In sql server 2008, how to extract only the year from the date. In DB I have a column for date, from that I need to extract the year. Is there any function for that?
This question is related to
sql
sql-server-2008
datetime
extract
year(@date)
year(getdate())
year('20120101')
update table
set column = year(date_column)
whre ....
or if you need it in another table
update t
set column = year(t1.date_column)
from table_source t1
join table_target t on (join condition)
where ....
SQL Server Script
declare @iDate datetime
set @iDate=GETDATE()
print year(@iDate) -- for Year
print month(@iDate) -- for Month
print day(@iDate) -- for Day
the year function dose, like this:
select year(date_column) from table_name
select year(current_timestamp)
Simply use
SELECT DATEPART(YEAR, SomeDateColumn)
It will return the portion of a DATETIME type that corresponds to the option you specify. SO DATEPART(YEAR, GETDATE()) would return the current year.
Can pass other time formatters instead of YEAR like
year(table_column)
Example:
select * from mytable where year(transaction_day)='2013'
DATEPART(yyyy, date_column) could be used to extract year. In general, DATEPART function is used to extract specific portions of a date value.
---Lalmuni Demos---
create table Users
(
userid int,date_of_birth date
)
insert into Users values(4,'9/10/1991')
select DATEDIFF(year,date_of_birth, getdate()) - (CASE WHEN (DATEADD(year, DATEDIFF(year,date_of_birth, getdate()),date_of_birth)) > getdate() THEN 1 ELSE 0 END) as Years,
MONTH(getdate() - (DATEADD(year, DATEDIFF(year, date_of_birth, getdate()), date_of_birth))) - 1 as Months,
DAY(getdate() - (DATEADD(year, DATEDIFF(year,date_of_birth, getdate()), date_of_birth))) - 1 as Days,
from users
You can use year() function in sql to get the year from the specified date.
Syntax:
YEAR ( date )
For more information check here
Source: Stackoverflow.com