Date difference in minutes in Python

Question

How do I calculate the difference in time in minutes for the following timestamp in Python   2010-01-01 17 31 22 2010-01-03 17 31 22

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minutes diff    datetime end - datetime start  total seconds     60 0

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RSabet s answer doesn t work in cases where the dates don t have the same exact time   Original problem   from datetime import datetime  fmt     Y- m- d  H  M  S  d1   datetime strptime  2010-01-01 17 31 22   fmt  d2   datetime strptime  2010-01-03 17 31 22   fmt   daysDiff    d2-d1  days print daysDiff  gt  2    Convert days to minutes minutesDiff   daysDiff   24   60  print minutesDiff  gt  2880   d2-d1 gives you a datetime timedelta and when you use days it will only show you the days in the timedelta  In this case it works fine  but if you would have the following   from datetime import datetime  fmt     Y- m- d  H  M  S  d1   datetime strptime  2010-01-01 16 31 22   fmt  d2   datetime strptime  2010-01-03 20 15 14   fmt   daysDiff    d2-d1  days print daysDiff  gt  2    Convert days to minutes minutesDiff   daysDiff   24   60  print minutesDiff  gt  2880    that is wrong   It would have still given you the same answer since it still returns 2 for days  it ignores the hour  min and second from the timedelta   A better approach would be to convert the dates to a common format and then do the calculation  The easiest way to do this is to convert them to Unix timestamps  Here is the code to do that   from datetime import datetime import time  fmt     Y- m- d  H  M  S  d1   datetime strptime  2010-01-01 17 31 22   fmt  d2   datetime strptime  2010-01-03 20 15 14   fmt     Convert to Unix timestamp d1 ts   time mktime d1 timetuple    d2 ts   time mktime d2 timetuple       They are now in seconds  subtract and then divide by 60 to get minutes  print int d2 ts-d1 ts    60  gt  3043    Much better

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there is also a sneak way with pandas   pd to timedelta x  - pd to timedelta y

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The result depends on the timezone that corresponds to the input time strings    The simplest case if both dates use the same utc offset      usr bin env python3 from datetime import datetime  timedelta  time format     Y- d- m  H  M  S  dt1   datetime strptime  2010-01-01 17 31 22   time format  dt2   datetime strptime  2010-01-03 17 31 22   time format  print  dt2 - dt1     timedelta minutes 1     minutes   If your Python version doesn t support td    timedelta  replace it with int td total seconds      60    If the input time is in the local timezone that might have different utc offset at different times e g   it has daylight saving time then you should make dt1  dt2 into aware datetime objects before finding the difference  to take into account the possible changes in the utc offset   The portable way to make an aware local datetime objects is to use pytz timezones      usr bin env python from datetime import timedelta import tzlocal     pip install tzlocal  local tz   tzlocal get localzone     get pytz timezone aware dt1  aware dt2   map local tz localize   dt1  dt2   td    aware dt2 - aware dt1   elapsed time   If either dt1 or dt2 correspond to an ambiguous time then the default is dst False is used to disambiguate  You could set is dst None to raise an exception for ambiguous or non-existent local times instead   If you can t install 3rd party modules then time mktime   could be used from  Ken Cochrane s answer that can find the correct utc offset on some platforms for some dates in some timezones -- if you don t need a consistent  but perhaps wrong  result then it is much better than doing dt2 - dt1 with naive datetime objects that always fails if the corresponding utc offsets are different

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In Other ways to get difference between date   import dateutil parser import datetime  timeDifference   current date - dateutil parser parse last sent date  time difference in minutes    int timeDifference days    24   60    int  timeDifference seconds    60    Thanks

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To calculate with a different time date   from datetime import datetime  fmt     Y- m- d  H  M  S  d1   datetime strptime  2010-01-01 16 31 22   fmt  d2   datetime strptime  2010-01-03 20 15 14   fmt   diff   d2-d1 diff minutes   diff seconds 60

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As was kind of said already  you need to use datetime datetime s strptime method   from datetime import datetime  fmt     Y- m- d  H  M  S  d1   datetime strptime  2010-01-01 17 31 22   fmt  d2   datetime strptime  2010-01-03 17 31 22   fmt   daysDiff    d2-d1  days    convert days to minutes minutesDiff   daysDiff   24   60  print minutesDiff

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In case someone doesn t realize it  one way to do this would be to combine Christophe and RSabet s answers   from datetime import datetime import time  fmt     Y- m- d  H  M  S  d1   datetime strptime  2010-01-01 17 31 22   fmt  d2   datetime strptime  2010-01-03 20 15 14   fmt   diff   d2 -d1 diff minutes    diff days   24   60     diff seconds 60   print diff minutes   gt  3043

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If you are trying to find the difference between timestamps that are in pandas columns  the the answer is fairly simple  If you need it in days or seconds then    For difference in days  df  diff in days    df  timestamp2   - df  timestamp1    dt days   For difference in seconds df  diff in seconds    df  timestamp2   - df  timestamp1    dt seconds   Now minute is tricky as dt minute works only on datetime64 ns  dtype  whereas the column generated from subtracting two datetimes has format   AttributeError   TimedeltaProperties  object has no attribute  m8    So like mentioned by many above to get the actual value of the difference in minute you have to do   df  diff in min   df  diff in seconds   60   But if just want the difference between the minute parts of the  two timestamps then do the following   convert the timedelta to datetime and then extract minute df  diff in min    pd to datetime df  timestamp2  -df  timestamp1     dt minute   You can also read the article https   docs python org 3 4 library datetime html and see section 8 1 2 you ll see the read only attributes are only seconds days and milliseconds  And this settles why the minute function doesn t work directly

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from datetime import datetime  fmt     Y- m- d  H  M  S  d1   datetime strptime  2010-01-01 17 31 22   fmt  d2   datetime strptime  2010-01-03 17 31 22   fmt   print  d2-d1  days   24   60

User · Answer

Use datetime strptime   to parse into datetime instances  and then compute the difference  and finally convert the difference into minutes

[python] Date difference in minutes in Python

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