[python] How to compare times in Python?

I see that date comparisons can be done and there's also datetime.timedelta(), but I'm struggling to find out how to check if the current time (datetime.datetime.now()) is earlier, later or the same than a specified time (e.g. 8am) regardless of the date.

Another way to do this without adding dependencies or using datetime is to simply do some math on the attributes of the time object. It has hours, minutes, seconds, milliseconds, and a timezone. For very simple comparisons, hours and minutes should be sufficient.

d = datetime.utcnow()
t = d.time()
print t.hour,t.minute,t.second

I don't recommend doing this unless you have an incredibly simple use-case. For anything requiring timezone awareness or awareness of dates, you should be using datetime.

Surprised I haven't seen this one liner here:

datetime.datetime.now().hour == 8

datetime have comparison capability

>>> import datetime
>>> import time
>>> a =  datetime.datetime.now()
>>> time.sleep(2.0)
>>> b =  datetime.datetime.now()
>>> print a < b
True
>>> print a == b
False

You can use the time() method of datetime objects to get the time of day, which you can use for comparison without taking the date into account:

>>> this_morning = datetime.datetime(2009, 12, 2, 9, 30)
>>> last_night = datetime.datetime(2009, 12, 1, 20, 0)
>>> this_morning.time() < last_night.time()
True

You Can Use Timedelta fuction for x time increase comparision.

>>> import datetime 

>>> now = datetime.datetime.now()
>>> after_10_min = now + datetime.timedelta(minutes = 10)
>>> now > after_10_min 

False

Just A combination of these answers this And Roger

You can compare datetime.datetime objects directly

E.g:

>>> a
datetime.datetime(2009, 12, 2, 10, 24, 34, 198130)
>>> b
datetime.datetime(2009, 12, 2, 10, 24, 36, 910128)
>>> a < b
True
>>> a > b
False
>>> a == a
True
>>> b == b
True
>>> 

Inspired by Roger Pate:

import datetime
def todayAt (hr, min=0, sec=0, micros=0):
   now = datetime.datetime.now()
   return now.replace(hour=hr, minute=min, second=sec, microsecond=micros)    

# Usage demo1:
print todayAt (17), todayAt (17, 15)

# Usage demo2:    
timeNow = datetime.datetime.now()
if timeNow < todayAt (13):
   print "Too Early"