[c#] How do I get the directory from a file's full path?

What is the simplest way to get the directory that a file is in? I'm using this to set a working directory.

string filename = @"C:\MyDirectory\MyFile.bat";

In this example, I should get "C:\MyDirectory".

You can get the current Application Path using:

string AssemblyPath = Path.GetDirectoryName(System.Reflection.Assembly.GetExecutingAssembly().Location).ToString();

Good Luck!

Path.GetDirectoryName(Context.Parameters["assemblypath"])

 string path= @"C:\Users\username\Desktop\FolderName"
  string Dirctory = new FileInfo(path).Name.ToString();
//output FolderName

System.IO.Path.GetDirectoryName(filename)

First, you have to use System.IO namespace. Then;

string filename = @"C:\MyDirectory\MyFile.bat";
string newPath = Path.GetFullPath(fileName);

or

string newPath = Path.GetFullPath(openFileDialog1.FileName));

You can use Path.GetDirectoryName and just pass in the filename.

MSDN Link

If you are working with a FileInfo object, then there is an easy way to extract a string representation of the directory's full path via the DirectoryName property.

Description of the FileInfo.DirectoryName Property via MSDN:

Gets a string representing the directory's full path.

Sample usage:

string filename = @"C:\MyDirectory\MyFile.bat";
FileInfo fileInfo = new FileInfo(filename);
string directoryFullPath = fileInfo.DirectoryName; // contains "C:\MyDirectory"

Link to the MSDN documentation.

Path.GetDirectoryName(filename);

In my case, I needed to find the directory name of a full path (of a directory) so I simply did:

var dirName = path.Split('\\').Last();

You can use System.IO.Path.GetDirectoryName(fileName), or turn the path into a FileInfo using FileInfo.Directory.

If you're doing other things with the path, the FileInfo class may have advantages.

Use below mentioned code to get the folder path

Path.GetDirectoryName(filename);

This will return "C:\MyDirectory" in your case

You can use Path.GetFullPath for most of the case. But if you want to get the path also in the case of the file name is relatively located then you can use the below generic method:

string GetPath(string filePath)
{
  return Path.GetDirectoryName(Path.GetFullPath(filePath))
}

For example:

GetPath("C:\Temp\Filename.txt") return "C:\Temp\"

GetPath("Filename.txt") return current working directory like "C:\Temp\"