What is the difference between dynamic and static polymorphism in Java

Question

Can anyone provide a simple example that explains the difference between Dynamic and Static polymorphism in Java

User · Answer

Method overloading would be an example of static polymorphism
whereas overriding would be an example of dynamic polymorphism.

Because, in case of overloading, at compile time the compiler knows which method to link to the call. However, it is determined at runtime for dynamic polymorphism

User · Answer

Dynamic  run time  polymorphism is the polymorphism existed at run-time  Here  Java compiler does not understand which method is called at compilation time  Only JVM decides which method is called at run-time  Method overloading and method overriding using instance methods are the examples for dynamic polymorphism   For example    Consider an application that serializes and de-serializes different types of documents  We can have    Document    as the base class and different document type classes deriving from it  E g  XMLDocument   WordDocument   etc  Document class will define     Serialize       and     De-serialize       methods as virtual and each derived class will implement these methods in its own way based on the actual contents of the documents  When different types of documents need to be serialized de-serialized  the document objects will be referred by the     Document     class reference  or pointer  and when the     Serialize       or     De-serialize       method are called on it  appropriate versions of the virtual methods are called    Static  compile time  polymorphism is the polymorphism exhibited at compile time  Here  Java compiler knows which method is called  Method overloading and method overriding using static methods  method overriding using private or final methods are examples for static polymorphism  For example    An employee object may have two print   methods one taking no arguments and one taking a prefix string to be displayed along with the employee data  Given these interfaces  when the print   method is called without any arguments  the compiler  looking at the function arguments knows which function is meant to be called and it generates the object code accordingly    For more details please read  What is Polymorphism   Google it

User · Answer

In simple terms      Static polymorphism   Same method name is overloaded with different  type  or number of parameters in same class  different signature   Targeted method call is resolved at compile time    Dynamic polymorphism   Same method is overridden with same signature in different classes  Type of object on which method is being invoked is not known at compile time but will be decided at run time   Generally overloading won t be considered as polymorphism    From java tutorial page       Subclasses of a class can define their own unique behaviors and yet share some of the same functionality of the parent class

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Polymorphism  Polymorphism is the ability of an object to take on many forms  The most common use of polymorphism in OOP occurs when a parent class reference is used to refer to a child class object   Dynamic Binding Runtime Polymorphism    Run time Polymorphism also known as method overriding  In this Mechanism by which a call to an overridden function is resolved at a Run-Time   public class DynamicBindingTest        public static void main String args              Vehicle vehicle   new Car      here Type is vehicle but object will be Car         vehicle start            Car s start called because start   is overridden method          class Vehicle        public void start             System out println  Inside start method of Vehicle             class Car extends Vehicle         Override     public void start             System out println  Inside start method of Car              Output   Inside start method of Car  Static Binding  compile-time polymorphism   Which method is to be called is decided at compile-time only   public class StaticBindingTest        public static void main String args              Collection c   new HashSet           StaticBindingTest et   new StaticBindingTest           et sort c                 overloaded method takes Collection argument     public Collection sort Collection c           System out println  Inside Collection sort method            return c               another overloaded method which takes HashSet argument which is sub class     public Collection sort HashSet hs           System out println  Inside HashSet sort method            return hs             Output  Inside Collection sort metho

User · Answer

Polymorphism  1  Static binding Compile-Time binding Early binding Method overloading  in same class   2  Dynamic binding Run-Time binding Late binding Method overriding  in different classes   overloading example   class Calculation       void sum int a int b  System out println a b        void sum int a int b int c  System out println a b c         public static void main String args            Calculation obj new Calculation          obj sum 10 10 10       30     obj sum 20 20         40              overriding example   class Animal          public void move          System out println  Animals can move            class Dog extends Animal       public void move           System out println  Dogs can walk and run            public class TestDog       public static void main String args            Animal a   new Animal       Animal reference and object       Animal b   new Dog       Animal reference but Dog object        a move     output  Animals can move        b move     output Dogs can walk and run

