I have two files A1 and A2 (unsorted). A1 is previous version of A2 and some lines have been added to A2. How can I get the new lines that are added to A2?
Note: I just want the new lines added and dont want the lines which were in A1 but deleted in A2. When i do diff A1 A2
, I get the additions as well as deletions but I want only additions.
Please suggest a way to do this.
You can try this
diff --changed-group-format='%>' --unchanged-group-format='' A1 A2
The options are documented in man diff
:
--GTYPE-group-format=GFMT
format GTYPE input groups with GFMT
and:
LTYPE is 'old', 'new', or 'unchanged'.
GTYPE is LTYPE or 'changed'.
and:
GFMT (only) may contain:
%< lines from FILE1
%> lines from FILE2
[...]
A similar approach to https://stackoverflow.com/a/15385080/337172 but hopefully more understandable and easy to tweak:
diff \
--new-line-format="%L" \
--old-line-format="" \
--unchanged-line-format="" \
A1 A2
git diff path/file.css | grep -E "^\+" | grep -v '+++ b/' | cut -c 2-
grep -E "^\+"
is from previous accepted answer, it is incomplete because leaves non-source stuffgrep -v '+++ b'
removes non-source line with file name of later versioncut -c 2-
removes column of +
signs, also may use sed 's/^\+//'
comm
or sdiff
were not an option because of git.
The simple method is to use :
sdiff A1 A2
Another method is to use comm
, as you can see in Comparing two unsorted lists in linux, listing the unique in the second file
You can type:
grep -v -f A1 A2
All of the below is copied directly from @TomOnTime's serverfault answer here:
Show lines that only exist in file a: (i.e. what was deleted from a)
comm -23 a b
Show lines that only exist in file b: (i.e. what was added to b)
comm -13 a b
Show lines that only exist in one file or the other: (but not both)
comm -3 a b | sed 's/^\t//'
(Warning: If file a
has lines that start with TAB, it (the first TAB) will be removed from the output.)
NOTE: Both files need to be sorted for "comm" to work properly. If they aren't already sorted, you should sort them:
sort <a >a.sorted
sort <b >b.sorted
comm -12 a.sorted b.sorted
If the files are extremely long, this may be quite a burden as it requires an extra copy and therefore twice as much disk space.
Edit: note that the command can be written more concisely using process substitution (thanks to @phk for the comment):
comm -12 <(sort < a) <(sort < b)
Source: Stackoverflow.com