What causes a java lang StackOverflowError

Question

What can cause a java lang StackOverflowError  The stack printout that I get is not very deep at all  only 5 methods

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In my case I have two activities  In the second activity I forgot to put super on the onCreate method   super onCreate savedInstanceState

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What actually causes a java lang StackOverflowError is typically unintentional recursion  For me it s often when I intended to call a super method for the overidden method  Such as in this case   public class Vehicle       public void accelerate float acceleration  float maxVelocity               set the acceleration          public class SpaceShip extends Vehicle        Override     public void accelerate float acceleration  float maxVelocity               update the flux capacitor and call super accelerate            oops meant to call super accelerate acceleration  maxVelocity              but accidentally wrote this instead  A StackOverflow is in our future          this accelerate acceleration  maxVelocity              First  it s useful to know what happens behind the scenes when we call a function  The arguments and the address of where the method was called is pushed on the stack  see http   en wikipedia org wiki Stack  abstract data type  Runtime memory management  so that the called method can access the arguments and so that when the called method is completed  execution can continue after the call  But since we are calling this accelerate acceleration  maxVelocity  recursively  recursion is loosely when a method calls itself  For more info see http   en wikipedia org wiki Recursion  computer science   we are in a situation known as infinite recursion and we keep piling the arguments and return address on the call stack  Since the call stack is finite in size  we eventually run out of space  The running out of space on the call stack is known as overflow  This is because we are trying to use more stack space than we have and the data literally overflows the stack  In the Java programming language  this results in the runtime exception java lang StackOverflow and will immediately halt the program    The above example is somewhat simplified  although it happens to me more than I d like to admit   The same thing can happen in a more round about way making it a bit harder to track down  However  in general  the StackOverflow is usually pretty easy to resolve  once it occurs   In theory  it is also possible to have a stack overflow without recursion  but in practice  it would appear to be a fairly rare event

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I was having the same issue Role java   ManyToMany mappedBy    quot roles quot   fetch   FetchType LAZY cascade   CascadeType ALL   Set lt BusinessUnitMaster gt  businessUnits  new HashSet lt  gt      BusinessUnitMaster java  ManyToMany cascade   CascadeType ALL  fetch   FetchType LAZY   JoinTable          name    quot BusinessUnitRoles quot           joinColumns     JoinColumn name    quot unit id quot   referencedColumnName    quot record id quot             inverseJoinColumns     JoinColumn name    quot role id quot   referencedColumnName    quot record id quot      private Set lt Role gt  roles new HashSet lt  gt      the problem is that when you create BusinessUnitMaster and Role you have to save the object for both sides for RoleService java roleRepository save role    for BusinessUnitMasterService java businessUnitMasterRepository save businessUnitMaster

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What is java lang StackOverflowError  The error java lang StackOverflowError is thrown to indicate that the application   s stack was exhausted  due to deep recursion i e your program script recurses too deeply   Details  The StackOverflowError extends VirtualMachineError class which indicates that the JVM have been or have run out of resources and cannot operate further  The VirtualMachineError which extends the Error class is used to indicate those serious problems that an application should not catch  A method may not declare such errors in its throw clause because these errors are abnormal conditions that was never expected to occur   An Example  Minimal  Complete  and Verifiable Example    package demo   public class StackOverflowErrorExample        public static void main String   args                 StackOverflowErrorExample recursivePrint 1              public static void recursivePrint int num            System out println  Number      num            if num    0              return          else             recursivePrint   num              Console Output  Number  1 Number  2       Number  8645 Number  8646 Number  8647Exception in thread  main  java lang StackOverflowError     at java io FileOutputStream write Unknown Source      at java io BufferedOutputStream flushBuffer Unknown Source      at java io BufferedOutputStream flush Unknown Source      at java io PrintStream write Unknown Source      at sun nio cs StreamEncoder writeBytes Unknown Source      at sun nio cs StreamEncoder implFlushBuffer Unknown Source      at sun nio cs StreamEncoder flushBuffer Unknown Source      at java io OutputStreamWriter flushBuffer Unknown Source      at java io PrintStream newLine Unknown Source      at java io PrintStream println Unknown Source      at demo StackOverflowErrorExample recursivePrint StackOverflowErrorExample java 11      at demo StackOverflowErrorExample recursivePrint StackOverflowErrorExample java 16                        at demo StackOverflowErrorExample recursivePrint StackOverflowErrorExample java 16    Explaination  When a function call is invoked by a Java Application  a stack frame is allocated on the call stack  The stack frame contains the parameters of the invoked method  its local parameters  and the return address of the method  The return address denotes the execution point from which  the program execution shall continue after the invoked method returns  If there is no space for a new stack frame then  the StackOverflowError is thrown by the Java Virtual Machine  JVM    The most common case that can possibly exhaust a Java application   s stack is recursion  In recursion  a method invokes itself during its execution  Recursion one of the most powerful general-purpose programming technique  but must be used with caution  in order for the StackOverflowError to be avoided   References   Java Doc  StackOverflowError