User · Answer

Method overloading is a compile time polymorphism  let s take an example to understand the concept   class Person                                              person java file       public static void main   String   args               Eat e   new Eat           e eat noodle                                    line 6           void eat  Noodles n         Noodles is a object    line 8                                    void eat   Pizza p              Pizza is a object               In this example  Person has a eat method which represents that he can either eat Pizza or Noodles  That the method eat is overloaded when we compile this Person java the compiler resolves the method call   e eat noodles   which is at line 6  with the method definition specified in line 8 that is it method which takes noodles as parameter and the entire process is done by Compiler so it is Compile time Polymorphism           The process of replacement of the method call with method definition is called as binding  in this case  it is done by the compiler so it is called as early binding

User · Answer

Following on from Naresh s answer  dynamic polymorphism is only  dynamic  in Java because of the presence of the virtual machine and its ability to interpret the code at run time rather than the code running natively    In C   it must be resolved at compile time if it is being compiled to a native binary using gcc  obviously  however  the runtime jump and thunk in the virtual table is still referred to as a  lookup  or  dynamic   If C inherits B  and you declare B  b   new C    b- gt method1     b will be resolved by the compiler to point to a B object inside C  for a simple class inherits a class situation  the B object inside C and C will start at the same memory address so nothing is required to be done  it will be pointing at the vptr that they both use   If C inherits B and A  the virtual function table of the A object inside C entry for method1 will have a thunk which will offset the pointer to the start of the encapsulating C object and then pass it to the real A  method1   in the text segment which C has overridden  For C  c   new C    c- gt method1    c will be pointing to the outer C object already and the pointer will be passed to C  method1   in the text segment  Refer to  http   www programmersought com article 2572545946   In java  for B b   new C    b method1     the virtual machine is able to dynamically check the type of the object paired with b and can pass the correct pointer and call the correct method  The extra step of the virtual machine eliminates the need for virtual function tables or the type being resolved at compile time  even when it could be known at compile time  It s just a different way of doing it which makes sense when a virtual machine is involved and code is only compiled to bytecode

User · Answer

Polymorphism refers to the ability of an object to behave differently for the same trigger   Static polymorphism  Compile-time Polymorphism    Static Polymorphism decides which method to execute during compile time  Method Overloading is an example of static polymorphism  and it is requred to happens static polymorphism  Static Polymorphism achieved through static binding  Static Polymorphism happens in the same class  Object assignment is not required for static polymorphism  Inheritance not involved for static polymorphism    Dynamic Polymorphism  Runtime Polymorphism    Dynamic Polymorphism decides which method to execute in runtime  Method Overriding is an example of dynamic polymorphism  and it is requred to happens dynamic polymorphism  Dynamic Polymorphism achieved through dynamic binding  Dynamic Polymorphism happens between different classes  It is required where a subclass object is assigned to super class object for dynamic polymorphism  Inheritance involved for dynamic polymorphism

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Method Overloading is known as Static Polymorphism and also Known as Compile Time Polymorphism or Static Binding because overloaded method calls get resolved at compile time by the compiler on the basis of the argument list and the reference on which we are calling the method   And Method Overriding is known as Dynamic Polymorphism or simple Polymorphism or Runtime Method Dispatch or Dynamic Binding because overridden method call get resolved at runtime   In order to understand why this is so let s take an example of Mammal and Human class  class Mammal       public void speak     System out println  ohlllalalalalalaoaoaoa         class Human extends Mammal         Override     public void speak     System out println  Hello           public void speak String language            if  language equals  Hindi    System out println  Namaste            else System out println  Hello               I have included output as well as bytecode of in below lines of code  Mammal anyMammal   new Mammal    anyMammal speak        Output - ohlllalalalalalaoaoaoa    10  invokevirtual  4    Method org programming mitra exercises OverridingInternalExample Mammal speak   V  Mammal humanMammal   new Human    humanMammal speak       Output - Hello    23  invokevirtual  4    Method org programming mitra exercises OverridingInternalExample Mammal speak   V  Human human   new Human    human speak       Output - Hello    36  invokevirtual  7    Method org programming mitra exercises OverridingInternalExample Human speak   V  human speak  Hindi       Output - Namaste    42  invokevirtual  9    Method org programming mitra exercises OverridingInternalExample Human speak  Ljava lang String  V   And by looking at above code we can see that the bytecodes of humanMammal speak     human speak   and human speak  Hindi   are totally different because the compiler is able to differentiate between them based on the argument list and class reference  And this is why Method Overloading is known as Static Polymorphism   But bytecode for anyMammal speak   and humanMammal speak   is same because according to compiler both methods are called on Mammal reference but the output for both method calls is different because at runtime JVM knows what object a reference is holding and JVM calls the method on the object and this is why Method Overriding is known as Dynamic Polymorphism   So from above code and bytecode  it is clear that during compilation phase calling method is considered from the reference type  But at execution time method will be called from the object which the reference is holding   If you want to know more about this you can read more on How Does JVM Handle Method Overloading and Overriding Internally

