I need to stop my program when an exception is raised in Python. How do I implement this?
This question is related to
python
exception-handling
If you don't handle an exception, it will propagate up the call stack up to the interpreter, which will then display a traceback and exit. IOW : you don't have to do anything to make your script exit when an exception happens.
import sys
try:
print("stuff")
except:
sys.exit(1) # exiing with a non zero value is better for returning from an error
import sys
try:
# your code here
except Exception as err:
print("Error: " + str(err))
sys.exit(50) # whatever non zero exit code
import sys
try:
print("stuff")
except:
sys.exit(1) # exiing with a non zero value is better for returning from an error
If you don't handle an exception, it will propagate up the call stack up to the interpreter, which will then display a traceback and exit. IOW : you don't have to do anything to make your script exit when an exception happens.
import sys
try:
import feedparser
except:
print "Error: Cannot import feedparser.\n"
sys.exit(1)
Here we're exiting with a status code of 1. It is usually also helpful to output an error message, write to a log, and clean up.
You can stop catching the exception, or - if you need to catch it (to do some custom handling), you can re-raise:
try:
doSomeEvilThing()
except Exception, e:
handleException(e)
raise
Note that typing raise
without passing an exception object causes the original traceback to be preserved. Typically it is much better than raise e
.
Of course - you can also explicitly call
import sys
sys.exit(exitCodeYouFindAppropriate)
This causes SystemExit exception to be raised, and (unless you catch it somewhere) terminates your application with specified exit code.
As far as I know, if an exception is not caught by your script, it will be interrupted.
You can stop catching the exception, or - if you need to catch it (to do some custom handling), you can re-raise:
try:
doSomeEvilThing()
except Exception, e:
handleException(e)
raise
Note that typing raise
without passing an exception object causes the original traceback to be preserved. Typically it is much better than raise e
.
Of course - you can also explicitly call
import sys
sys.exit(exitCodeYouFindAppropriate)
This causes SystemExit exception to be raised, and (unless you catch it somewhere) terminates your application with specified exit code.
import sys
try:
print("stuff")
except:
sys.exit(1) # exiing with a non zero value is better for returning from an error
If you don't handle an exception, it will propagate up the call stack up to the interpreter, which will then display a traceback and exit. IOW : you don't have to do anything to make your script exit when an exception happens.
As far as I know, if an exception is not caught by your script, it will be interrupted.
import sys
try:
print("stuff")
except:
sys.exit(1) # exiing with a non zero value is better for returning from an error
You can stop catching the exception, or - if you need to catch it (to do some custom handling), you can re-raise:
try:
doSomeEvilThing()
except Exception, e:
handleException(e)
raise
Note that typing raise
without passing an exception object causes the original traceback to be preserved. Typically it is much better than raise e
.
Of course - you can also explicitly call
import sys
sys.exit(exitCodeYouFindAppropriate)
This causes SystemExit exception to be raised, and (unless you catch it somewhere) terminates your application with specified exit code.
If you don't handle an exception, it will propagate up the call stack up to the interpreter, which will then display a traceback and exit. IOW : you don't have to do anything to make your script exit when an exception happens.
As far as I know, if an exception is not caught by your script, it will be interrupted.
import sys
try:
import feedparser
except:
print "Error: Cannot import feedparser.\n"
sys.exit(1)
Here we're exiting with a status code of 1. It is usually also helpful to output an error message, write to a log, and clean up.
import sys
try:
# your code here
except Exception as err:
print("Error: " + str(err))
sys.exit(50) # whatever non zero exit code
You can stop catching the exception, or - if you need to catch it (to do some custom handling), you can re-raise:
try:
doSomeEvilThing()
except Exception, e:
handleException(e)
raise
Note that typing raise
without passing an exception object causes the original traceback to be preserved. Typically it is much better than raise e
.
Of course - you can also explicitly call
import sys
sys.exit(exitCodeYouFindAppropriate)
This causes SystemExit exception to be raised, and (unless you catch it somewhere) terminates your application with specified exit code.
Source: Stackoverflow.com