round for float in C

Question

I need a simple floating point rounding function  thus    double round double    round 0 1    0 round -0 1    0 round -0 9    -1   I can find ceil   and floor   in the math h - but not round     Is it present in the standard C   library under another name  or is it missing

User · Answer

If you ultimately want to convert the double output of your round   function to an int  then the accepted solutions of this question will look something like   int roundint double r      return  int   r  gt  0 0    floor r   0 5    ceil r - 0 5        This clocks in at around 8 88 nbsp ns on my machine when passed in uniformly random values   The below is functionally equivalent  as far as I can tell  but clocks in at 2 48 nbsp ns on my machine  for a significant performance advantage   int roundint  double r      int tmp   static cast lt int gt   r     tmp     r-tmp gt   5  -  r-tmp lt  - 5     return tmp      Among the reasons for the better performance is the skipped branching

User · Answer

Function double round double  with the use of the modf function   double round double x        using namespace std       if   numeric limits lt double gt   max   - 0 5   lt   x          return numeric limits lt double gt   max         if   -1 std  numeric limits lt double gt   max     0 5   gt  x          return  -1 std  numeric limits lt double gt   max          double intpart      double fractpart   modf x   amp intpart        if  fractpart  gt   0 5          return  intpart   1       else if  fractpart  gt   -0 5          return intpart      else         return  intpart - 1           To be compile clean  includes  math h  and  limits  are necessary  The function works according to a following rounding schema    round of 5 0 is 5 0 round of 3 8 is 4 0 round of 2 3 is 2 0 round of 1 5 is 2 0 round of 0 501 is 1 0 round of 0 5 is 1 0 round of 0 499 is 0 0 round of 0 01 is 0 0 round of 0 0 is 0 0 round of -0 01 is -0 0 round of -0 499 is -0 0 round of -0 5 is -0 0 round of -0 501 is -1 0 round of -1 5 is -1 0 round of -2 3 is -2 0 round of -3 8 is -4 0 round of -5 0 is -5 0

User · Answer

Beware of floor x 0 5   Here is what can happen for odd numbers in range  2 52 2 53    -bash-3 2  cat  gt test-round c  lt  lt END   include  lt math h gt   include  lt stdio h gt   int main         double x 5000000000000001 0      double y round x       double z floor x 0 5       printf        x       f n  x       printf  round x       f n  y       printf  floor x 0 5   f n  z       return 0    END  -bash-3 2  gcc test-round c -bash-3 2    a out       x      5000000000000001 000000 round x      5000000000000001 000000 floor x 0 5  5000000000000002 000000   This is http   bugs squeak org view php id 7134  Use a solution like the one of  konik   My own robust version would be something like   double round double x        double truncated roundedFraction      double fraction   modf x   amp truncated       modf 2 0 fraction   amp roundedFraction       return truncated   roundedFraction      Another reason to avoid floor x 0 5  is given here

User · Answer

There is no need to implement anything  so I m not sure why so many answers involve defines  functions  or methods   In C99  We have the following and and header  lt tgmath h gt  for type-generic macros    include  lt math h gt  double round  double x   float roundf  float x   long double roundl  long double x     If you cannot compile this  you have probably left out the math library   A command similar to this works on every C compiler I have  several    gcc -lm -std c99       In C  11  We have the following and additional overloads in  include  lt cmath gt  that rely on IEEE double precision floating point    include  lt math h gt  double round  double x   float round  float x   long double round  long double x   double round  T x     There are equivalents in the std namespace too   If you cannot compile this  you may be using C compilation instead of C     The following basic command produces neither errors nor warnings with g   6 3 1  x86 64-w64-mingw32-g   6 3 0  clang-x86 64   3 8 0  and Visual C   2015 Community   g   -std c  11 -Wall   With Ordinal Division  When dividing two ordinal numbers  where T is short  int  long  or another ordinal  the rounding expression is this   T roundedQuotient    2   integerNumerator   1         2   integerDenominator     Accuracy  There is no doubt that odd looking inaccuracies appear in floating point operations  but this is only when the numbers appear  and has little to do with rounding   The source is not just the number of significant digits in the mantissa of the IEEE representation of a floating point number  it is related to our decimal thinking as humans   Ten is the product of five and two  and 5 and 2 are relatively prime   Therefore the IEEE floating point standards cannot possibly be represented perfectly as decimal numbers for all binary digital representations   This is not an issue with the rounding algorithms   It is mathematical reality that should be considered during the selection of types and the design of computations  data entry  and display of numbers   If an application displays the digits that show these decimal-binary conversion issues  then the application is visually expressing accuracy that does not exist in digital reality and should be changed

User · Answer

If you need to be able to compile code in environments that support the C  11 standard  but also need to be able to compile that same code in environments that don t support it  you could use a function macro to choose between std  round   and a custom function for each system   Just pass -DCPP11 or  DCPP11 to the C  11-compliant compiler  or use its built-in version macros   and make a header like this      File  rounding h  include  lt cmath gt    ifdef CPP11      define ROUND x  std  round x   else       CPP11        inline double myRound double x            return  x  gt   0 0   std  floor x   0 5    std  ceil x - 0 5                define ROUND x  myRound x   endif      CPP11      For a quick example  see http   ideone com zal709    This approximates std  round   in environments that aren t C  11-compliant  including preservation of the sign bit for -0 0   It may cause a slight performance hit  however  and will likely have issues with rounding certain known  problem  floating-point values such as 0 49999999999999994 or similar values   Alternatively  if you have access to a C  11-compliant compiler  you could just grab std  round   from its  lt cmath gt  header  and use it to make your own header that defines the function if it s not already defined   Note that this may not be an optimal solution  however  especially if you need to compile for multiple platforms

User · Answer

Convert the float to a string    We might use stringstream  but it looks like it truncates the float to only   5 decimal points  maybe that s what you want anyway  P   float MyFloat   5 11133333311111333  float NewConvertedFloat   0 0  string FirstString        string SecondString        stringstream ss  stringstream  in   stringstream  out   ss  lt  lt  MyFloat  FirstString   ss str        Take out how ever many decimal places you want     this is a string it includes the point  SecondString   FirstString substr 0 5     whatever precision decimal place you want     Convert it back to a float stringstream SecondString   gt  gt  NewConvertedFloat  cout  lt  lt  NewConvertedFloat  system  pause      It might be an inefficient dirty way of conversion but heck  it works lol  And it s good  because it applies to the actual float  Not just affecting the output visually

