Regular expression for exact match of a string

Question

I want to match two passwords with regular expression  For example I have two inputs  123456  and  1234567  then the result should be not match  false   And when I have entered  123456  and  123456  then the result should be match  true    I couldn t make the expression  How do I do it

User · Answer

A more straight forward way is to check for equality

if string1 == string2
  puts "match"
else
  puts "not match"
end

however, if you really want to stick to regular expression,

string1 =~ /^123456$/

User · Answer

You may also try appending a space at the start and end of keyword    s 123456 s  i

User · Answer

lt    w d  abc     w d     this makes sure that your match is not preceded by some character  number  or underscore and is not followed immediately by  character or number  or underscore  so it will match  abc  in  abc    abc     abc    but not  4abc   nor  abcde

User · Answer

if you have a the input password in a variable and you want to match exactly 123456 then anchors will help you     123456     in perl the test for matching the password would be something like  print  MATCH OK  if   input pass    123456       EDIT   bart kiers is right tho  why don t you use a strcmp   for this  every language has it in its own way  as a second thought  you may want to consider a safer authentication mechanism

User · Answer

In malfaux s answer     and     has been used to detect the beginning and the end of the text   These are usually used to detect the beginning and the end of a line  However this may be the correct way in this case  But if you wish to match an exact word the more elegant way is to use   b   In this case following pattern will match the exact phrase 123456          b123456 b

[regex] Regular expression for exact match of a string

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