User · Answer

Consider the code below   public class X       public void methodA      Base class method               System out println   hello  I m methodA of class X             public class Y extends X       public void methodA      Derived Class method               System out println   hello  I m methodA of class Y            public class Z   public static void main  String args              this takes input from the user during runtime     System out println  Enter x or y        Scanner scanner   new Scanner System in       String value  scanner nextLine         X obj1   null      if value equals  x            obj1   new X       Reference and object X     else if value equals  y            obj2   new Y       X reference but Y object     else         System out println  Invalid param value         obj1 methodA          Now  looking at the code you can never tell which implementation of methodA   will be executed  Because it depends on what value the user gives during runtime  So  it is only decided during the runtime as to which method will be called  Hence  Runtime polymorphism

User · Answer

method overloading is an example of compile time static polymorphism because method binding between method call and method definition happens at compile time and it depends on the reference of the class  reference created at compile time and goes to stack    method overriding is an example of run time dynamic polymorphism because method binding between method call and method definition happens at run time and it depends on the object of the class  object created at runtime and goes to the heap

User · Answer

Compile time polymorphism Static Binding Early Binding   In static polymorphism  if we call a method in our code then which definition of that method is to be called actually is resolved at compile time only    or   At compile time  Java knows which method to invoke by checking the method signatures   So  this is called compile-time polymorphism or static binding   Dynamic Polymorphism Late Binding  Runtime Polymorphism   At run time  Java waits until runtime to determine which object is actually being pointed to by the reference  Method resolution was taken at runtime  due to that we call as run time polymorphism

User · Answer

Static Polymorphism   is where the decision to resolve which method to accomplish  is determined during the compile time  Method Overloading could be an example of this   Dynamic Polymorphism   is where the decision to choose which method to execute  is set during the run-time  Method Overriding could be an example of this

User · Answer

Binding refers to the link between method call and method definition    This picture clearly shows what is binding     In this picture     a1 methodOne      call is binding to corresponding methodOne   definition and    a1 methodTwo      call is binding to corresponding methodTwo   definition   For every method call there should be proper method definition  This is a rule in java  If compiler does not see the proper method definition for every method call  it throws error   Now  come to static binding and dynamic binding in java   Static Binding In Java       Static binding is a binding which happens during compilation  It is   also called early binding because binding happens before a program   actually runs      Static binding can be demonstrated like in the below picture     In this picture     a1    is a reference variable of type Class A pointing to object of class A      a2    is also reference variable of type class A but pointing to object of Class B   During compilation  while binding  compiler does not check the type of object to which a particular reference variable is pointing  It just checks the type of reference variable through which a method is called and checks whether there exist a method definition for it in that type   For example  for    a1 method      method call in the above picture  compiler checks whether there exist method definition for method   in Class A  Because    a1  is Class A type  Similarly  for    a2 method      method call  it checks whether there exist method definition for method   in Class A  Because    a2  is also Class A type  It does not check to which object     a1    and    a2    are pointing  This type of binding is called static binding   Dynamic Binding In Java       Dynamic binding is a binding which happens during run time  It is also   called late binding because binding happens when program actually is   running    During run time actual objects are used for binding  For example  for    a1 method      call in the above picture  method   of actual object to which    a1    is pointing will be called  For    a2 method      call  method   of actual object to which    a2    is pointing will be called  This type of binding is called dynamic binding   The dynamic binding of above example can be demonstrated like below     Reference static-binding-and-dynamic-binding-in-java

[java] What is the difference between dynamic and static polymorphism in Java?

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