User · Answer

If you need to be able to compile code in environments that support the C  11 standard  but also need to be able to compile that same code in environments that don t support it  you could use a function macro to choose between std  round   and a custom function for each system   Just pass -DCPP11 or  DCPP11 to the C  11-compliant compiler  or use its built-in version macros   and make a header like this      File  rounding h  include  lt cmath gt    ifdef CPP11      define ROUND x  std  round x   else       CPP11        inline double myRound double x            return  x  gt   0 0   std  floor x   0 5    std  ceil x - 0 5                define ROUND x  myRound x   endif      CPP11      For a quick example  see http   ideone com zal709    This approximates std  round   in environments that aren t C  11-compliant  including preservation of the sign bit for -0 0   It may cause a slight performance hit  however  and will likely have issues with rounding certain known  problem  floating-point values such as 0 49999999999999994 or similar values   Alternatively  if you have access to a C  11-compliant compiler  you could just grab std  round   from its  lt cmath gt  header  and use it to make your own header that defines the function if it s not already defined   Note that this may not be an optimal solution  however  especially if you need to compile for multiple platforms

User · Answer

There s no round   in the C  98 standard library  You can write one yourself though  The following is an implementation of round-half-up   double round double d      return floor d   0 5       The probable reason there is no round function in the C  98 standard library is that it can in fact be implemented in different ways  The above is one common way but there are others such as round-to-even  which is less biased and generally better if you re going to do a lot of rounding  it s a bit more complex to implement though

User · Answer

Boost offers a simple set of rounding functions    include  lt boost math special functions round hpp gt   double a   boost  math  round 1 5      Yields 2 0 int b   boost  math  iround 1 5      Yields 2 as an integer   For more information  see the Boost documentation   Edit  Since C  11  there are std  round  std  lround  and std  llround

User · Answer

These days it shouldn t be a problem to use a C  11 compiler which includes a C99 C  11 math library   But then the question becomes  which rounding function do you pick   C99 C  11 round   is often not actually the rounding function you want   It uses a funky rounding mode that rounds away from 0 as a tie-break on half-way cases   -xxx 5000    If you do specifically want that rounding mode  or you re targeting a C   implementation where round   is faster than rint    then use it  or emulate its behaviour with one of the other answers on this question which took it at face value and carefully reproduced that specific rounding behaviour    round   s rounding is different from the IEEE754 default round to nearest mode with even as a tie-break   Nearest-even avoids statistical bias in the average magnitude of numbers  but does bias towards even numbers   There are two math library rounding functions that use the current default rounding mode  std  nearbyint   and std  rint    both added in C99 C  11  so they re available any time std  round   is   The only difference is that nearbyint never raises FE INEXACT   Prefer rint   for performance reasons  gcc and clang both inline it more easily  but gcc never inlines nearbyint    even with -ffast-math     gcc clang for x86-64 and AArch64  I put some test functions on Matt Godbolt s Compiler Explorer  where you can see source   asm output  for multiple compilers    For more about reading compiler output  see this Q amp A  and Matt s CppCon2017 talk     What Has My Compiler Done for Me Lately  Unbolting the Compiler s Lid      In FP code  it s usually a big win to inline small functions   Especially on non-Windows  where the standard calling convention has no call-preserved registers  so the compiler can t keep any FP values in XMM registers across a call   So even if you don t really know asm  you can still easily see whether it s just a tail-call to the library function or whether it inlined to one or two math instructions   Anything that inlines to one or two instructions is better than a function call  for this particular task on x86 or ARM    On x86  anything that inlines to SSE4 1 roundsd can auto-vectorize with SSE4 1 roundpd  or AVX vroundpd     FP- integer conversions are also available in packed SIMD form  except for FP- 64-bit integer which requires AVX512     std  nearbyint      x86 clang  inlines to a single insn with -msse4 1  x86 gcc  inlines to a single insn only with -msse4 1 -ffast-math  and only on gcc 5 4 and earlier   Later gcc never inlines it  maybe they didn t realize that one of the immediate bits can suppress the inexact exception   That s what clang uses  but older gcc uses the same immediate as for rint when it does inline it  AArch64 gcc6 3  inlines to a single insn by default   std  rint    x86 clang  inlines to a single insn with -msse4 1 x86 gcc7  inlines to a single insn with -msse4 1    Without SSE4 1  inlines to several instructions  x86 gcc6 x and earlier  inlines to a single insn with -ffast-math -msse4 1  AArch64 gcc  inlines to a single insn by default  std  round    x86 clang  doesn t inline x86 gcc  inlines to multiple instructions with -ffast-math -msse4 1  requiring two vector constants  AArch64 gcc  inlines to a single instruction  HW support for this rounding mode as well as IEEE default and most others    std  floor   std  ceil   std  trunc   x86 clang  inlines to a single insn with -msse4 1 x86 gcc7 x  inlines to a single insn with -msse4 1 x86 gcc6 x and earlier  inlines to a single insn with -ffast-math -msse4 1 AArch64 gcc  inlines by default to a single instruction      Rounding to int   long   long long   You have two options here  use lrint  like rint but returns long  or long long for llrint   or use an FP- FP rounding function and then convert to an integer type the normal way  with truncation    Some compilers optimize one way better than the other   long l   lrint x    int  i    int rint x     Note that int i   lrint x  converts float or double -  long first  and then truncates the integer to int   This makes a difference for out-of-range integers  Undefined Behaviour in C    but well-defined for the x86 FP -  int instructions  which the compiler will emit unless it sees the UB at compile time while doing constant propagation  then it s allowed to make code that breaks if it s ever executed    On x86  an FP- integer conversion that overflows the integer produces INT MIN or LLONG MIN  a bit-pattern of 0x8000000 or the 64-bit equivalent  with just the sign-bit set    Intel calls this the  integer indefinite  value    See the cvttsd2si manual entry  the SSE2 instruction that converts  with truncation  scalar double to signed integer   It s available with 32-bit or 64-bit integer destination  in 64-bit mode only    There s also a cvtsd2si  convert with current rounding mode   which is what we d like the compiler to emit  but unfortunately gcc and clang won t do that without -ffast-math   Also beware that FP to from unsigned int   long is less efficient on x86  without AVX512    Conversion to 32-bit unsigned on a 64-bit machine is pretty cheap  just convert to 64-bit signed and truncate   But otherwise it s significantly slower    x86 clang with without -ffast-math -msse4 1   int long rint inlines to roundsd   cvttsd2si    missed optimization to cvtsd2si    lrint doesn t inline at all  x86 gcc6 x and earlier without -ffast-math  neither way inlines x86 gcc7 without -ffast-math   int long rint rounds and converts separately  with 2 total instructions of SSE4 1 is enabled  otherwise with a bunch of code inlined for rint without roundsd    lrint doesn t inline  x86 gcc with -ffast-math  all ways inline to cvtsd2si  optimal   no need for SSE4 1  AArch64 gcc6 3 without -ffast-math   int long rint inlines to 2 instructions   lrint doesn t inline AArch64 gcc6 3 with -ffast-math   int long rint compiles to a call to lrint   lrint doesn t inline   This may be a missed optimization unless the two instructions we get without -ffast-math are very slow

