[mysql] MYSQL query between two timestamps

Try below code. Worked in my case. Hope this helps!

    select id,total_Hour,
    (coalesce(weekday_1,0)+coalesce(weekday_2,0)+coalesce(weekday_3,0)) as weekday_Listing_Hrs,
    (coalesce(weekend_1,0)+coalesce(weekend_2,0)+coalesce(weekend_3,0)) as weekend_Listing_Hrs
    from
    select *,
    listing_duration_Hour-(coalesce(weekday_1,0)+coalesce(weekday_2,0)+coalesce(weekday_3,0)+coalesce(weekend_1,0)+coalesce(weekend_2,0)) as weekend_3 
    from 
    (
    select * , 
    case when date(Start_Date) = date(End_Date) and weekday(Start_Date) in (0,1,2,3,4) 
         then timestampdiff(hour,Start_Date,End_Date)
         when date(Start_Date) != date(End_Date) and weekday(Start_Date) in (0,1,2,3,4) 
         then 24-timestampdiff(hour,date(Start_Date),Start_Date)
         end as weekday_1,  
    case when date(Start_Date) != date(End_Date) and weekday(End_Date) in (0,1,2,3,4) 
         then timestampdiff(hour,date(End_Date),End_Date)
         end as weekday_2,
    case when date(Start_Date) != date(End_Date) then    
    (5*(DATEDIFF(date(End_Date),adddate(date(Start_Date),+1)) DIV 7) + 
    MID('0123455501234445012333450122234501101234000123450',7 * WEEKDAY(adddate(date(Start_Date),+1))
    + WEEKDAY(date(End_Date)) + 1, 1))* 24 end as  weekday_3,
    case when date(Start_Date) = date(End_Date) and weekday(Start_Date) in (5,6) 
         then timestampdiff(hour,Start_Date,End_Date)
         when date(Start_Date) != date(End_Date) and weekday(Start_Date) in (5,6) 
         then 24-timestampdiff(hour,date(Start_Date),Start_Date)
         end as weekend_1,  
    case when date(Start_Date) != date(End_Date) and weekday(End_Date) in (5,6) 
         then timestampdiff(hour,date(End_Date),End_Date)
         end as weekend_2
    from 
    TABLE_1
    )