[ruby] How do I search within an array of hashes by hash values in ruby?

I have an array of hashes, @fathers.

a_father = { "father" => "Bob", "age" =>  40 }
@fathers << a_father
a_father = { "father" => "David", "age" =>  32 }
@fathers << a_father
a_father = { "father" => "Batman", "age" =>  50 }
@fathers << a_father 

How can I search this array and return an array of hashes for which a block returns true?

For example:

@fathers.some_method("age" > 35) #=> array containing the hashes of bob and batman

Thanks.

This question is related to ruby search hash arrays

The answer is


if your array looks like

array = [
 {:name => "Hitesh" , :age => 27 , :place => "xyz"} ,
 {:name => "John" , :age => 26 , :place => "xtz"} ,
 {:name => "Anil" , :age => 26 , :place => "xsz"} 
]

And you Want To know if some value is already present in your array. Use Find Method

array.find {|x| x[:name] == "Hitesh"}

This will return object if Hitesh is present in name otherwise return nil


(Adding to previous answers (hope that helps someone):)

Age is simpler but in case of string and with ignoring case:

  • Just to verify the presence:

@fathers.any? { |father| father[:name].casecmp("john") == 0 } should work for any case in start or anywhere in the string i.e. for "John", "john" or "JoHn" and so on.

  • To find first instance/index:

@fathers.find { |father| father[:name].casecmp("john") == 0 }

  • To select all such indices:

@fathers.select { |father| father[:name].casecmp("john") == 0 }


this will return first match

@fathers.detect {|f| f["age"] > 35 }

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