How to exit a function in bash

Question

How would you exit out of a function if a condition is true without killing the whole script  just return back to before you called the function   Example    Start script Do scripty stuff here Ok now lets call FUNCT FUNCT Here is A to come back to  function FUNCT     if   blah is false    then     exit the function and go up to A   else     keep running the function   fi

User · Answer

Use return operator   function FUNCT     if   blah is false    then     return 1   or return 0  or even you can omit the argument    else     keep running the function   fi

User · Answer

If you want to return from an outer function with an error without exiting you can use this trick   do-something-complex         Using  return  here would only return from  fail   not from  do-something-complex       Using  exit  would close the entire shell      So we  ab use a different feature       fail            fail fast   1         nested-func           try-this    fail  This didn t work        try-that    fail  That didn t work        nested-func     Trying it out     do-something-complex try-this  command not found bash    fail fast  This didn t work   This has the added benefit drawback that you can optionally turn off this feature    fail fast x do-something-complex   Note that this causes the outermost function to return 1

User · Answer

Use  return  n   From help return  return  return  n  Return from a shell function   Causes a function or sourced script to exit with the return value specified by N   If N is omitted  the return status is that of the last command executed within the function or script   Exit Status  Returns N  or failure if the shell is not executing a function or script

[bash] How to exit a function in bash

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