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Check for any recusive calls for methods  Mainly it is caused when there is recursive call for a method  A simple example is  public static void main String    args        Main main   new Main         main testMethod 1      public void testMethod int i        testMethod i        System out println i       Here the System out println i   will be repeatedly pushed to stack when the testMethod is called

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Stack Overflow exceptions can occur when a thread stack continues to grow in size until reaching the maximum limit    Adjusting the Stack Sizes  Xss and Xmso  options     I suggest you see this link  http   www-01 ibm com support docview wss uid swg21162896 There are many possible causes to a StackOverflowError  as you can see in the link

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When a function call is invoked by a Java application  a stack frame is allocated on the call stack  The stack frame contains the parameters of the invoked method  its local parameters  and the return address of the method    The return address denotes the execution point from which  the program execution shall continue after the invoked method returns  If there is no space for a new stack frame then  the StackOverflowError is thrown by the Java Virtual Machine  JVM    The most common case that can possibly exhaust a Java application   s stack is recursion    Please Have a look   How to solve StackOverflowError

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Solution for Hibernate users when parsing datas   I had this error because I was parsing a list of objects mapped on both sides  OneToMany and  ManyToOne to json using jackson which caused an infinite loop   If you are in the same situation you can solve this by using  JsonManagedReference and  JsonBackReference annotations   Definitions from API     JsonManagedReference  https   fasterxml github io jackson-annotations javadoc 2 5 com fasterxml jackson annotation JsonManagedReference html         Annotation used to indicate that annotated property is part of two-way   linkage between fields  and that its role is  parent   or  forward     link  Value type  class  of property must have a single compatible   property annotated with JsonBackReference  Linkage is handled such   that the property annotated with this annotation is handled normally    serialized normally  no special handling for deserialization   it is   the matching back reference that requires special handling  JsonBackReference   https   fasterxml github io jackson-annotations javadoc 2 5 com fasterxml jackson annotation JsonBackReference html       Annotation used to indicate that associated property is part of   two-way linkage between fields  and that its role is  child   or    back   link  Value type of the property must be a bean  it can not be   a Collection  Map  Array or enumeration  Linkage is handled such that   the property annotated with this annotation is not serialized  and   during deserialization  its value is set to instance that has the    managed   forward  link     Example   Owner java    JsonManagedReference  OneToMany mappedBy    owner   fetch   FetchType EAGER  Set lt Car gt  cars    Car java    JsonBackReference  ManyToOne fetch   FetchType EAGER   JoinColumn name    owner id   private Owner owner    Another solution is to use  JsonIgnore which will just set null to the field

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One of the  optional  arguments to the JVM is the stack size  It s -Xss  I don t know what the default value is  but if the total amount of stuff on the stack exceeds that value  you ll get that error   Generally  infinite recursion is the cause of this  but if you were seeing that  your stack trace would have more than 5 frames   Try adding a -Xss argument  or increasing the value of one  to see if this goes away

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I created a program with hibernate  in which I created two POJO classes  both with an object of each other as data members  When in the main method I tried to save them in the database I also got this error   This happens because both of the classes are referring each other  hence creating a loop which causes this error   So  check whether any such kind of relationships exist in your program

[java] What causes a java.lang.StackOverflowError

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