Convert a timedelta to days hours and minutes

Question

I ve got a timedelta  I want the days  hours and minutes from that - either as a tuple or a dictionary    I m not fussed   I must have done this a dozen times in a dozen languages over the years but Python usually has a simple answer to everything so I thought I d ask here before busting out some nauseatingly simple  yet verbose  mathematics   Mr Fooz raises a good point   I m dealing with  listings   a bit like ebay listings  where each one has a duration  I m trying to find the time left by doing when added   duration - now  Am I right in saying that wouldn t account for DST  If not  what s the simplest way to add subtract an hour

User · Answer

I used the following   delta   timedelta   totalMinute  second   divmod delta seconds  60  hour  minute   divmod totalMinute  60  print f  hour h minute 02 m second 02 s

User · Answer

days  hours  minutes   td days  td seconds    3600  td seconds    60   60   As for DST  I think the best thing is to convert both datetime objects to seconds  This way the system calculates DST for you    gt  gt  gt  m13   datetime 2010  3  13  8  0  0     2010 March 13 8 00 AM  gt  gt  gt  m14   datetime 2010  3  14  8  0  0     DST starts on this day  in my time zone  gt  gt  gt  mktime m14 timetuple    - mktime m13 timetuple          difference in seconds 82800 0  gt  gt  gt    3600                                                  convert to hours 23 0

User · Answer

Here is a little function I put together to do this right down to microseconds  def tdToDict td datetime timedelta  - gt  dict      def   t t  n           if t  lt  n  return  t  0          v   t  n         return  t -   v   n   v       s  h      t td seconds  3600       s  m      t s  60           micS  milS      t td microseconds  1000       return             days   td days           hours   h           minutes   m           seconds   s           milliseconds   milS           microseconds   micS        Here is a version that returns a tuple    usage    d   h   m   s   mils   mics    tdTuple td  def tdTuple td datetime timedelta  - gt  tuple      def  t t  n           if t  lt  n  return  t  0          v   t  n         return  t -   v   n   v       s  h     t td seconds  3600       s  m     t s  60           mics  mils     t td microseconds  1000      return  td days  h  m  s  mics  mils

User · Answer

This is a bit more compact  you get the hours  minutes and seconds in two lines   days   td days hours  remainder   divmod td seconds  3600  minutes  seconds   divmod remainder  60    If you want to take into account fractions of a second seconds    td microseconds   1e6

User · Answer

If you have a datetime timedelta value td  td days already gives you the  days  you want  timedelta values keep fraction-of-day as seconds  not directly hours or minutes  so you ll indeed have to perform  nauseatingly simple mathematics   e g    def days hours minutes td       return td days  td seconds  3600   td seconds  60  60

User · Answer

I don t understand   days  hours  minutes   td days  td seconds    3600  td seconds    60   60   how about this  days  hours  minutes   td days  td seconds    3600  td seconds   3600   60 0   You get minutes and seconds of a minute as a float

User · Answer

timedeltas have a days and seconds attribute    you can convert them yourself with ease

User · Answer

I found the easiest way is using str timedelta   It will return a sting formatted like 3 days  21 06 40 001000  and you can parse hours and minutes using simple string operations or regular expression

[python] Convert a timedelta to days, hours and minutes

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