Ruby - ignore exit in code

Question

Consider this code   class Bar   def initialize     puts  Hi from class Bar       exit   end end   class Foo   def initialize     loop         case  stdin gets chomp       when  foo          puts  Hi from class Foo         when  bar          Bar new       end         end end   Can I ignore the exit in class Bar somehow   It terminates my loop  I don t want that   Note - the real code base is much larger and more complicated than that  But it boils down to this question whether I can ignore exit   or not

User · Accepted Answer

loop     begin     Bar new   rescue SystemExit     p          lt SystemExit  exit gt    end     This will print   lt SystemExit  exit gt  in an infinite loop  without ever exiting

User · Answer

One hackish way to define an exit method in context   class Bar  def exit  end  end   This works because exit in the initializer will be resolved as self exit1  In addition  this approach allows using the object after it has been created  as in  b   B new   But really  one shouldn t be doing this  don t have exit  or even puts  there to begin with    And why is there an  infinite  loop and or user input in an intiailizer  This entire problem is primarily the result of poorly structured code      1 Remember Kernel exit is only a method  Since Kernel is included in every Object  then it s merely the case that exit normally resolves to Object exit  However  this can be changed by introducing an overridden method as shown - nothing fancy

[ruby] Ruby - ignore "exit" in code

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