So I want to compare this folder http://cloudobserver.googlecode.com/svn/branches/v0.4/Boost.Extension.Tutorial/libs/boost/extension/ with this http://svn.boost.org/svn/boost/sandbox/boost/extension/. I want to get a diff file as a result. These folders are under svn control but I'd prefer git styled diff file (like one shown here) I tried git diff but it seems not to work that way for web folders. So how to do the same thing with one command on Linux?
Update: So we had a great answer. But it works strangely - it seems to me it shows that all files (same files) have all theire contents replaced with very same contents (while I know for sure that there were only like 3-4 code lines changed at all)...
Update 2: To achieve what I really needed (dif file with only really changed lines, with git styling, on Linux) do:
$ svn export http://cloudobserver.googlecode.com/svn/branches/v0.4/Boost.Extension.Tutorial/libs/boost/extension/ repos2 --native-eol CRLF
$ svn export http://svn.boost.org/svn/boost/sandbox/boost/extension/ repos --native-eol CRLF
$ git diff repos repos2 > fileWithReadableDiff.diff
Once you have the source trees, e.g.
diff -ENwbur repos1/ repos2/
Even better
diff -ENwbur repos1/ repos2/ | kompare -o -
and have a crack at it in a good gui tool :)
You urls are not in the same repository, so you can't do it with the svn diff command.
svn: 'http://svn.boost.org/svn/boost/sandbox/boost/extension' isn't in the same repository as 'http://cloudobserver.googlecode.com/svn'
Another way you could do it, is export each repos using svn export, and then use the diff command to compare the 2 directories you exported.
// Export repositories
svn export http://svn.boost.org/svn/boost/sandbox/boost/extension/ repos1
svn export http://cloudobserver.googlecode.com/svn/branches/v0.4/Boost.Extension.Tutorial/libs/boost/extension/ repos2
// Compare exported directories
diff repos1 repos2 > file.diff
Source: Stackoverflow.com