How to parse unix timestamp to time Time

Question

I m trying to parse an Unix timestamp but I get out of range error  That doesn t really makes sense to me  because the layout is correct  as in the Go docs    package main  import  fmt  import  time   func main         tm  err    time Parse  1136239445    1405544146       if err    nil          panic err             fmt Println tm      Playground

User · Answer

You can directly use time Unix function of time which converts the unix time stamp to UTC   package main  import      fmt     time      func main         unixTimeUTC  time Unix 1405544146  0    gives unix time stamp in utc       unitTimeInRFC3339   unixTimeUTC Format time RFC3339     converts utc time to RFC3339 format      fmt Println  unix time stamp in UTC  --- gt   unixTimeUTC      fmt Println  unix time stamp in unitTimeInRFC3339 format  - gt   unitTimeInRFC3339      Output  unix time stamp in UTC  --- gt  2014-07-16 20 55 46  0000 UTC unix time stamp in unitTimeInRFC3339 format  ---- gt  2014-07-16T20 55 46Z   Check in Go Playground  https   play golang org p 5FtRdnkxAd

User · Answer

Sharing a few functions which I created for dates   Please note that I wanted to get time for a particular location  not just UTC time   If you want UTC time  just remove loc variable and  In loc  function call    func GetTimeStamp   string        loc       time LoadLocation  America Los Angeles        t    time Now   In loc       return t Format  20060102150405     func GetTodaysDate   string       loc       time LoadLocation  America Los Angeles       current time    time Now   In loc      return current time Format  2006-01-02      func GetTodaysDateTime   string       loc       time LoadLocation  America Los Angeles       current time    time Now   In loc      return current time Format  2006-01-02 15 04 05      func GetTodaysDateTimeFormatted   string       loc       time LoadLocation  America Los Angeles       current time    time Now   In loc      return current time Format  Jan 2  2006 at 3 04 PM      func GetTimeStampFromDate dtformat string  string       form     Jan 2  2006 at 3 04 PM      t2       time Parse form  dtformat      return t2 Format  20060102150405

User · Answer

According to the go documentation  Unix returns a local time      Unix returns the local Time corresponding to the given Unix time   This means the output would depend on the machine your code runs on  which  most often is what you need  but sometimes  you may want to have the value in UTC   To do so  I adapted the snippet to make it return a time in UTC   i  err    strconv ParseInt  1405544146   10  64  if err    nil       panic err    tm    time Unix i  0  fmt Println tm UTC      This prints on my machine  in CEST   2014-07-16 20 55 46  0000 UTC

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I do a lot of logging where the timestamps are float64 and use this function to get the timestamps as string  func dateFormat layout string  d float64  string      intTime    int64 d      t    time Unix intTime  0      if layout     quot  quot            layout    quot 2006-01-02 15 04 05 quot            return t Format layout

User · Answer

The time Parse function does not do Unix timestamps  Instead you can use strconv ParseInt to parse the string to int64 and create the timestamp with time Unix   package main  import        fmt       time       strconv     func main         i  err    strconv ParseInt  1405544146   10  64      if err    nil           panic err            tm    time Unix i  0      fmt Println tm      Output   2014-07-16 20 55 46  0000 UTC   Playground  http   play golang org p v j6UIro7a  Edit   Changed from strconv Atoi to strconv ParseInt to avoid int overflows on 32 bit systems

[go] How to parse unix timestamp to time.Time

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