[oop] Call an overridden method from super class in typescript

If you want a super class to call a function from a subclass, the cleanest way is to define an abstract pattern, in this manner you explicitly know the method exists somewhere and must be overridden by a subclass.

This is as an example, normally you do not call a sub method within the constructor as the sub instance is not initialized yet… (reason why you have an "undefined" in your question's example)

abstract class A {
    // The abstract method the subclass will have to call
    protected abstract doStuff():void;

    constructor(){
     alert("Super class A constructed, calling now 'doStuff'")
     this.doStuff();
    }
}

class B extends A{

    // Define here the abstract method
    protected doStuff()
    {
        alert("Submethod called");
    }
}

var b = new B();

Test it Here

And if like @Max you really want to avoid implementing the abstract method everywhere, just get rid of it. I don't recommend this approach because you might forget you are overriding the method.

abstract class A {
    constructor() {
        alert("Super class A constructed, calling now 'doStuff'")
        this.doStuff();
    }

    // The fallback method the subclass will call if not overridden
    protected doStuff(): void {
        alert("Default doStuff");
    };
}

class B extends A {
    // Override doStuff()
    protected doStuff() {
        alert("Submethod called");
    }
}

class C extends A {
    // No doStuff() overriding, fallback on A.doStuff()
}

var b = new B();
var c = new C();

Try it Here