[python] How can I check file size in Python?

I am writing a Python script in Windows. I want to do something based on the file size. For example, if the size is greater than 0, I will send an email to somebody, otherwise continue to other things.

How do I check the file size?

Using pathlib (added in Python 3.4 or a backport available on PyPI):

from pathlib import Path
file = Path() / 'doc.txt'  # or Path('./doc.txt')
size = file.stat().st_size

This is really only an interface around os.stat, but using pathlib provides an easy way to access other file related operations.

You can use the stat() method from the os module. You can provide it with a path in the form of a string, bytes or even a PathLike object. It works with file descriptors as well.

import os

res = os.stat(filename)

res.st_size # this variable contains the size of the file in bytes

#Get file size , print it , process it...
#Os.stat will provide the file size in (.st_size) property. 
#The file size will be shown in bytes.

import os

fsize=os.stat('filepath')
print('size:' + fsize.st_size.__str__())

#check if the file size is less than 10 MB

if fsize.st_size < 10000000:
    process it ....

The other answers work for real files, but if you need something that works for "file-like objects", try this:

# f is a file-like object. 
f.seek(0, os.SEEK_END)
size = f.tell()

It works for real files and StringIO's, in my limited testing. (Python 2.7.3.) The "file-like object" API isn't really a rigorous interface, of course, but the API documentation suggests that file-like objects should support seek() and tell().

Edit

Another difference between this and os.stat() is that you can stat() a file even if you don't have permission to read it. Obviously the seek/tell approach won't work unless you have read permission.

Edit 2

At Jonathon's suggestion, here's a paranoid version. (The version above leaves the file pointer at the end of the file, so if you were to try to read from the file, you'd get zero bytes back!)

# f is a file-like object. 
old_file_position = f.tell()
f.seek(0, os.SEEK_END)
size = f.tell()
f.seek(old_file_position, os.SEEK_SET)

You can check a file size by using

import sys
print(sys.getsizeof(your_file))

For example,

nums = range(10000)
squares = [i**2 for i in nums]
print(sys.getsizeof(squares))

import os


def convert_bytes(num):
    """
    this function will convert bytes to MB.... GB... etc
    """
    for x in ['bytes', 'KB', 'MB', 'GB', 'TB']:
        if num < 1024.0:
            return "%3.1f %s" % (num, x)
        num /= 1024.0


def file_size(file_path):
    """
    this function will return the file size
    """
    if os.path.isfile(file_path):
        file_info = os.stat(file_path)
        return convert_bytes(file_info.st_size)


# Lets check the file size of MS Paint exe 
# or you can use any file path
file_path = r"C:\Windows\System32\mspaint.exe"
print file_size(file_path)

Result:

6.1 MB

we have two options Both include importing os module

1) import os, as os.stat() function returns an object which contains so many headers including file created time and last modified time etc.. among them st_size gives the exact size of the file.

os.stat("filename").st_size

2) import os In this, we have to provide the exact file path(absolute path), not a relative path.

os.path.getsize("path of file")

There is a bitshift trick I use if I want to to convert from bytes to any other unit. If you do a right shift by 10 you basically shift it by an order (multiple).

Example: 5GB are 5368709120 bytes

print (5368709120 >> 10)  # 5242880 kilobytes (kB)
print (5368709120 >> 20 ) # 5120 megabytes (MB)
print (5368709120 >> 30 ) # 5 gigabytes (GB)

Using os.path.getsize:

>>> import os
>>> b = os.path.getsize("/path/isa_005.mp3")
>>> b
2071611

The output is in bytes.

Strictly sticking to the question, the Python code (+ pseudo-code) would be:

import os
file_path = r"<path to your file>"
if os.stat(file_path).st_size > 0:
    <send an email to somebody>
else:
    <continue to other things>