[javascript] Submit form and stay on same page?

I have a form that looks like this

<form action="receiver.pl" method="post">
  <input name="signed" type="checkbox">
  <input value="Save" type="submit">
</form>

and I would like to stay on the same page, when Submit is clicked, but still have receiver.pl executed.

How should that be done?

When you hit on the submit button, the page is sent to the server. If you want to send it async, you can do it with ajax.

The HTTP/CGI way to do this would be for your program to return an HTTP status code of 204 (No Content).

99% of the time I would use XMLHttpRequest or fetch for something like this. However, there's an alternative solution which doesn't require javascript...

You could include a hidden iframe on your page and set the target attribute of your form to point to that iframe.

<style>
  .hide { position:absolute; top:-1px; left:-1px; width:1px; height:1px; }
</style>

<iframe name="hiddenFrame" class="hide"></iframe>

<form action="receiver.pl" method="post" target="hiddenFrame">
  <input name="signed" type="checkbox">
  <input value="Save" type="submit">
</form>

There are very few scenarios where I would choose this route. Generally handling it with javascript is better because, with javascript you can...

• gracefully handle errors (e.g. retry)
• provide UI indicators (e.g. loading, processing, success, failure)
• run logic before the request is sent, or run logic after the response is received.

Use XMLHttpRequest

var xhr = new XMLHttpRequest();
xhr.open("POST", '/server', true);

//Send the proper header information along with the request
xhr.setRequestHeader("Content-Type", "application/x-www-form-urlencoded");

xhr.onreadystatechange = function() { // Call a function when the state changes.
    if (this.readyState === XMLHttpRequest.DONE && this.status === 200) {
        // Request finished. Do processing here.
    }
}
xhr.send("foo=bar&lorem=ipsum");
// xhr.send(new Int8Array()); 
// xhr.send(document);