Regular expression to return text between parenthesis

Question

u abcde date   2 xc2 xb2   time    case test png       All I need is the contents inside the parenthesis

User · Answer

import re  fancy   u abcde date   2 xc2 xb2   time    case test png      print re compile               search  fancy   group  1

User · Answer

contents re   re match r           P lt contents gt             data  if contents re      print contents re groupdict    contents

User · Answer

Use re search r            s  group 1     gt  gt  gt  import re  gt  gt  gt  s   u abcde date   2 xc2 xb2   time    case test png      gt  gt  gt  re search r            s  group 1  u date  2 xc2 xb2  time   case test png

User · Answer

If you want to find all occurences     gt  gt  gt  re findall           s   u  date  2 xc2 xb2  time   case test png     u  eee      gt  gt  gt  re findall             s   u date  2 xc2 xb2  time   case test png    u eee

User · Answer

If your problem is really just this simple  you don t need regex   s s find      1 s find

User · Answer

No need to use regex      Just use list slicing     string  quot  tidtkdgkxkxlgxlhxl                     quot  print string string find  quot   quot   1 string find  quot   quot

User · Answer

Building on tkerwin s answer  if you happen to have nested parentheses like in   st    sum  a b   c d      his answer will not work if you need to take everything between the first opening parenthesis and the last closing parenthesis to get  a b   c d   because find searches from the left of the string  and would stop at the first closing parenthesis   To fix that  you need to use rfind for the second part of the operation  so it would become   st st find      1 st rfind

[python] Regular expression to return text between parenthesis

Examples related to python

Examples related to regex

Examples related to python-3.x