User · Answer

There is no need to implement anything  so I m not sure why so many answers involve defines  functions  or methods   In C99  We have the following and and header  lt tgmath h gt  for type-generic macros    include  lt math h gt  double round  double x   float roundf  float x   long double roundl  long double x     If you cannot compile this  you have probably left out the math library   A command similar to this works on every C compiler I have  several    gcc -lm -std c99       In C  11  We have the following and additional overloads in  include  lt cmath gt  that rely on IEEE double precision floating point    include  lt math h gt  double round  double x   float round  float x   long double round  long double x   double round  T x     There are equivalents in the std namespace too   If you cannot compile this  you may be using C compilation instead of C     The following basic command produces neither errors nor warnings with g   6 3 1  x86 64-w64-mingw32-g   6 3 0  clang-x86 64   3 8 0  and Visual C   2015 Community   g   -std c  11 -Wall   With Ordinal Division  When dividing two ordinal numbers  where T is short  int  long  or another ordinal  the rounding expression is this   T roundedQuotient    2   integerNumerator   1         2   integerDenominator     Accuracy  There is no doubt that odd looking inaccuracies appear in floating point operations  but this is only when the numbers appear  and has little to do with rounding   The source is not just the number of significant digits in the mantissa of the IEEE representation of a floating point number  it is related to our decimal thinking as humans   Ten is the product of five and two  and 5 and 2 are relatively prime   Therefore the IEEE floating point standards cannot possibly be represented perfectly as decimal numbers for all binary digital representations   This is not an issue with the rounding algorithms   It is mathematical reality that should be considered during the selection of types and the design of computations  data entry  and display of numbers   If an application displays the digits that show these decimal-binary conversion issues  then the application is visually expressing accuracy that does not exist in digital reality and should be changed

User · Answer

It s usually implemented as floor value   0 5    Edit  and it s probably not called round since there are at least three rounding algorithms I know of  round to zero  round to closest integer  and banker s rounding  You are asking for round to closest integer

User · Answer

I use the following implementation of round in asm for x86 architecture and MS VS specific C       forceinline int Round const double v        int r        asm               FLD     v         FISTP   r         FWAIT            return r      UPD  to return double value    forceinline double dround const double v        double r        asm               FLD     v         FRNDINT         FSTP    r         FWAIT            return r      Output   dround 0 1   0 000000000000000 dround -0 1   -0 000000000000000 dround 0 9   1 000000000000000 dround -0 9   -1 000000000000000 dround 1 1   1 000000000000000 dround -1 1   -1 000000000000000 dround 0 49999999999999994   0 000000000000000 dround -0 49999999999999994   -0 000000000000000 dround 0 5   0 000000000000000 dround -0 5   -0 000000000000000

User · Answer

Based on Kalaxy s response  the following is a templated solution that rounds any floating point number to the nearest integer type based on natural rounding  It also throws an error in debug mode if the value is out of range of the integer type  thereby serving roughly as a viable library function          round a floating point number to the nearest integer     template  lt typename Arg gt      int Round Arg arg         ifndef NDEBUG            check that the argument can be rounded given the return type          if                Arg std  numeric limits lt int gt   max    lt  arg    Arg  0 5                  Arg std  numeric limits lt int gt   lowest    gt  arg -  Arg  0 5                                      throw std  overflow error  out of bounds               endif          return  arg  gt   Arg  0 0     int  r    Arg  0 5     int  r -  Arg  0 5

User · Answer

There s no round   in the C  98 standard library  You can write one yourself though  The following is an implementation of round-half-up   double round double d      return floor d   0 5       The probable reason there is no round function in the C  98 standard library is that it can in fact be implemented in different ways  The above is one common way but there are others such as round-to-even  which is less biased and generally better if you re going to do a lot of rounding  it s a bit more complex to implement though

User · Answer

I use the following implementation of round in asm for x86 architecture and MS VS specific C       forceinline int Round const double v        int r        asm               FLD     v         FISTP   r         FWAIT            return r      UPD  to return double value    forceinline double dround const double v        double r        asm               FLD     v         FRNDINT         FSTP    r         FWAIT            return r      Output   dround 0 1   0 000000000000000 dround -0 1   -0 000000000000000 dround 0 9   1 000000000000000 dround -0 9   -1 000000000000000 dround 1 1   1 000000000000000 dround -1 1   -1 000000000000000 dround 0 49999999999999994   0 000000000000000 dround -0 49999999999999994   -0 000000000000000 dround 0 5   0 000000000000000 dround -0 5   -0 000000000000000

User · Answer

Since C   11 simply   include  lt cmath gt  std  round 1 1   or to get int static cast lt int gt  std  round 1 1

User · Answer

Function double round double  with the use of the modf function   double round double x        using namespace std       if   numeric limits lt double gt   max   - 0 5   lt   x          return numeric limits lt double gt   max         if   -1 std  numeric limits lt double gt   max     0 5   gt  x          return  -1 std  numeric limits lt double gt   max          double intpart      double fractpart   modf x   amp intpart        if  fractpart  gt   0 5          return  intpart   1       else if  fractpart  gt   -0 5          return intpart      else         return  intpart - 1           To be compile clean  includes  math h  and  limits  are necessary  The function works according to a following rounding schema    round of 5 0 is 5 0 round of 3 8 is 4 0 round of 2 3 is 2 0 round of 1 5 is 2 0 round of 0 501 is 1 0 round of 0 5 is 1 0 round of 0 499 is 0 0 round of 0 01 is 0 0 round of 0 0 is 0 0 round of -0 01 is -0 0 round of -0 499 is -0 0 round of -0 5 is -0 0 round of -0 501 is -1 0 round of -1 5 is -1 0 round of -2 3 is -2 0 round of -3 8 is -4 0 round of -5 0 is -5 0

