Swift - Remove character from string

Question

I have a string which is  Optional  5      I need to remove the    surrounding the 5   I have removed the  Optional  by doing   text2   text2 stringByReplacingOccurrencesOfString  Optional    withString      options  NSStringCompareOptions LiteralSearch  range  nil    I am having difficulties removing the   characters as they designate the end of a string in the code

User · Accepted Answer

Swift uses backslash to escape double quotes. Here is the list of escaped special characters in Swift:

\0 (null character)

\\ (backslash)

\t (horizontal tab)

\n (line feed)

\r (carriage return)

\" (double quote)

\' (single quote)

This should work:

text2 = text2.replacingOccurrences(of: "\\", with: "", options: NSString.CompareOptions.literal, range: nil)

User · Answer

Let s say you have a string   var string    potatoes   carrots    And you want to replace the word  potatoes  in that string with  tomatoes   string   string replacingOccurrences of   potatoes   with   tomatoes   options  NSString CompareOptions literal  range  nil    If you print your string  it will now be   tomatoes   carrots   If you want to remove the word potatoes from the sting altogether  you can use   string   string replacingOccurrences of   potatoes   with      options  NSString CompareOptions literal  range  nil    If you want to use some other characters in your sting  use         Null Character   0    Backslash       Horizontal Tab   t    Line Feed   n    Carriage Return   r    Double Quote        Single Quote           Example   string   string replacingOccurrences of   potatoes   with   dog  s toys   options  NSString CompareOptions literal  range  nil    Output   dog s toys   carrots

User · Answer

Swift 3 and Swift 4   text2   text2 textureName replacingOccurrences of        with      options  NSString CompareOptions literal  range nil    Latest documents updated to Swift 3 0 1 have         Null Character   0    Backslash        Horizontal Tab   t    Line Feed   n    Carriage Return   r    Double Quote        Single Quote        Unicode scalar   u n    where n is between one and eight hexadecimal    digits      If you need more details you can take a look to the official docs here

User · Answer

You ve instantiated text2 as an Optional  e g  var text2  String    This is why you receive Optional  5   in your string   take away the   and replace with   var text2  String

User · Answer

Replacing for Removing is not quite logical  String filter allows to iterate a string char by char and keep only true assertion   Swift 4  amp  5  var aString    Optional   5      aString   aString filter    0             gt  Optional 5    Or to extend  var aString    Optional   5      let filteredChars       n t   aString   aString filter   filteredChars range of  String  0      nil     gt  Optional 5

User · Answer

If you want to remove more characters for example  a    A    b    B    c    C  from string you can do it this way   someString   someString replacingOccurrences of    abc    with      options    regularExpression   caseInsensitive

User · Answer

Here is the swift 3 updated answer  var editedText   myLabel text  replacingOccurrences of        with         Null Character   0  Backslash      Horizontal Tab   t  Line Feed   n  Carriage Return   r  Double Quote      Single Quote      Unicode scalar   u n

User · Answer

I ve eventually got this to work in the playground  having multiple characters I m trying to remove from a string   var otherstring    lat     40 7127837  n  var new   otherstring stringByTrimmingCharactersInSet NSCharacterSet init charactersInString   la t   n          count new    result   10 println new     yielding what I m after just the numeric portion 40 7127837

User · Answer

If you are getting the output Optional 5  when trying to print the value of 5 in an optional Int or String  you should unwrap the value first   if let value   text       print value      Now you ve got the value without the  Optional  string that Swift adds when the value is not unwrapped before

User · Answer

If you are getting the output Optional 5  when trying to print the value of 5 in an optional Int or String  you should unwrap the value first  if value    nil   print value     or you can use this  if let value   text       print value     or in simple just 1 line answer  print value     quot  quot    The last line will check if variable  value  has any value assigned to it  if not it will print empty string

User · Answer

To remove the optional you only should do this  println    text2       cause if you dont use     it takes the optional value of text2  And to remove    from 5 you have to convert it to NSInteger or NSNumber easy peasy  It has    cause its an string

User · Answer

As Martin R says  your string  Optional  5    looks like you did something wrong   dasblinkenlight answers you so it is fine  but for future readers  I will try to add alternative code as   if let realString   yourOriginalString       text2   realString   else       text2          text2 in your example looks like String and it is maybe already set to    but it looks like you have an yourOriginalString of type Optional String  somewhere that it wasn t cast or use correctly   I hope this can help some reader

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