[xml] How do you add an image?

Situation:

I have a simple XML document that contains image information. I need to transform it into HTML. However, I can't see where the open tag is and when I use the XSL code below, it shows the following error message:

"Cannot write an attribute node when no element start tag is open."

XML content:

<root>
    <HeaderText>
        <HeaderText>Dan Testing</HeaderText>
    </HeaderText>
    <Image>
        <img width="100" height="100" alt="FPO lady" src="/uploadedImages/temp_photo_small.jpg"/>
    </Image>
    <BodyText>
        <p>This is a test of the body text<br  /></p>
    </BodyText>
    <ShowLinkArrow>false</ShowLinkArrow>
</root>

XSL code:

<xsl:stylesheet version="1.0" extension-element-prefixes="msxsl"
    exclude-result-prefixes="msxsl js dl" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    xmlns:js="urn:custom-javascript" xmlns:msxsl="urn:schemas-microsoft-com:xslt"
    xmlns:dl="urn:datalist">
    <xsl:output method="xml" version="1.0" omit-xml-declaration="yes" indent="yes" encoding="utf-8"/>
    <xsl:template match="/" xml:space="preserve">
        <img>
            <xsl:attribute name="width">
                100
            </xsl:attribute>
            <xsl:attribute name="height">
                100
            </xsl:attribute>
            <xsl:attribute name="class">
                CalloutRightPhoto
            </xsl:attribute>
            <xsl:attribute name="src">
                <xsl:copy-of select="/root/Image/node()"/>
            </xsl:attribute>
        </img>
    </xsl:template>
</xsl:stylesheet>

This question is related to xml xslt xslt-1.0

The answer is


Shouldn't that be:

<xsl:value-of select="/root/Image/img/@src"/>

? It looks like you are trying to copy the entire Image/img node to the attribute @src


In order to add attributes, XSL wants

<xsl:element name="img">
     (attributes)
</xsl:element>

instead of just

<img>
     (attributes)
</img>

Although, yes, if you're just copying the element as-is, you don't need any of that.


Never mind -- I'm an idiot. I just needed <xsl:value-of select="/root/Image/node()"/>


The other option to try is a straightforward

<img width="100" height="100" src="/root/Image/image.jpeg" class="CalloutRightPhoto"/>

i.e. without {} but instead giving the direct image path