User · Answer

The C  03 standard relies on the C90 standard for what the standard calls the Standard C Library which is covered in the draft C  03 standard  closest publicly available draft standard to C  03 is N1804  section 1 2 Normative references      The library described in clause 7 of ISO IEC 9899 1990 and clause 7 of   ISO IEC 9899 Amd 1 1995 is hereinafter called the Standard C   Library 1    If we go to the C documentation for round  lround  llround on cppreference we can see that round and related functions are part of C99 and thus won t be available in C  03 or prior    In C  11 this changes since C  11 relies on the C99 draft standard for C standard library and therefore provides std  round and for integral return types std  lround  std  llround     include  lt iostream gt   include  lt cmath gt   int main         std  cout  lt  lt  std  round  0 4    lt  lt       lt  lt  std  lround  0 4    lt  lt       lt  lt  std  llround  0 4    lt  lt  std  endl       std  cout  lt  lt  std  round  0 5    lt  lt       lt  lt  std  lround  0 5    lt  lt       lt  lt  std  llround  0 5    lt  lt  std  endl       std  cout  lt  lt  std  round  0 6    lt  lt       lt  lt  std  lround  0 6    lt  lt       lt  lt  std  llround  0 6    lt  lt  std  endl       Another option also from C99 would be std  trunc which      Computes nearest integer not greater in magnitude than arg     include  lt iostream gt   include  lt cmath gt   int main         std  cout  lt  lt  std  trunc  0 4    lt  lt  std  endl       std  cout  lt  lt  std  trunc  0 9    lt  lt  std  endl       std  cout  lt  lt  std  trunc  1 1    lt  lt  std  endl        If you need to support non C  11 applications your best bet would be to use boost round  iround  lround  llround or boost trunc   Rolling your own version of round is hard  Rolling your own is probably not worth the effort as Harder than it looks  rounding float to nearest integer  part 1  Rounding float to nearest integer  part 2 and Rounding float to nearest integer  part 3 explain   For example a common roll your implementation using std  floor and adding 0 5 does not work for all inputs   double myround double d      return std  floor d   0 5       One input this will fail for is 0 49999999999999994   see it live    Another common implementation involves casting a floating point type to an integral type  which can invoke undefined behavior in the case where the integral part can not be represented in the destination type  We can see this from the draft C   standard section 4 9 Floating-integral conversions which says  emphasis mine       A prvalue of a floating point type can be converted to a prvalue of an   integer type  The conversion truncates  that is  the fractional part   is discarded  The behavior is undefined if the truncated value cannot   be represented in the destination type         For example   float myround float f      return static cast lt float gt   static cast lt unsigned int gt   f           Given std  numeric limits lt unsigned int gt   max   is 4294967295 then the following call   myround  4294967296 5f      will cause overflow   see it live    We can see how difficult this really is by looking at this answer to Concise way to implement round   in C  which referencing newlibs version of single precision float round  It is a very long function for something which seems simple  It seems unlikely that anyone without intimate knowledge of floating point implementations could correctly implement this function   float roundf x      int signbit      uint32 t w       Most significant word  least significant word       int exponent less 127     GET FLOAT WORD w  x         Extract sign bit       signbit   w  amp  0x80000000        Extract exponent field       exponent less 127    int   w  amp  0x7f800000   gt  gt  23  - 127     if  exponent less 127  lt  23              if  exponent less 127  lt  0                      w  amp   0x80000000            if  exponent less 127    -1                 Result is  1 0 or -1 0                 w        uint32 t 127  lt  lt  23                   else                     unsigned int exponent mask   0x007fffff  gt  gt  exponent less 127            if   w  amp  exponent mask     0                 x has an integral value                 return x             w    0x00400000  gt  gt  exponent less 127            w  amp    exponent mask                    else             if  exponent less 127    128             x is NaN or infinite             return x   x        else         return x          SET FLOAT WORD x  w     return x      On the other hand if none of the other solutions are usable newlib could potentially be an option since it is a well tested implementation

User · Answer

It s usually implemented as floor value   0 5    Edit  and it s probably not called round since there are at least three rounding algorithms I know of  round to zero  round to closest integer  and banker s rounding  You are asking for round to closest integer

User · Answer

It s available since C  11 in cmath  according to http   www open-std org jtc1 sc22 wg21 docs papers 2012 n3337 pdf    include  lt cmath gt   include  lt iostream gt   int main int argc  char   argv      std  cout  lt  lt   round 0 5   t   lt  lt  round 0 5   lt  lt  std  endl    std  cout  lt  lt   round -0 5   t   lt  lt  round -0 5   lt  lt  std  endl    std  cout  lt  lt   round 1 4   t   lt  lt  round 1 4   lt  lt  std  endl    std  cout  lt  lt   round -1 4   t   lt  lt  round -1 4   lt  lt  std  endl    std  cout  lt  lt   round 1 6   t   lt  lt  round 1 6   lt  lt  std  endl    std  cout  lt  lt   round -1 6   t   lt  lt  round -1 6   lt  lt  std  endl    return 0      Output   round 0 5    1 round -0 5   -1 round 1 4    1 round -1 4   -1 round 1 6    2 round -1 6   -2

User · Answer

I did this    include  lt cmath h gt   using namespace std   double roundh double number  int place           place   decimal point  Putting in 0 will make it round to whole                               number  putting in 1 will round to the                               tenths digit              number    10 place      int istack    int floor number       int out   number-istack      if  out  lt  0 5           floor number           number    10 place          return number            if  out  gt  0 4            ceil number           number    10 place          return number

User · Answer

There are 2 problems we are looking at    rounding conversions  type conversion    Rounding conversions mean rounding    float double to nearest floor ceil float double  May be your problem ends here  But if you are expected to return Int Long  you need to perform type conversion  and thus  Overflow  problem might hit your solution  SO  do a check for error in your function  long round double x       assert x  gt   LONG MIN-0 5      assert x  lt   LONG MAX 0 5      if  x  gt   0        return  long   x 0 5      return  long   x-0 5       define round x    x   lt  LONG MIN-0 5     x   gt  LONG MAX 0 5          error       x  gt  0  long   x  0 5   long   x -0 5     from   http   www cs tut fi  jkorpela round html

