XSLT string replace

Question

I don t really know XSL but I need to fix this code  I have reduced it to make it simpler  I am getting this error      Invalid XSLT XPath function   on this line   lt xsl variable name  text  select  replace  text  a   b     gt    This is the XSL   lt xsl stylesheet xmlns xsl  http   www w3 org 1999 XSL Transform      xmlns inm  http   www inmagic com webpublisher query  version  1 0  gt       lt xsl output method  text  encoding  UTF-8    gt        lt xsl preserve-space elements       gt       lt xsl template match  text      gt        lt xsl template match  mos  gt           lt xsl apply-templates   gt            lt xsl for-each select  mosObj  gt             Notes or subject               lt xsl call-template                 name  rem-html  gt                   lt xsl with-param name  text  select  SBS ABSTRACT    gt               lt  xsl call-template gt           lt  xsl for-each gt       lt  xsl template gt        lt xsl template name  rem-html  gt           lt xsl param name  text    gt           lt xsl variable name  text  select  replace  text   a    b      gt       lt  xsl template gt   lt  xsl stylesheet gt    Can anyone tell me what s wrong with it

User · Answer

The rouine is pretty good  however it causes my app to hang  so I needed to add the case      lt xsl when test   text      or  replace     or not  replace    gt       lt xsl value-of select   text    gt       lt  -- Prevent thsi routine from hanging -- gt     lt  xsl when gt    before the function gets called recursively   I got the answer from here  When test hanging in an infinite loop  Thank you

User · Answer

Here is the XSLT function which will work similar to the String Replace   function of C    This template has the 3 Parameters as below  text  - your main string  replace  - the string which you want to replace  by  - the string which will reply by new string  Below are the Template    lt xsl template name  string-replace-all  gt     lt xsl param name  text    gt     lt xsl param name  replace    gt     lt xsl param name  by    gt     lt xsl choose gt       lt xsl when test  contains  text   replace   gt         lt xsl value-of select  substring-before  text  replace     gt         lt xsl value-of select   by    gt         lt xsl call-template name  string-replace-all  gt           lt xsl with-param name  text  select  substring-after  text  replace     gt           lt xsl with-param name  replace  select   replace    gt           lt xsl with-param name  by  select   by    gt         lt  xsl call-template gt       lt  xsl when gt       lt xsl otherwise gt         lt xsl value-of select   text    gt       lt  xsl otherwise gt     lt  xsl choose gt   lt  xsl template gt    Below sample shows how to call it   lt xsl variable name  myVariable   gt     lt xsl call-template name  string-replace-all  gt       lt xsl with-param name  text  select   This is a  old  text     gt       lt xsl with-param name  replace  select    old      gt       lt xsl with-param name  by  select   New     gt     lt  xsl call-template gt   lt  xsl variable gt    You can also refer the below URL for the details

User · Answer

You can use the following code when your processor runs on  NET or uses MSXML  as opposed to Java-based or other native processors   It uses msxsl script   Make sure to add the namespace xmlns msxsl  urn schemas-microsoft-com xslt  to your root xsl stylesheet or xsl transform element   In addition  bind outlet to any namespace you like  for instance xmlns outlet    http   my functions     lt msxsl script implements-prefix  outlet  language  javascript  gt  function replace str str text str replace str by         return str text replace str replace str by      lt  msxsl script gt     lt xsl variable name  newtext  select  outlet replace str string  oldstring   me   you      gt

User · Answer

replace isn t available for XSLT 1 0    Codesling has a template for string-replace you can use as a substitute for the function    lt xsl template name  string-replace-all  gt       lt xsl param name  text    gt       lt xsl param name  replace    gt       lt xsl param name  by    gt       lt xsl choose gt           lt xsl when test   text      or  replace     or not  replace    gt               lt  -- Prevent this routine from hanging -- gt               lt xsl value-of select   text    gt           lt  xsl when gt           lt xsl when test  contains  text   replace   gt               lt xsl value-of select  substring-before  text  replace     gt               lt xsl value-of select   by    gt               lt xsl call-template name  string-replace-all  gt                   lt xsl with-param name  text  select  substring-after  text  replace     gt                   lt xsl with-param name  replace  select   replace    gt                   lt xsl with-param name  by  select   by    gt               lt  xsl call-template gt           lt  xsl when gt           lt xsl otherwise gt               lt xsl value-of select   text    gt           lt  xsl otherwise gt       lt  xsl choose gt   lt  xsl template gt    invoked as    lt xsl variable name  newtext  gt       lt xsl call-template name  string-replace-all  gt           lt xsl with-param name  text  select   text    gt           lt xsl with-param name  replace  select  a    gt           lt xsl with-param name  by  select  b    gt       lt  xsl call-template gt   lt  xsl variable gt    On the other hand  if you literally only need to replace one character with another  you can call translate which has a similar signature  Something like this should work fine    lt xsl variable name  newtext  select  translate  text  a   b     gt    Also  note  in this example  I changed the variable name to  newtext   in XSLT variables are immutable  so you can t do the equivalent of  foo    foo like you had in your original code

User · Answer

I keep hitting this answer  But none of them list the easiest solution for xsltproc  and probably most XSLT 1 0 processors     Add the exslt strings name to the stylesheet  i e      lt xsl stylesheet   version  1 0    xmlns str  http   exslt org strings    xmlns xsl  http   www w3 org 1999 XSL Transform  gt     Then use it like     lt xsl value-of select  str replace               gt

User · Answer

Note  In case you wish to use the already-mentioned algo for cases where you need to replace huge number of instances in the source string  e g  new lines in long text  there is high probability you ll end up with StackOverflowException because of the recursive call   I resolved this issue thanks to Xalan s  didn t look how to do it in Saxon  built-in Java type embedding    lt xsl stylesheet version  1 0  exclude-result-prefixes  xalan str                  xmlns xsl  http   www w3 org 1999 XSL Transform                  xmlns xalan  http   xml apache org xalan                  xmlns str  xalan   java lang String           gt       lt xsl value-of select  str replaceAll      str new text          search string       replace string    gt       lt  xsl stylesheet gt

[xslt] XSLT string replace

Examples related to xslt

Examples related to xpath

Examples related to replace

Examples related to xslt-1.0

Examples related to xpath-1.0