gt  1            System out println binary          binary to decimal     int power   1      n   0      for  int i   binary length   - 1  i  gt   0  i--            n   n   Character getNumericValue binary charAt i     power          power   power   2             System out println n

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Binary to Decimal without using Integer ParseInt     import java util Scanner     convert binary to decimal number in java without using Integer parseInt   method   public class BinaryToDecimalWithOutParseInt        public static void main String   args             Scanner input   new Scanner  System in            System out println  Enter a binary number               int  binarynum  input nextInt            int binary binarynum           int decimal   0          int power   0           while true                if binary    0                    break                 else                    int temp   binary 10                  decimal    temp Math pow 2  power                   binary   binary 10                  power                                     System out println  Binary   binarynum   Decimal   decimal                Output   Enter a binary number    1010  Binary 1010 Decimal 10    Binary to Decimal using Integer parseInt     import java util Scanner     convert binary to decimal number in java using Integer parseInt   method  public class BinaryToDecimalWithParseInt        public static void main String   args             Scanner input   new Scanner  System in             System out println  Enter a binary number              String binaryString  input nextLine             System out println  Result    Integer parseInt binaryString 2                Output   Enter a binary number    1010  Result  10

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No need of any java in-built functions  Simple recursion will do   public class DecimaltoBinaryTest        public static void main String   args            DecimaltoBinary decimaltoBinary   new DecimaltoBinary            System out println  hello     decimaltoBinary convertToBinary 1000 0              class DecimaltoBinary        public DecimaltoBinary                public int convertToBinary int num int binary            if  num    0    num    1                return num                     binary   convertToBinary num   2  binary           binary   binary   10    num   2           return binary

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converts decimal to binary string String convertToBinary int decimalNumber         String binary         while decimalNumber gt 0           int remainder decimalNumber 2            line below ensures the remainders are reversed         binary remainder binary          decimalNumber decimalNumber 2            return binary

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Integer toString n 8     decimal to octal  Integer toString n 2     decimal to binary  Integer toString n 16    decimal to Hex   where n   decimal number

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A rather simple than efficient program  yet it does the job           Scanner sc   new Scanner System in           System out println  Give me my binaries            int str   sc nextInt 2           System out println str

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Practically you can write it as a recursive function  Each function call returns their results and add to the tail of the previous result  It is possible to write this method by using java as simple as you can find below  public class Solution        private static String convertDecimalToBinary int n            String output    quot  quot           if  n  gt   1                output   convertDecimalToBinary n  gt  gt  1     n   2                      return output             public static void main String   args            int num   125          String binaryStr   convertDecimalToBinary num            System out println binaryStr             Let us take a look how is the above recursion working   After calling convertDecimalToBinary method once  it calls itself till the value of the number will be lesser than 1 and return all of the concatenated results to the place where it called first  References  Java - Bitwise and Bit Shift Operators https   docs oracle com javase tutorial java nutsandbolts op3 html

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In C    but it s just the same as in Java     public static void findOnes2 int num        int count   0          count 1 s      String snum            final binary representation     int rem   0            remainder      while  num    0                rem   num   2               grab remainder         snum    rem ToString        build the binary rep         num   num   2          if  rem    1                check if we have a 1              count                   if so add 1 to the count            char   arr   snum ToCharArray        Array Reverse arr       String snum2   new string arr       Console WriteLine  Reporting            Console WriteLine  The binary representation      snum2       Console WriteLine  The number of 1 s is      count      public static void Main         findOnes2 10

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import java util     public class BinaryNumber        public static void main String   args                Scanner scan   new Scanner System in           System out println  Enter the number            int n   scan nextInt            int rem          int num  n           String str             while num gt 0                        rem   num 2              str   rem   str              num num 2                    System out println  the bunary number for   n   is     str

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Here is the conversion of Decimal to Binary in three different ways   import java util Scanner  public static Scanner scan   new Scanner System in        public static void conversionLogical int ip                         My Method One          String str             do              str ip 2 str              ip ip 2            while ip  1           System out print 1 str              public static void byMethod int ip                               Online Method           Integer ii new Integer ip           System out print Integer toBinaryString ip              public static String recursion int ip                           Using My Recursion          if ip  1              return  1           return  DecToBin recursion ip 2   ip 2                 public static void main String   args                  Main Method          int ip                   System out println  Enter Positive Integer            ip   scan nextInt             System out print   nResult 1                 DecToBin conversionLogical ip           System out print   nResult 2               DecToBin byMethod ip           System out println   nResult 3     DecToBin recursion ip

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param no                 Decimal no     return binary as integer array     public int   convertBinary int no        int i   0  temp     new int 7       int binary        while  no  gt  0            temp i      no   2          no    2            binary   new int i       int k   0      for  int j   i - 1  j  gt   0  j--            binary k      temp j              return binary

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Even better with StringBuilder using insert   in front of the decimal string under construction  without calling reverse      static String toBinary int n        if  n    0            return  0              StringBuilder bldr   new StringBuilder        while  n  gt  0            bldr   bldr insert 0  n   2           n   n   2             return bldr toString

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Your binaryForm method is getting caught in an infinite recursion  you need to return if number  lt   1   import java util Scanner   public class ReversedBinary        public static void main String   args            int number           Scanner in   new Scanner System in            System out println  Enter a positive integer            number   in nextInt             if  number  lt  0                System out println  Error  Not a positive integer              else                System out print  Convert to binary is                   System out print binaryform number                printBinaryform number                        private static void printBinaryform int number            int remainder           if  number  lt   1                System out print number               return     KICK OUT OF THE RECURSION                    remainder   number   2          printBinaryform number  gt  gt  1           System out print remainder

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I just want to add  for anyone who uses       String x Integer toBinaryString     to get a String of Binary numbers and wants to convert that string into an int  If you use     int y Integer parseInt x    you will get a NumberFormatException error   What I did to convert String x to Integers  was first converted each individual Char in the String x to a single Char in a for loop      char t    x charAt z      I then converted each Char back into an individual String      String u String valueOf t     then Parsed each String into an Integer    Id figure Id post this  because I took me a while to figure out how to get a binary such as 01010101 into Integer form

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One of the fastest solutions   public static long getBinary int n                long res 0          int t 0          while n gt 1                        t   int   Math log n  Math log 2                res   res  long  Math pow 10  t                n- Math pow 2  t                     return res

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It might seem silly   but if u wanna try utility function   System out println Integer parseInt  Integer toString i 2        there must be some  utility method to do it directly  I cant remember

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public static void main String h          Scanner sc new Scanner System in       int decimal sc nextInt         String binary          if decimal lt  0                System out println  Please Enter more than 0               else               while decimal gt 0                         binary  decimal 2  binary              decimal decimal 2                     System out println  binary is   binary

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public class BinaryConvert        public static void main String   args           System out println  Binary Result     doBin 45               static String doBin int n           int b   2          String r               String c                do              c     n   b               n    b                    while n    0            for int i    c length   - 1   i  gt  0  i--               r    c charAt i                      return r

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This is a very basic procedure  I got this after putting a general procedure on paper   import java util Scanner       public class DecimalToBinary            public static void main String   args                Scanner input   new Scanner System in               System out println  Enter a Number                 int number   input nextInt                while number  0                                if number 2  0                                         number  2                      System out print 0    Example  10 2   5     - gt  0                                   else if number 2  1                                         number  2                      System out print 1     5 2   2              - gt  1                                   else if number  2                                        number  2                      System out print 01     2 2   0             - gt  01   - gt 0101

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Integer toBinaryString   is an in-built method and will do quite well

[java] Converting Decimal to Binary Java

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