User · Answer

Best way to rounding off a floating value by  n  decimal places  is as following with in O 1  time -  We have to round off the value by 3 places i e  n 3 So   float a 47 8732355  printf    3f  a

User · Answer

Convert the float to a string    We might use stringstream  but it looks like it truncates the float to only   5 decimal points  maybe that s what you want anyway  P   float MyFloat   5 11133333311111333  float NewConvertedFloat   0 0  string FirstString        string SecondString        stringstream ss  stringstream  in   stringstream  out   ss  lt  lt  MyFloat  FirstString   ss str        Take out how ever many decimal places you want     this is a string it includes the point  SecondString   FirstString substr 0 5     whatever precision decimal place you want     Convert it back to a float stringstream SecondString   gt  gt  NewConvertedFloat  cout  lt  lt  NewConvertedFloat  system  pause      It might be an inefficient dirty way of conversion but heck  it works lol  And it s good  because it applies to the actual float  Not just affecting the output visually

User · Answer

There are 2 problems we are looking at    rounding conversions  type conversion    Rounding conversions mean rounding    float double to nearest floor ceil float double  May be your problem ends here  But if you are expected to return Int Long  you need to perform type conversion  and thus  Overflow  problem might hit your solution  SO  do a check for error in your function  long round double x       assert x  gt   LONG MIN-0 5      assert x  lt   LONG MAX 0 5      if  x  gt   0        return  long   x 0 5      return  long   x-0 5       define round x    x   lt  LONG MIN-0 5     x   gt  LONG MAX 0 5          error       x  gt  0  long   x  0 5   long   x -0 5     from   http   www cs tut fi  jkorpela round html

User · Answer

As pointed out in comments and other answers  the ISO C   standard library did not add round   until ISO C  11  when this function was pulled in by reference to the ISO C99 standard math library   For positive operands in      ub  round x     floor  x   0 5   where ub is 223 for float when mapped to IEEE-754  2008  binary32  and 252 for double when it is mapped to IEEE-754  2008   binary64  The numbers 23 and 52 correspond to the number of stored mantissa bits in these two floating-point formats  For positive operands in   0      round x     0  and for positive operands in  ub   8  round x     x  As the function is symmetric about the x-axis  negative arguments x can be handled according to round -x     -round x    This leads to the compact code below  It compiles into a reasonable number of machine instructions across various platforms  I observed the most compact code on GPUs  where my roundf   requires about a dozen instructions  Depending on processor architecture and toolchain  this floating-point based approach could be either faster or slower than the integer-based implementation from newlib referenced in a different answer   I tested my roundf   exhaustively against the newlib roundf   implementation using Intel compiler version 13  with both  fp strict and  fp fast  I also checked that  the newlib version matches the roundf   in the mathimf library of the Intel compiler  Exhaustive testing is not possible for double-precision round    however the code is structurally identical to the single-precision implementation    include  lt stdio h gt   include  lt stdlib h gt   include  lt stdint h gt   include  lt string h gt   include  lt math h gt   float my roundf  float x        const float half   0 5f      const float one   2   half      const float lbound   half      const float ubound   1L  lt  lt  23      float a  f  r  s  t      s    x  lt  0     -one    one      a   x   s      t    a  lt  lbound    x   s      f    a  lt  lbound    0   floorf  a   half       r    a  gt  ubound    x    t   f       return r     double my round  double x        const double half   0 5      const double one   2   half      const double lbound   half      const double ubound   1ULL  lt  lt  52      double a  f  r  s  t      s    x  lt  0     -one    one      a   x   s      t    a  lt  lbound    x   s      f    a  lt  lbound    0   floor  a   half       r    a  gt  ubound    x    t   f       return r     uint32 t float as uint  float a        uint32 t r      memcpy   amp r   amp a  sizeof r        return r     float uint as float  uint32 t a        float r      memcpy   amp r   amp a  sizeof r        return r     float newlib roundf  float x        uint32 t w      int exponent less 127       w   float as uint x          Extract exponent field         exponent less 127    int   w  amp  0x7f800000   gt  gt  23  - 127      if  exponent less 127  lt  23            if  exponent less 127  lt  0                   Extract sign bit                 w  amp   0x80000000              if  exponent less 127    -1                       Result is  1 0 or -1 0                     w      uint32 t 127  lt  lt  23                           else               uint32 t exponent mask   0x007fffff  gt  gt  exponent less 127              if   w  amp  exponent mask     0                       x has an integral value                     return x                            w    0x00400000  gt  gt  exponent less 127              w  amp    exponent mask                  else           if  exponent less 127    128                   x is NaN or infinite so raise FE INVALID by adding                return x   x            else               return x                      x   uint as float  w       return x     int main  void        uint32 t argi  resi  refi      float arg  res  ref       argi   0      do           arg   uint as float  argi           ref   newlib roundf  arg           res   my roundf  arg           resi   float as uint  res           refi   float as uint  ref           if  resi    refi       check for identical bit pattern             printf        arg  08x  res  08x  ref  08x n   argi  resi  refi               return EXIT FAILURE                    argi          while  argi       return EXIT SUCCESS

User · Answer

Beware of floor x 0 5   Here is what can happen for odd numbers in range  2 52 2 53    -bash-3 2  cat  gt test-round c  lt  lt END   include  lt math h gt   include  lt stdio h gt   int main         double x 5000000000000001 0      double y round x       double z floor x 0 5       printf        x       f n  x       printf  round x       f n  y       printf  floor x 0 5   f n  z       return 0    END  -bash-3 2  gcc test-round c -bash-3 2    a out       x      5000000000000001 000000 round x      5000000000000001 000000 floor x 0 5  5000000000000002 000000   This is http   bugs squeak org view php id 7134  Use a solution like the one of  konik   My own robust version would be something like   double round double x        double truncated roundedFraction      double fraction   modf x   amp truncated       modf 2 0 fraction   amp roundedFraction       return truncated   roundedFraction      Another reason to avoid floor x 0 5  is given here

