Get folder name of the file in Python

Question

In Python what command should I use to get the name of the folder which contains the file I m working with   quot C  folder1 folder2 filename xml quot  Here  quot folder2 quot  is what I want to get  The only thing I ve come up with is to use os path split twice  folderName   os path split os path split  quot C  folder1 folder2 filename xml quot   0   1   Is there any better way to do it

User · Answer

You are looking to use dirname  If you only want that one directory  you can use os path basename   When put all together it looks like this    os path basename os path dirname  dir sub dir other sub dir file name txt      That should get you  other sub dir   The following is not the ideal approach  but I originally proposed using os path split  and simply get the last item  which would look like this   os path split os path dirname  dir sub dir other sub dir file name txt    -1

User · Answer

this is pretty old  but if you are using Python 3 4 or above use PathLib     using OS import os path os path dirname  C  folder1 folder2 filename xml   print path  print os path basename path      using pathlib import pathlib path   pathlib PurePath  C  folder1 folder2 filename xml   print path parent  print path parent name

User · Answer

I m using 2 ways to get the same response  one of them use     os path basename filename   due to errors that I found in my script I changed to  Path   filename   len filename -len os path basename filename      it s a workaround due to python s

User · Answer

You could get the full path as a string then split it into a list using your operating system s separator character   Then you get the program name  folder name etc by accessing the elements from the end of the list using negative indices   Like this   import os strPath   os path realpath   file    print  f Full Path      strPath     nmFolders   strPath split  os path sep   print   List of Folders    nmFolders   print  f Program Name   nmFolders -1      print  f Folder Name    nmFolders -2      print  f Folder Parent  nmFolders -3        The output of the above was this   Full Path     C  Users terry Documents apps environments dev app 02 app 02 py List of Folders    C     Users    terry    Documents    apps    environments    dev    app 02    app 02 py   Program Name  app 02 py Folder Name   app 02 Folder Parent dev

User · Answer

you can use pathlib from pathlib import Path Path r quot C  folder1 folder2 filename xml quot   parts -2   The output of the above was this   folder2

User · Answer

You can use dirname    os path dirname path        Return the directory name of pathname path  This is the first element   of the pair returned by passing path to the function split      And given the full path  then you can split normally to get the last portion of the path  For example  by using basename    os path basename path        Return the base name of pathname path  This is the second element of   the pair returned by passing path to the function split    Note that   the result of this function is different from the Unix basename   program  where basename for   foo bar   returns  bar   the basename     function returns an empty string           All together    gt  gt  gt  import os  gt  gt  gt  path os path dirname  C  folder1 folder2 filename xml    gt  gt  gt  path  C  folder1 folder2   gt  gt  gt  os path basename path   folder2

User · Answer

os path dirname is what you are looking for -  os path dirname r C  folder1 folder2 filename xml     Make sure you prepend r to the string so that its considered as a raw string   Demo -  In  46   os path dirname r C  folder1 folder2 filename xml   Out 46    C   folder1  folder2      If you just want folder2   you can use os path basename with the above  Example -  os path basename os path dirname r C  folder1 folder2 filename xml      Demo -  In  48   os path basename os path dirname r C  folder1 folder2 filename xml    Out 48    folder2

[python] Get folder name of the file in Python

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