[ios] Perform Segue programmatically and pass parameters to the destination view

in my app I've a button that performs a segue programmatically:

- (void)myButtonMethod
    //execute segue programmatically
    [self performSegueWithIdentifier: @"MySegue" sender: self];

I would like to know if there is a way to reference the destination view and to pass it some parameters.

I know that in prepareForSegue method, I can refer to it with:myDestinationViewController *vc = [segue destinationViewController];, but I don't know how to this executing the segue programmatically.

Do you have any ideas?

Thanks, yassa


I'm sorry for this question!!! I simply discovered that, even if the segue is invoked programmatically, the prepareForSegue method is called anyway and so it is possible to pass parameters in the same usual way.

This question is related to ios view parameters storyboard segue

The answer is

Swift 4:

override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
    if segue.identifier == "ExampleSegueIdentifier" {
        if let destinationVC = segue.destination as? ExampleSegueVC {
            destinationVC.exampleString = "Example"

Swift 3:

override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) {
        if segue.identifier == "ExampleSegueIdentifier" {
            if let destinationVC = segue.destinationViewController as? ExampleSegueVC {
                destinationVC.exampleString = "Example"

Old question but here's the code on how to do what you are asking. In this case I am passing data from a selected cell in a table view to another view controller.

in the .h file of the trget view:

@property(weak, nonatomic)  NSObject* dataModel;

in the .m file:

@synthesize dataModel;

dataModel can be string, int, or like in this case it's a model that contains many items

- (void)someMethod {
     [self performSegueWithIdentifier:@"loginMainSegue" sender:self];


- (void)someMethod {
    UIViewController *myController = [self.storyboard instantiateViewControllerWithIdentifier:@"HomeController"];
    [self.navigationController pushViewController: myController animated:YES];

- (void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender {
    if([segue.identifier isEqualToString:@"storyDetailsSegway"]) {
        UITableViewCell *cell = (UITableViewCell *) sender;
        NSIndexPath *indexPath = [self.tableView indexPathForCell:cell];
        NSDictionary *storiesDict =[topStories objectAtIndex:[indexPath row]];
        StoryModel *storyModel = [[StoryModel alloc] init];
        storyModel = storiesDict;
        StoryDetails *controller = (StoryDetails *)segue.destinationViewController;
        controller.dataModel= storyModel;

The answer is simply that it makes no difference how the segue is triggered.

The prepareForSegue:sender: method is called in any case and this is where you pass your parameters across.

I understand the problem of performing the segue at one place and maintaining the state to send parameters in prepare for segue.

I figured out a way to do this. I've added a property called userInfoDict to ViewControllers using a category. and I've override perform segue with identifier too, in such a way that If the sender is self(means the controller itself). It will pass this userInfoDict to the next ViewController.

Here instead of passing the whole UserInfoDict you can also pass the specific params, as sender and override accordingly.

1 thing you need to keep in mind. don't forget to call super method in ur performSegue method.

In case if you use new swift version.

override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
        if segue.identifier == "ChannelMoreSegue" {


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