User · Answer

As pointed out in comments and other answers  the ISO C   standard library did not add round   until ISO C  11  when this function was pulled in by reference to the ISO C99 standard math library   For positive operands in      ub  round x     floor  x   0 5   where ub is 223 for float when mapped to IEEE-754  2008  binary32  and 252 for double when it is mapped to IEEE-754  2008   binary64  The numbers 23 and 52 correspond to the number of stored mantissa bits in these two floating-point formats  For positive operands in   0      round x     0  and for positive operands in  ub   8  round x     x  As the function is symmetric about the x-axis  negative arguments x can be handled according to round -x     -round x    This leads to the compact code below  It compiles into a reasonable number of machine instructions across various platforms  I observed the most compact code on GPUs  where my roundf   requires about a dozen instructions  Depending on processor architecture and toolchain  this floating-point based approach could be either faster or slower than the integer-based implementation from newlib referenced in a different answer   I tested my roundf   exhaustively against the newlib roundf   implementation using Intel compiler version 13  with both  fp strict and  fp fast  I also checked that  the newlib version matches the roundf   in the mathimf library of the Intel compiler  Exhaustive testing is not possible for double-precision round    however the code is structurally identical to the single-precision implementation    include  lt stdio h gt   include  lt stdlib h gt   include  lt stdint h gt   include  lt string h gt   include  lt math h gt   float my roundf  float x        const float half   0 5f      const float one   2   half      const float lbound   half      const float ubound   1L  lt  lt  23      float a  f  r  s  t      s    x  lt  0     -one    one      a   x   s      t    a  lt  lbound    x   s      f    a  lt  lbound    0   floorf  a   half       r    a  gt  ubound    x    t   f       return r     double my round  double x        const double half   0 5      const double one   2   half      const double lbound   half      const double ubound   1ULL  lt  lt  52      double a  f  r  s  t      s    x  lt  0     -one    one      a   x   s      t    a  lt  lbound    x   s      f    a  lt  lbound    0   floor  a   half       r    a  gt  ubound    x    t   f       return r     uint32 t float as uint  float a        uint32 t r      memcpy   amp r   amp a  sizeof r        return r     float uint as float  uint32 t a        float r      memcpy   amp r   amp a  sizeof r        return r     float newlib roundf  float x        uint32 t w      int exponent less 127       w   float as uint x          Extract exponent field         exponent less 127    int   w  amp  0x7f800000   gt  gt  23  - 127      if  exponent less 127  lt  23            if  exponent less 127  lt  0                   Extract sign bit                 w  amp   0x80000000              if  exponent less 127    -1                       Result is  1 0 or -1 0                     w      uint32 t 127  lt  lt  23                           else               uint32 t exponent mask   0x007fffff  gt  gt  exponent less 127              if   w  amp  exponent mask     0                       x has an integral value                     return x                            w    0x00400000  gt  gt  exponent less 127              w  amp    exponent mask                  else           if  exponent less 127    128                   x is NaN or infinite so raise FE INVALID by adding                return x   x            else               return x                      x   uint as float  w       return x     int main  void        uint32 t argi  resi  refi      float arg  res  ref       argi   0      do           arg   uint as float  argi           ref   newlib roundf  arg           res   my roundf  arg           resi   float as uint  res           refi   float as uint  ref           if  resi    refi       check for identical bit pattern             printf        arg  08x  res  08x  ref  08x n   argi  resi  refi               return EXIT FAILURE                    argi          while  argi       return EXIT SUCCESS

User · Answer

It s available since C  11 in cmath  according to http   www open-std org jtc1 sc22 wg21 docs papers 2012 n3337 pdf    include  lt cmath gt   include  lt iostream gt   int main int argc  char   argv      std  cout  lt  lt   round 0 5   t   lt  lt  round 0 5   lt  lt  std  endl    std  cout  lt  lt   round -0 5   t   lt  lt  round -0 5   lt  lt  std  endl    std  cout  lt  lt   round 1 4   t   lt  lt  round 1 4   lt  lt  std  endl    std  cout  lt  lt   round -1 4   t   lt  lt  round -1 4   lt  lt  std  endl    std  cout  lt  lt   round 1 6   t   lt  lt  round 1 6   lt  lt  std  endl    std  cout  lt  lt   round -1 6   t   lt  lt  round -1 6   lt  lt  std  endl    return 0      Output   round 0 5    1 round -0 5   -1 round 1 4    1 round -1 4   -1 round 1 6    2 round -1 6   -2

User · Answer

Since C   11 simply   include  lt cmath gt  std  round 1 1   or to get int static cast lt int gt  std  round 1 1

User · Answer

It may be worth noting that if you wanted an integer result from the rounding you don t need to pass it through either ceil or floor   I e    int round int  double r         return  r  gt  0 0     r   0 5     r - 0 5

