[python] Convert python datetime to timestamp in milliseconds

How to convert a human readable time with the format 20.12.2016 09:38:42,76 to Unix timestamps in milliseconds? I found a lot of similar questions, but didn't found this specific question/answer.

For those who searches for an answer without parsing and loosing milliseconds, given dt_obj is a datetime:

python3 only, elegant

int(dt_obj.timestamp() * 1000)

both python2 and python3 compatible:

import time

int(time.mktime(dt_obj.utctimetuple()) * 1000 + dt_obj.microsecond / 1000)

You need to parse your time format using strptime.

>>> import time
>>> from datetime import datetime
>>> ts, ms = '20.12.2016 09:38:42,76'.split(',')
>>> ts
'20.12.2016 09:38:42'
>>> ms
'76'
>>> dt = datetime.strptime(ts, '%d.%m.%Y %H:%M:%S')
>>> time.mktime(dt.timetuple())*1000 + int(ms)*10
1482223122760.0

For Python2.7

You can format it into seconds and then multiply by 1000 to convert to millisecond.

from datetime import datetime

d = datetime.strptime("20.12.2016 09:38:42,76", "%d.%m.%Y %H:%M:%S,%f").strftime('%s')
d_in_ms = int(d)*1000
print(d_in_ms)

print(datetime.fromtimestamp(float(d)))

Output:

1482206922000
2016-12-20 09:38:42

For Python2.7 - modifying MYGz's answer to not strip milliseconds:

from datetime import datetime

d = datetime.strptime("20.12.2016 09:38:42,76", "%d.%m.%Y %H:%M:%S,%f").strftime('%s.%f')
d_in_ms = int(float(d)*1000)
print(d_in_ms)

print(datetime.fromtimestamp(float(d)))

Output:

1482248322760
2016-12-20 09:38:42.760000