[ruby] Ruby - ignore "exit" in code

Consider this code:

class Bar   def initialize     puts 'Hi from class Bar.'     exit   end end   class Foo   def initialize     loop {       case $stdin.gets.chomp       when 'foo'         puts 'Hi from class Foo.'       when 'bar'         Bar.new       end     }   end end 

Can I ignore the exit in class Bar somehow?

It terminates my loop. I don't want that.

Note - the real code base is much larger and more complicated than that. But it boils down to this question whether I can ignore exit() or not.

One hackish way to define an exit method in context:

class Bar; def exit; end; end 

This works because exit in the initializer will be resolved as self.exit¹. In addition, this approach allows using the object after it has been created, as in: b = B.new.

But really, one shouldn't be doing this: don't have exit (or even puts) there to begin with.

(And why is there an "infinite" loop and/or user input in an intiailizer? This entire problem is primarily the result of poorly structured code.)

¹ Remember Kernel#exit is only a method. Since Kernel is included in every Object, then it's merely the case that exit normally resolves to Object#exit. However, this can be changed by introducing an overridden method as shown - nothing fancy.