User · Answer

These days it shouldn t be a problem to use a C  11 compiler which includes a C99 C  11 math library   But then the question becomes  which rounding function do you pick   C99 C  11 round   is often not actually the rounding function you want   It uses a funky rounding mode that rounds away from 0 as a tie-break on half-way cases   -xxx 5000    If you do specifically want that rounding mode  or you re targeting a C   implementation where round   is faster than rint    then use it  or emulate its behaviour with one of the other answers on this question which took it at face value and carefully reproduced that specific rounding behaviour    round   s rounding is different from the IEEE754 default round to nearest mode with even as a tie-break   Nearest-even avoids statistical bias in the average magnitude of numbers  but does bias towards even numbers   There are two math library rounding functions that use the current default rounding mode  std  nearbyint   and std  rint    both added in C99 C  11  so they re available any time std  round   is   The only difference is that nearbyint never raises FE INEXACT   Prefer rint   for performance reasons  gcc and clang both inline it more easily  but gcc never inlines nearbyint    even with -ffast-math     gcc clang for x86-64 and AArch64  I put some test functions on Matt Godbolt s Compiler Explorer  where you can see source   asm output  for multiple compilers    For more about reading compiler output  see this Q amp A  and Matt s CppCon2017 talk     What Has My Compiler Done for Me Lately  Unbolting the Compiler s Lid      In FP code  it s usually a big win to inline small functions   Especially on non-Windows  where the standard calling convention has no call-preserved registers  so the compiler can t keep any FP values in XMM registers across a call   So even if you don t really know asm  you can still easily see whether it s just a tail-call to the library function or whether it inlined to one or two math instructions   Anything that inlines to one or two instructions is better than a function call  for this particular task on x86 or ARM    On x86  anything that inlines to SSE4 1 roundsd can auto-vectorize with SSE4 1 roundpd  or AVX vroundpd     FP- integer conversions are also available in packed SIMD form  except for FP- 64-bit integer which requires AVX512     std  nearbyint      x86 clang  inlines to a single insn with -msse4 1  x86 gcc  inlines to a single insn only with -msse4 1 -ffast-math  and only on gcc 5 4 and earlier   Later gcc never inlines it  maybe they didn t realize that one of the immediate bits can suppress the inexact exception   That s what clang uses  but older gcc uses the same immediate as for rint when it does inline it  AArch64 gcc6 3  inlines to a single insn by default   std  rint    x86 clang  inlines to a single insn with -msse4 1 x86 gcc7  inlines to a single insn with -msse4 1    Without SSE4 1  inlines to several instructions  x86 gcc6 x and earlier  inlines to a single insn with -ffast-math -msse4 1  AArch64 gcc  inlines to a single insn by default  std  round    x86 clang  doesn t inline x86 gcc  inlines to multiple instructions with -ffast-math -msse4 1  requiring two vector constants  AArch64 gcc  inlines to a single instruction  HW support for this rounding mode as well as IEEE default and most others    std  floor   std  ceil   std  trunc   x86 clang  inlines to a single insn with -msse4 1 x86 gcc7 x  inlines to a single insn with -msse4 1 x86 gcc6 x and earlier  inlines to a single insn with -ffast-math -msse4 1 AArch64 gcc  inlines by default to a single instruction      Rounding to int   long   long long   You have two options here  use lrint  like rint but returns long  or long long for llrint   or use an FP- FP rounding function and then convert to an integer type the normal way  with truncation    Some compilers optimize one way better than the other   long l   lrint x    int  i    int rint x     Note that int i   lrint x  converts float or double -  long first  and then truncates the integer to int   This makes a difference for out-of-range integers  Undefined Behaviour in C    but well-defined for the x86 FP -  int instructions  which the compiler will emit unless it sees the UB at compile time while doing constant propagation  then it s allowed to make code that breaks if it s ever executed    On x86  an FP- integer conversion that overflows the integer produces INT MIN or LLONG MIN  a bit-pattern of 0x8000000 or the 64-bit equivalent  with just the sign-bit set    Intel calls this the  integer indefinite  value    See the cvttsd2si manual entry  the SSE2 instruction that converts  with truncation  scalar double to signed integer   It s available with 32-bit or 64-bit integer destination  in 64-bit mode only    There s also a cvtsd2si  convert with current rounding mode   which is what we d like the compiler to emit  but unfortunately gcc and clang won t do that without -ffast-math   Also beware that FP to from unsigned int   long is less efficient on x86  without AVX512    Conversion to 32-bit unsigned on a 64-bit machine is pretty cheap  just convert to 64-bit signed and truncate   But otherwise it s significantly slower    x86 clang with without -ffast-math -msse4 1   int long rint inlines to roundsd   cvttsd2si    missed optimization to cvtsd2si    lrint doesn t inline at all  x86 gcc6 x and earlier without -ffast-math  neither way inlines x86 gcc7 without -ffast-math   int long rint rounds and converts separately  with 2 total instructions of SSE4 1 is enabled  otherwise with a bunch of code inlined for rint without roundsd    lrint doesn t inline  x86 gcc with -ffast-math  all ways inline to cvtsd2si  optimal   no need for SSE4 1  AArch64 gcc6 3 without -ffast-math   int long rint inlines to 2 instructions   lrint doesn t inline AArch64 gcc6 3 with -ffast-math   int long rint compiles to a call to lrint   lrint doesn t inline   This may be a missed optimization unless the two instructions we get without -ffast-math are very slow

User · Answer

It s usually implemented as floor value   0 5    Edit  and it s probably not called round since there are at least three rounding algorithms I know of  round to zero  round to closest integer  and banker s rounding  You are asking for round to closest integer

User · Answer

Boost offers a simple set of rounding functions    include  lt boost math special functions round hpp gt   double a   boost  math  round 1 5      Yields 2 0 int b   boost  math  iround 1 5      Yields 2 as an integer   For more information  see the Boost documentation   Edit  Since C  11  there are std  round  std  lround  and std  llround

User · Answer

A certain type of rounding is also implemented in Boost    include  lt iostream gt    include  lt boost numeric conversion converter hpp gt   template lt typename T  typename S gt  T round2 const S amp  x      typedef boost  numeric  conversion traits lt T  S gt  Traits    typedef boost  numeric  def overflow handler OverflowHandler    typedef boost  numeric  RoundEven lt typename Traits  source type gt  Rounder    typedef boost  numeric  converter lt T  S  Traits  OverflowHandler  Rounder gt  Converter    return Converter  convert x      int main       std  cout  lt  lt  round2 lt int  double gt  0 1   lt  lt       lt  lt  round2 lt int  double gt  -0 1   lt  lt       lt  lt  round2 lt int  double gt  -0 9   lt  lt  std  endl      Note that this works only if you do a to-integer conversion

User · Answer

There s no round   in the C  98 standard library  You can write one yourself though  The following is an implementation of round-half-up   double round double d      return floor d   0 5       The probable reason there is no round function in the C  98 standard library is that it can in fact be implemented in different ways  The above is one common way but there are others such as round-to-even  which is less biased and generally better if you re going to do a lot of rounding  it s a bit more complex to implement though

User · Answer

It s usually implemented as floor value   0 5    Edit  and it s probably not called round since there are at least three rounding algorithms I know of  round to zero  round to closest integer  and banker s rounding  You are asking for round to closest integer

