I would like to get just the folder path from the full path to a file.
For example T:\Data\DBDesign\DBDesign_93_v141b.mdb
and I would like to get just T:\Data\DBDesign
(excluding the \DBDesign_93_v141b.mdb
).
I have tried something like this:
existGDBPath = r'T:\Data\DBDesign\DBDesign_93_v141b.mdb'
wkspFldr = str(existGDBPath.split('\\')[0:-1])
print wkspFldr
but it gave me a result like this:
['T:', 'Data', 'DBDesign']
which is not the result that I require (being T:\Data\DBDesign
).
Any ideas on how I can get the path to my file?
The built-in submodule os.path has a function for that very task.
import os
os.path.dirname('T:\Data\DBDesign\DBDesign_93_v141b.mdb')
Anyone trying to do this in the ESRI GIS Table field calculator interface can do this with the Python parser:
PathToContainingFolder =
"\\".join(!FullFilePathWithFileName!.split("\\")[0:-1])
so that
\Users\me\Desktop\New folder\file.txt
becomes
\Users\me\Desktop\New folder
Here is my little utility helper for splitting paths int file, path tokens:
import os
# usage: file, path = splitPath(s)
def splitPath(s):
f = os.path.basename(s)
p = s[:-(len(f))-1]
return f, p
WITH PATHLIB MODULE (UPDATED ANSWER)
One should consider using pathlib for new development. It is in the stdlib for Python3.4, but available on PyPI for earlier versions. This library provides a more object-orented method to manipulate paths <opinion>
and is much easier read and program with </opinion>
.
>>> import pathlib
>>> existGDBPath = pathlib.Path(r'T:\Data\DBDesign\DBDesign_93_v141b.mdb')
>>> wkspFldr = existGDBPath.parent
>>> print wkspFldr
Path('T:\Data\DBDesign')
WITH OS MODULE
Use the os.path module:
>>> import os
>>> existGDBPath = r'T:\Data\DBDesign\DBDesign_93_v141b.mdb'
>>> wkspFldr = os.path.dirname(existGDBPath)
>>> print wkspFldr
'T:\Data\DBDesign'
You can go ahead and assume that if you need to do some sort of filename manipulation it's already been implemented in os.path
. If not, you'll still probably need to use this module as the building block.
Here is the code:
import os
existGDBPath = r'T:\Data\DBDesign\DBDesign_93_v141b.mdb'
wkspFldr = os.path.dirname(existGDBPath)
print wkspFldr # T:\Data\DBDesign
Source: Stackoverflow.com