User · Answer

The C  03 standard relies on the C90 standard for what the standard calls the Standard C Library which is covered in the draft C  03 standard  closest publicly available draft standard to C  03 is N1804  section 1 2 Normative references      The library described in clause 7 of ISO IEC 9899 1990 and clause 7 of   ISO IEC 9899 Amd 1 1995 is hereinafter called the Standard C   Library 1    If we go to the C documentation for round  lround  llround on cppreference we can see that round and related functions are part of C99 and thus won t be available in C  03 or prior    In C  11 this changes since C  11 relies on the C99 draft standard for C standard library and therefore provides std  round and for integral return types std  lround  std  llround     include  lt iostream gt   include  lt cmath gt   int main         std  cout  lt  lt  std  round  0 4    lt  lt       lt  lt  std  lround  0 4    lt  lt       lt  lt  std  llround  0 4    lt  lt  std  endl       std  cout  lt  lt  std  round  0 5    lt  lt       lt  lt  std  lround  0 5    lt  lt       lt  lt  std  llround  0 5    lt  lt  std  endl       std  cout  lt  lt  std  round  0 6    lt  lt       lt  lt  std  lround  0 6    lt  lt       lt  lt  std  llround  0 6    lt  lt  std  endl       Another option also from C99 would be std  trunc which      Computes nearest integer not greater in magnitude than arg     include  lt iostream gt   include  lt cmath gt   int main         std  cout  lt  lt  std  trunc  0 4    lt  lt  std  endl       std  cout  lt  lt  std  trunc  0 9    lt  lt  std  endl       std  cout  lt  lt  std  trunc  1 1    lt  lt  std  endl        If you need to support non C  11 applications your best bet would be to use boost round  iround  lround  llround or boost trunc   Rolling your own version of round is hard  Rolling your own is probably not worth the effort as Harder than it looks  rounding float to nearest integer  part 1  Rounding float to nearest integer  part 2 and Rounding float to nearest integer  part 3 explain   For example a common roll your implementation using std  floor and adding 0 5 does not work for all inputs   double myround double d      return std  floor d   0 5       One input this will fail for is 0 49999999999999994   see it live    Another common implementation involves casting a floating point type to an integral type  which can invoke undefined behavior in the case where the integral part can not be represented in the destination type  We can see this from the draft C   standard section 4 9 Floating-integral conversions which says  emphasis mine       A prvalue of a floating point type can be converted to a prvalue of an   integer type  The conversion truncates  that is  the fractional part   is discarded  The behavior is undefined if the truncated value cannot   be represented in the destination type         For example   float myround float f      return static cast lt float gt   static cast lt unsigned int gt   f           Given std  numeric limits lt unsigned int gt   max   is 4294967295 then the following call   myround  4294967296 5f      will cause overflow   see it live    We can see how difficult this really is by looking at this answer to Concise way to implement round   in C  which referencing newlibs version of single precision float round  It is a very long function for something which seems simple  It seems unlikely that anyone without intimate knowledge of floating point implementations could correctly implement this function   float roundf x      int signbit      uint32 t w       Most significant word  least significant word       int exponent less 127     GET FLOAT WORD w  x         Extract sign bit       signbit   w  amp  0x80000000        Extract exponent field       exponent less 127    int   w  amp  0x7f800000   gt  gt  23  - 127     if  exponent less 127  lt  23              if  exponent less 127  lt  0                      w  amp   0x80000000            if  exponent less 127    -1                 Result is  1 0 or -1 0                 w        uint32 t 127  lt  lt  23                   else                     unsigned int exponent mask   0x007fffff  gt  gt  exponent less 127            if   w  amp  exponent mask     0                 x has an integral value                 return x             w    0x00400000  gt  gt  exponent less 127            w  amp    exponent mask                    else             if  exponent less 127    128             x is NaN or infinite             return x   x        else         return x          SET FLOAT WORD x  w     return x      On the other hand if none of the other solutions are usable newlib could potentially be an option since it is a well tested implementation

User · Answer

You could round to n digits precision with   double round  double x     const double sd   1000    for accuracy to 3 decimal places return int x sd    x lt 0  -0 5   0 5   sd

User · Answer

It may be worth noting that if you wanted an integer result from the rounding you don t need to pass it through either ceil or floor   I e    int round int  double r         return  r  gt  0 0     r   0 5     r - 0 5

User · Answer

You could round to n digits precision with   double round  double x     const double sd   1000    for accuracy to 3 decimal places return int x sd    x lt 0  -0 5   0 5   sd

User · Answer

A certain type of rounding is also implemented in Boost    include  lt iostream gt    include  lt boost numeric conversion converter hpp gt   template lt typename T  typename S gt  T round2 const S amp  x      typedef boost  numeric  conversion traits lt T  S gt  Traits    typedef boost  numeric  def overflow handler OverflowHandler    typedef boost  numeric  RoundEven lt typename Traits  source type gt  Rounder    typedef boost  numeric  converter lt T  S  Traits  OverflowHandler  Rounder gt  Converter    return Converter  convert x      int main       std  cout  lt  lt  round2 lt int  double gt  0 1   lt  lt       lt  lt  round2 lt int  double gt  -0 1   lt  lt       lt  lt  round2 lt int  double gt  -0 9   lt  lt  std  endl      Note that this works only if you do a to-integer conversion

User · Answer

I did this    include  lt cmath h gt   using namespace std   double roundh double number  int place           place   decimal point  Putting in 0 will make it round to whole                               number  putting in 1 will round to the                               tenths digit              number    10 place      int istack    int floor number       int out   number-istack      if  out  lt  0 5           floor number           number    10 place          return number            if  out  gt  0 4            ceil number           number    10 place          return number

User · Answer

Based on Kalaxy s response  the following is a templated solution that rounds any floating point number to the nearest integer type based on natural rounding  It also throws an error in debug mode if the value is out of range of the integer type  thereby serving roughly as a viable library function          round a floating point number to the nearest integer     template  lt typename Arg gt      int Round Arg arg         ifndef NDEBUG            check that the argument can be rounded given the return type          if                Arg std  numeric limits lt int gt   max    lt  arg    Arg  0 5                  Arg std  numeric limits lt int gt   lowest    gt  arg -  Arg  0 5                                      throw std  overflow error  out of bounds               endif          return  arg  gt   Arg  0 0     int  r    Arg  0 5     int  r -  Arg  0 5

User · Answer

Best way to rounding off a floating value by  n  decimal places  is as following with in O 1  time -  We have to round off the value by 3 places i e  n 3 So   float a 47 8732355  printf    3f  a

User · Answer

There s no round   in the C  98 standard library  You can write one yourself though  The following is an implementation of round-half-up   double round double d      return floor d   0 5       The probable reason there is no round function in the C  98 standard library is that it can in fact be implemented in different ways  The above is one common way but there are others such as round-to-even  which is less biased and generally better if you re going to do a lot of rounding  it s a bit more complex to implement though

User · Answer

If you ultimately want to convert the double output of your round   function to an int  then the accepted solutions of this question will look something like   int roundint double r      return  int   r  gt  0 0    floor r   0 5    ceil r - 0 5        This clocks in at around 8 88 nbsp ns on my machine when passed in uniformly random values   The below is functionally equivalent  as far as I can tell  but clocks in at 2 48 nbsp ns on my machine  for a significant performance advantage   int roundint  double r      int tmp   static cast lt int gt   r     tmp     r-tmp gt   5  -  r-tmp lt  - 5     return tmp      Among the reasons for the better performance is the skipped branching

[c++] round() for float in C++

Examples related to c++

Examples related to floating-point

Examples related to rounding